Rohan and Vikas decide to play a game which involves flipping of a coin. In a round, Rohan gives rs 5 to
Vikas if the coin shows tail whereas Vikas gives rs 2 to Rohan if the coin shows head. They start the game
with a biased coin in which head is likely to occur 50% more times than tail If initially, each of the two has
50, then what is the probability that at the end of 10th round Vikas would have at least 80 rupees in all?
@hari_bang said:If you have 5 coins of 1 rupee; 4 coins of 2 rupee and 2 coins of 5 rupee. Then how many combination of coins are possible. Ans is-89approah anyone....
6.5.3 - 1 = 89
@hari_bang said:If you have 5 coins of 1 rupee; 4 coins of 2 rupee and 2 coins of 5 rupee. Then how many combination of coins are possible. Ans is-89approah anyone....
combination of what
@hedonistajay said:combination of what
any combination
lik..
1 combination,
2 combination...
any no.of coin and any typ...:)
@Gaul said:On a partly cloudy day, Derek decides to walk back from work. When it is sunny, he walks at a speed of s miles/hr (s is an integer) and when it gets cloudy, he increases his speed to (s + 1) miles/hr. If his average speed for the entire distance is 2.8 miles/hr, what fraction of the total distance did he cover while the sun was shining on him?
is ans 1/7
@sujamait said:@hari_bang said:If you have 5 coins of 1 rupee; 4 coins of 2 rupee and 2 coins of 5 rupee. Then how many combination of coins are possible. Ans is-89approah anyone.... 6.5.3 - 1 = 89
hw?
is dis method???
for dis type of ques?
76% of 76% of 76% of 76% of..................................of 75 
@Gaul said:how?pls explain
well see if the avg speed is 2.8 .. and the speed is s and s+1 as avg has to lie btw s and s+1 s has to be 2 so s+1 becomes 3 and avg is 2.8 so the ratio of time will be 1/4 so the distance travlled with 2 = 2*x
distance travlled with 3 will be = 3*4x
so ratio becomes 2/14 = 1/7
distance travlled with 3 will be = 3*4x
so ratio becomes 2/14 = 1/7
What will be the probability of having 4 selected cards ace, king, queen, and jack of exactly one suit?
@hari_bang said:What will be the probability of having 4 selected cards ace, king, queen, and jack of exactly one suit?
My ans is 256/270725
@sujamait said:Rohan and Vikas decide to play a game which involves flipping of a coin. In a round, Rohan gives rs 5 toVikas if the coin shows tail whereas Vikas gives rs 2 to Rohan if the coin shows head. They start the gamewith a biased coin in which head is likely to occur 50% more times than tail If initially, each of the two has50, then what is the probability that at the end of 10th round Vikas would have at least 80 rupees in all?
is it 0?
@hari_bang said:My ans is 256/270725.
shudnt it be 4/270725 ... we can select ace, king, queen, and jack of exactly one suit ... in 4 ways ..
@hedonistajay said:
shudnt it be 4/270725 ... we can select ace, king, queen, and jack of exactly one suit ... in 4 ways ..
select of which of these cards should also matter i guess...
so i think we should multiply this with 4!
@hari_bang said:What will be the probability of having 4 selected cards ace, king, queen, and jack of exactly one suit?
i reckon since the question asks for "selection" it should be = 1/ (52 C 4) = 1/270725
kindly post the solution asap..
@hari_bang said:What will be the probability of having 4 selected cards ace, king, queen, and jack of exactly one suit?
4/ (52 C 4)
@sujamait said:Rohan and Vikas decide to play a game which involves flipping of a coin. In a round, Rohan gives rs 5 toVikas if the coin shows tail whereas Vikas gives rs 2 to Rohan if the coin shows head. They start the gamewith a biased coin in which head is likely to occur 50% more times than tail If initially, each of the two has 50, then what is the probability that at the end of 10th round Vikas would have at least 80 rupees in all?
56/(2^10) = 56/1024 = 7/128....?