A milkman claims to sell milk at the cost price but actually mixes water and milk in the ratio 1 : 4. By selling this product, his revenue is Rs. 600 every day. The amount of milk remains the same every day. One day his revenue is Rs. 560 by selling the product at its normal fixed price of Rs. 10 per litre. What is the proportion of water in milk on that day ?a) 20% b) 14.28% c) 15% d) 12% e) 16.66%
he sells 5 lts at cost of 4 lts, thus making profit of 25%
hence cost of 600 is 480.
so % of water in resultant mixture=(560-480)/560=14.28%
note: proportion in milk I am considering the resultant milk mixture.
Michael went from city A to city B,driving more than 100 miles.When he started from city A,the first milestone reads N km and before reaching city B,the last milestone read 1 km.While driving on the road,Michael reached a milestone for which the sum of the numbers on all type of milestones before it was equal to the sum of the numbers on all milestone after it. What can be the minimum distance of that milestone from the city B? a) 288 b) 1189 c) 1681 d) 204
A milkman claims to sell milk at the cost price but actually mixes water and milk in the ratio 1 : 4. By selling this product, his revenue is Rs. 600 every day. The amount of milk remains the same every day. One day his revenue is Rs. 560 by selling the product at its normal fixed price of Rs. 10 per litre. What is the proportion of water in milk on that day ?a) 20%b) 14.28%c) 15%d) 12%e) 16.66%
Michael went from city A to city B,driving more than 100 miles.When he started from city A,the first milestone reads N km and before reaching city B,the last milestone read 1 km.While driving on the road,Michael reached a milestone for which the sum of the numbers on all type of milestones before it was equal to the sum of the numbers on all milestone after it. What can be the minimum distance of that milestone from the city B?a) 288b) 1189c) 1681d) 204
Let the milestone be at 'm' km from the point A
N(N+1)/2 - m(m+1)/2 = m(m-1)/2
=> m^2 = N(N+1)/2
Then went through the options and checked for each value
Michael went from city A to city B,driving more than 100 miles.When he started from city A,the first milestone reads N km and before reaching city B,the last milestone read 1 km.While driving on the road,Michael reached a milestone for which the sum of the numbers on all type of milestones before it was equal to the sum of the numbers on all milestone after it. What can be the minimum distance of that milestone from the city B?a) 288b) 1189c) 1681d) 204
this can only happen when there are few milestones before the said milestone and more after it...we start with the extreme case....1 milestone at the left and milestones with an interval of 1 between them till 1 e.g: 6 ...X.....3 2 1
so we start with the min option and check whether thats possible
204 closest to N(N+1)/2 => N(N+1) = 408 , so n can be 20, and the remaining milestone needed at left is 420-408 = 12 but which is already there so cant be possible , next option n=21, 462 - 408 = 54 which more than 21 so can be possible
so the case can be A......408(N).............54..............22(the said milestone)....21..20....19...and so on till 1.....B
408+54 = 21+20+19+....1 = 462
also 1 mile = 1.6 kms => 100 miles means the distance has to be more than 160 kms which would be in every case.....
i believe we can fit every case in it ...just a thought 😃
whats the OA considering that the logic might be flawed :)
Let the milestone be at 'm' km from the point A N(N+1)/2 - m(m+1)/2 = m(m-1)/2=> m^2 = N(N+1)/2Then went through the options and checked for each valueThe value 204 satisfies the equationNeeded a lot of time for this Please let me know if there is a better method
Bhai sorry to say that i dont have the OA I was just looking for a convincing approach(I also reached up to m^2 = N(N+1)/2) one more thing is that you have found m=204, which is distance from A ,but in question it has been asked distance from B
Michael went from city A to city B,driving more than 100 miles.When he started from city A,the first milestone reads N km and before reaching city B,the last milestone read 1 km.While driving on the road,Michael reached a milestone for which the sum of the numbers on all type of milestones before it was equal to the sum of the numbers on all milestone after it. What can be the minimum distance of that milestone from the city B?a) 288b) 1189c) 1681d) 204
Let N be the reading of the first milestone. and X be the reading of the required milestone
Acc to the question.
N(N+1)/2 - X(X+1)/2= X(X-1)/2
=> N(N+1)/2 = X^2
minimum value of N for which its summation gives a square number.
Michael went from city A to city B,driving more than 100 miles.When he started from city A,the first milestone reads N km and before reaching city B,the last milestone read 1 km.While driving on the road,Michael reached a milestone for which the sum of the numbers on all type of milestones before it was equal to the sum of the numbers on all milestone after it. What can be the minimum distance of that milestone from the city B?a) 288b) 1189c) 1681d) 204
d) 204
N(N+1)/2 - n(n+1)/2 = n(n+1)/2 - n N(N+1)/2 = n(n+1) - n N(N+1) = 2n^2 from options 2*204^2 = 83232 = 288*289
Guys Simple interest que:-Que Mahajan landed out Rs 9 on condition that the loan is payable in 10 months by 10 equal installments of Rs 1.Find the rate of interest......?Please tell me where I am going wrong:-I have taken the amount to be 10 as that is what he will get in 10 installments....now 10=9(1+R.10/1200)Is this approach not correct?
Guys Simple interest que:-Que Mahajan landed out Rs 9 on condition that the loan is payable in 10 months by 10 equal installments of Rs 1.Find the rate of interest......?Please tell me where I am going wrong:-I have taken the amount to be 10 as that is what he will get in 10 installments....now 10=9(1+R.10/1200)Is this approach not correct?
26.64% per year....
let interest rate be r% per month total interest paid is 1 rupee in 10 months which is equal to... 9.r/100 + 8.r/100 + 7.r/100 + ...... + r/100 45.r/100 = 1 r = 2.22 per month
Q find the least number of complete years in which a sum of money put out at 25% C.I will be more than double itself?One query why cant we use RT=72 and get the value of T here?
Q find the least number of complete years in which a sum of money put out at 25% C.I will be more than double itself?One query why cant we use RT=72 and get the value of T here?
Q find the least number of complete years in which a sum of money put out at 25% C.I will be more than double itself?One query why cant we use RT=72 and get the value of T here?
