Official Quant thread for CAT 2013

@soumitrabengeri said:
Could you explain the second one? 1st and 3rd samjha
2nd answer 1295 aayega shaayad.


@paridhi11890 said:
Please tell the approach u ppl have used...
is 1295 correct?
@incognitos said:
is 1295 correct?
Yes.
@paridhi11890 said:
Please solve the ques attached...
ďťż
[1] 8RNCC
[2] 1295
[3] Go by options. When we move right, in place of 9, 8 will be one of the character. So, not a proper word.
Hence, option with both left would be an answer.
@soumitrabengeri said:
Could you explain the second one? 1st and 3rd samjha
@paridhi11890 said:
Yes.
36*36-1
36 is the number of ways a letter on the second wheel can be coded on innerwheel or outer wheel...after that all the patterns repeat...36*36 includes that one way in which the given text is not coded(unchanged)...so subtract that one way.
@vijay_chandola said:
[1] 8RNCC[2] 1295[3] Go by options. When we move right, in place of 9, 8 will be one of the character. So, not a proper word.Hence, option with both left would be an answer.
1. 4 is the answer.. Rest all are correct :thumbsup:
Kaise kiya?
@paridhi11890 said:
Please tell the approach u ppl have used...
I have already explained
@paridhi11890 said:
1. 4 is the answer.. Rest all are correct
Kaise kiya?
typo :embarrassed:
option 4th hi h answer.
move the inner wheel two place right, A would be replaced by 8 (character that is two places left)
Similar approach for other characters.
@soumitrabengeri said:
I have already explained
Just checked now... Seems ur post got lost in the between :p
anyways thanks :)
@paridhi11890
i am not even to able to understand the cryptogram stuff...(forget abt solving)

how do we read it? some1 plz explain

Guys soln on this one .........please tell the approach as well.........

@bhatkushal Original expenditure per day be E

Average = E/42

new average,
E' = E + 31

E'/55 = E/42 - 3 => E/42 - E/55 = 3+31/55 = 196/55

=> E = 196/55*42*55/13 = 633.23
@bhatkushal
let the expense per day per person = x
now, the expenses per day = 42x

aftre the admission, expenses = 42x+31 = 55*(x-3)
==> 42x+31 = 55x - 165
==>196 = 13x ==>x = 196/13
==>original exp of mess = 42x = 42*196/13 = 633.23

is this correct...?
@shadowwarrior said:
@bhatkushallet the expense per day per person = xnow, the expenses per day = 42xaftre the admission, expenses = 42x+31 = 55*(x-3)==> 42x+31 = 55x - 165==>196 = 13x ==>x = 196/13==>original exp of mess = 42x = 42*196/13 = 633.23is this correct...?
correct

guys try doing it without the options and please do share the approach.......

@tmohan02 said:
Karan sells a chair at a loss of 10%. If he had sold at a profit of 5%, he would have earned Rs. 75. What is the cost price of the chair??.plz give explanation......
complete Q ?
@nole said:
one side of a right angled triangle is 8 cm.What is the length of the hypotenuse if the area of the traingle is 24 sq cm. my doubt is if lets say it is given one side is 80 cm then how to find which side is it ?
1/2*8*b = 24
b=6
hyp=10


@maneeshp what was the approach yaar even I have the same feeling.............
@bhatkushal said:
guys try doing it without the options and please do share the approach.......
This is wierd...
if the conditions are true
then

x+y+z= 150

x+y/2 + z/4 = 150

This can satisfy only if all coins are Re 1 Coins...
@bhatkushal said:
guys try doing it without the options and please do share the approach.......
i will also go with 0....

i twas stupid of me to even think of putting pen/pencil on the paper.......
@tmohan02 said:
Karan sells a chair at a loss of 10%. If he had sold at a profit of 5%, he would have earned Rs. 75. What is the cost price of the chair??.plz give explanation......
5% of cost price =75
100% of cost price=1500