Option 2 if a
If a>b, then none of these.
@IIM-A2013 said:if a and b are positive integers then หลก2 always lies between :1 a and b2 a/b and (a+2b)/(a+b)3 (a+b)/(a-b) and ab4 ab/(a+b) and (a-b)/ab
2?
@sujamait said:anyone ?In the sequence 1,9,7,7,4,7,5,3,9,4,1, โฌล every digit from the fifth on is the sum of the preceding 4 digits mod 10.Does one of the following set ever occur in the sequence?a) 1,2,3,4 b) 3,2,6,9 c) 0,1,9,8 d) 7,9,5,3
anyone ?
b...coz found out that 6 was not occuring in the series upto the point where i found.....may be im wrong........
For what value of n will the sum ( 2^1096+2^2248+2^2n ) be perfect square?
A 2008
B 2010
C 2012
D none of these....post the method too puys :)
A 2008
B 2010
C 2012
D none of these....post the method too puys :)
hi puys I am new to PagalGuy....looking forward to learn a lot from you....3:)
@ankurkapruwan said:For what value of n will the sum ( 2^1096+2^2248+2^2n ) be perfect square?A 2008B 2010C 2012D none of these....post the method too puys
None of these?
Going by the option....perfect squares can never end with the unit digit 2,3,7,8
for 2008--2n = 2^4016--> 6 unit digit
2010 ---2^4020 ---> 6 unit digit
2012-----2^4024----6 unit digit...
also 2^1096+2^2248 = 6+6 (unit digits)
so all three options on adding....gives 8 as unit digit..whch can never happen in perfect square case.
@milestogo3 :I dont know the exact answer....but I dont think your answer is amiguous in any way.....thanks amigo
@ankurkapruwan said:For what value of n will the sum ( 2^1096+2^2248+2^2n ) be perfect square?A 2008B 2010C 2012D none of these....post the method too puys
(2^6)(2^10)^odd + (2^8)(2^10)^even + 2^2n = xxx6 + xxx6 + 2^2n.
so going by options now. -> xxx2 + 2^4016 = 2^6*24 + xxx2 = 8 (no sq ends in 8).
xxx2 + 2^4020 = xxx2 + xxx76 = 8 (no sq ends in 8).
xxx2 + 2^4024 = xxx2 + 2^4*76 = xxx2 + xxx6 = 8 (no sq ends in 8).
hence, has to be NOT.
so going by options now. -> xxx2 + 2^4016 = 2^6*24 + xxx2 = 8 (no sq ends in 8).
xxx2 + 2^4020 = xxx2 + xxx76 = 8 (no sq ends in 8).
xxx2 + 2^4024 = xxx2 + 2^4*76 = xxx2 + xxx6 = 8 (no sq ends in 8).
hence, has to be NOT.
@ankurkapruwan said:For what value of n will the sum ( 2^1096+2^2248+2^2n ) be perfect square?A 2008B 2010C 2012D none of these....post the method too puys
My take:none
4^548 + 4^1124 + 4^n
as if it has to be square,the power of one among the three terms should have been odd (observation from (a+b)^2)
koi plz bata do Number System ki theory k liye kya prefer kiya jaye . I want to strong my Number System . thanks in advance .......:)
@Neel453 said:koi plz bata do Number System ki theory k liye kya prefer kiya jaye . I want to strong my Number System . thanks in advance .......
download total godha's number system pdf..
@sundip said:57.8 ??
can u pls tel me hw u got with the 2 stms..
i thought the ans was E..
side opp to AD is just DC rite... pls correct me if i am wrong