Q1
@vbhvgupta said:Q1
21
5 refuse to sit up and 8 to sit down....
so 8 will have to sit up and 5 down...
13 done...
remaining 7...
two can sit down and 5 up...
how many ways can we select 2 from 7 is the answer...
i.e. 7C2 = 21 = 7C5
@vbhvgupta said:C explain buddy.....
total 7 can sit on lower deck
Out of 20, 5 will sit on lower deck and 8 will sit on upper deck
Now we hv to look for only remaining 7 coz position of remaining 13 is fixed. ( 5 lower and 8 upper)
for lower deck we hv to choose 2 more. that can be done in
7C2 ways= 21 ways
@rahulnema said:11 mines are present in the figure..E, G, I, K, L, M, P are not mines.. right ??
Sorry check again...
@vbhvgupta said:Q1
Total 20
-----------
5 refuse to sit on upper deck and 8 refuse to sit on lower deck
So send first 5 five to lower deck and other 8 to upper deck
---
Remaining 20-13=7
Upper deck(Max 13) : 8, vacant(5)
Lower deck(Max 7) : 5, vacant(2)
---
So we have 7 persons and 5upper+2lower vacant seats, Ways=7!/5!*2!= 7*6/2=21?
-----------
5 refuse to sit on upper deck and 8 refuse to sit on lower deck
So send first 5 five to lower deck and other 8 to upper deck
---
Remaining 20-13=7
Upper deck(Max 13) : 8, vacant(5)
Lower deck(Max 7) : 5, vacant(2)
---
So we have 7 persons and 5upper+2lower vacant seats, Ways=7!/5!*2!= 7*6/2=21?
@Aman.Malhotra said:If x and y are real numbers, then the minimum value of x^2 + 4xy + 6y^2 - 4y + 4 is
(x+2y)^2+2(y-1)^2+2
Min is 2
@floamiya said:Find The Mines : There are how many mines in the figure and at which place.Digits are indicating the number of mines in adjacent squaresM B A - Maths By Amiyawww.facebook.com/MathsByAmiya
A,B,D,F,G,I,N,O,Q,R are the mines...
DO you have maths in U: NUMBER SYSTEM
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Mod Note: This thread is for questions and quant discussions only. Promote your pages elsewhere on threads meant for that.
Try this :
DO you Have Maths in your blood :
N is a natural number such that (N-1) is a perfect square and (N+1) is a perfect cube.
Then there are(is) how many values on N be possible...???
Then there are(is) how many values on N be possible...???
{SNIPPED}
Mod Note: This thread is for questions and quant discussions only. Promote your pages elsewhere on threads meant for that.
@floamiya said:DO you have maths in U: NUMBER SYSTEMTry this :DO you Have Maths in your blood : N is a natural number such that (N-1) is a perfect square and (N+1) is a perfect cube.Then there are(is) how many values on N be possible...???www.facebook.com/4753263525194...www.facebook.com/MathsByAmiya
1 i.e. 26??
@dream_IIMA said:1) A three digit number is eleven times the two digit number formed by using the hundreds and the units digit of three digit number respectively. in the tens and units place of the two digit number. if the difference between the digit in tens place and the digit in hundred place is 1 then what is the digit in the unit place???A 2 B 3 C 4D 12) in addition to the above data if the difference between the digit in tens place and that in the units place of three digit no. is also 1 then what is the number??A 121B 321C 212D 231
abc=11*ac
c+10b+100a=11(c+10a)
a+c=b
b-a=1
b-a=c
c=1
b-c=1
b=2
a=1
Number is 121
@floamiya said:DO you have maths in U: NUMBER SYSTEMTry this :DO you Have Maths in your blood : N is a natural number such that (N-1) is a perfect square and (N+1) is a perfect cube.Then there are(is) how many values on N be possible...???www.facebook.com/4753263525194...www.facebook.com/MathsByAmiya
26?
@floamiya said:DO you have maths in U: NUMBER SYSTEMTry this :DO you Have Maths in your blood : N is a natural number such that (N-1) is a perfect square and (N+1) is a perfect cube.
Only 1 number possible i.e. 26?
Q2
@vbhvgupta 10 %
base 100 le kr min and max i.e 60 + 80 =140 so 40 are extra which play both the games now 70 people who play football have to be in that base 100 too. 40 are definitely playing 2 games already so 70+40 =110 means 10 % are playing all the three games definitely :D