Official Quant thread for CAT 2013

@gs4890 said:
There are 30 number (1,2,3 €Ś30). In how many ways three of them can be selected such that sum of the selected numbers is multiple of three.Could solve this Q during CAT time. no more Approach plz !
Out of the 30 numbers

10 are of type = 3k , 10 of 3k + 1, 10 of 3k + 2

Now, how can we get the sum to be a multiple of 3 ?
Case 1: I take one number each from each of the group => 10C1*10C1*10C1

Case 2: I take all three from any one group => 3C2*(10C3)

total ways = (10C1)^3 + 3*(10C3) = 1000 + 360 = 1360 ?

Hey puys..!! I couldn't find the proper thread to ask this question..please tell me which coaching institute is better...Bjyu or Tathagat..or TIME..really confused..!!

@akanksha0411 i would suggest to either go for CL or TIME.These two are the best mentors for the CAT.They have been in this field over the long years and have produced great results.
So you can go and join any one of them. But make sure you do not fully rely only on them.
Remember CAT or any other entrance is a totally self excellence. You should only use them as your guide and nothing more. Baaki it's your call. ATB..

a train has to travel the distance between aurangabad and daulatabad,equal to 20 km at a constant speed.It travelled half the way with the specified speed and stopped for three minutes,to arrive at daulatabad on time,it had to increase its speed by 10 km/h for the rest of the way.next time the train stopped for 5 minutes.By what speed must it increase its speed for the remaining half of the distance to arrive at daulatabad as per schedule.


m getting answer as 20 km/h in book it is given 16km/h.
ďťż
@nole said:
a train has to travel the distance between aurangabad and daulatabad,equal to 20 km at a constant speed.It travelled half the way with the specified speed and stopped for three minutes,to arrive at daulatabad on time,it had to increase its speed by 10 km/h for the rest of the way.next time the train stopped for 5 minutes.By what speed must it increase its speed for the remaining half of the distance to arrive at daulatabad as per schedule.
is it 20kmph???
@pari19O1 m getting as 20 km/h in book it is given it is given 16km/h.that's why i posted the question here.most probably 20km/h should be correct.
@nole said:
a train has to travel the distance between aurangabad and daulatabad,equal to 20 km at a constant speed.It travelled half the way with the specified speed and stopped for three minutes,to arrive at daulatabad on time,it had to increase its speed by 10 km/h for the rest of the way.next time the train stopped for 5 minutes.By what speed must it increase its speed for the remaining half of the distance to arrive at daulatabad as per schedule.m getting answer as 20 km/h in book it is given 16km/h.
You're right. I think it should be 20kmph.

10/x + 0.05 + 10/(x+10) = 20/x
10/x - 10/(x+10) = 0.05
10/(x(x+10)) = 0.005
x(x+10) = 2000
x = 40

10/40 + 5/60 + 10/(y) = 20/40
10/y = 10/40 - 5/60
10/y = 20/120
y = 60 kmph

@nole said:
a train has to travel the distance between aurangabad and daulatabad,equal to 20 km at a constant speed.It travelled half the way with the specified speed and stopped for three minutes,to arrive at daulatabad on time,it had to increase its speed by 10 km/h for the rest of the way.next time the train stopped for 5 minutes.By what speed must it increase its speed for the remaining half of the distance to arrive at daulatabad as per schedule.m getting answer as 20 km/h in book it is given 16km/h.
10/v+3/60+10/(v+10)=20/v
=> v=40

10/40+5/60+10/(40+x)=20/40
=> x=20 km
@antodaya said:
Q Š There are 20 guavas,10apples,5chikos.How many can u select 25 fruits.?*show approach no answer*
ans -> 51

solution -
i did it using counting...

with 20 guavas there can be 6 cases(5a,0c) to (0a,5c)
similarly with 19,18,17,16,15 g 6 cases
with 14 g 5 cases
with 13 g 4 cases
with 12 g 3 cases
with 11 g 2 cases
with 10 g 1 case

total 6*6 + 5+4+3+2+1 = 51??

a –– If the data in statement (1) alone is sufficient to answer the question;

b –– If the data in statement (2) alone is sufficient to answer the question;

c –– If the data in both the statements together are needed to answer the question;

d –– If either statement (1) alone or statement (2) alone is sufficient to answer the question;

A number is picked randomly from a given set of numbers. What is the probability that it is divisible by 3?

Statement 1: The set contains 10 consecutive integers

Statement 2: The first number of the set is divisible by 3
@vbhvgupta said:
a ––If the data in statement (1) alone is sufficient to answer the question;b ––If the data in statement (2) alone is sufficient to answer the question;c ––If the data in both the statements together are needed to answer the question;d ––If either statement (1) alone or statement (2) alone is sufficient to answer the question;A number is picked randomly from a given set of numbers. What is the probability that it is divisible by 3?Statement 1:The set contains 10 consecutive integersStatement 2:The first number of the set is divisible by 3
c?

From 1: there are either 3 or 4 multiples of 3
From 1 and 2: there are 4 multiples of 3
So it can be answered by using both the statements together.
@vbhvgupta said:
a ––If the data in statement (1) alone is sufficient to answer the question;b ––If the data in statement (2) alone is sufficient to answer the question;c ––If the data in both the statements together are needed to answer the question;d ––If either statement (1) alone or statement (2) alone is sufficient to answer the question;A number is picked randomly from a given set of numbers. What is the probability that it is divisible by 3?Statement 1:The set contains 10 consecutive integersStatement 2:The first number of the set is divisible by 3
using both.

a, b and c are three numbers selected from a set containing ten numbers 0 to 9. Is (a + b + c) a multiple of 9?

Statement 1: Three digit number abc is a multiple of 9

Statement 2: (a ´ b) + c is a multiple of 9

a, b and c are prime numbers. What is the value of a ´ b ´ c?

Statement 1: a + b + c = 12

Statement 2: 6300 is divisible by a ´ b ´ c and 1890 is divisible by b ´ c
@vbhvgupta said:
a, b and c are three numbers selected from a set containing ten numbers 0 to 9. Is (a + b + c) a multiple of 9?Statement 1:Three digit number abc is a multiple of 9Statement 2:(a ´ b) + c is a multiple of 9
Is that (a*b)+c ? (The highlighted part)
@adwaitjw said:
Is that
(a*b)+c
? (The highlighted part)
Yes.
@vbhvgupta said:
a, b and c are three numbers selected from a set containing ten numbers 0 to 9. Is (a + b + c) a multiple of 9?Statement 1:Three digit number abc is a multiple of 9Statement 2:(a ´ b) + c is a multiple of 9
a ––The data in statement (1) alone is sufficient to answer the question?

statement 1 is sufficient.
statement 2:
145 => 1*4 + 5 = 9 and 1+4+5 = 10
009 => 0*0 + 9 = 9 and 0+0+9 = 9

@vbhvgupta said:
a, b and c are three numbers selected from a set containing ten numbers 0 to 9. Is (a + b + c) a multiple of 9?Statement 1:Three digit number abc is a multiple of 9Statement 2:(a ´ b) + c is a multiple of 9
D??

forgot 009...matlab mera galat ho gaya...
:(
only using statement 1 hai phir iska answer...

nice @grkkrg :thumbsup:


@vbhvgupta said:
a, b and c are prime numbers. What is the value of a ´ b ´ c?Statement 1:a + b + c = 12Statement 2:6300 is divisible by a ´ b ´ c and 1890 is divisible by b ´ c
E- cannot be answered using both together...??
@grkkrg said:
a €“ €“The data in statement (1) alone is sufficient to answer the question?statement 1 is sufficient.statement 2: 145 => 1*4 + 5 = 9 and 1+4+5 = 10009 => 0*0 + 9 = 9 and 0+0+9 = 9
But how can we be sure that two no.s can be same or not?
@adwaitjw said:
But how can we be sure that two no.s can be same or not?
It's not mentioned in the question that they have to be distinct. I may be wrong here though.