@19rsb said:6800?
, approach plz, approach plz
If "3 + 2i" is one of the root of x^2 + bx + 10 = 2i ; Then find the another root and value of "b"
@IIM-A2013 said:The weight of an iron bucket increases by 33.33% when filled with water to 50% of its capacity. Which of these may be 50% of the weight of the bucket when it is filled with water( assume the weight of bucket and its capacity in kg to be integers?..plz explain in detail with steps.a 7 kg b 5 kg c 6 kg d 8 kg
5?
@rkshtsurana said:If "3 + 2i" is one of the root of x^2 + bx + 10 = 2i ; Then find the another root and value of "b"
other root=(34/13)-2i
b=-73/13?
b=-73/13?
@sonamaries7 said:There are 2 buses running from terminuses A nd B, each bus making 5 round trips in a day with no stops in btw.These buses ply on the same route with diff but uniform speeds. Each morning the buses start at 7am from their respective terminuses. They meet for teh 1st time at a dist of 7km from A and. Thier next meeting takes place at a dist of 4km from B, while travelling in opp directions.Assuming that the time taken by the buses at the terminuses is negligible and the cost of running a bus is Rs20/km.Find the daily cost of running the buses.3200400064006800none@YouMadFellow
6800...
D = total distance between A & B
7/(D-7) = (D+4)/(2D-4)
Solving - D = 17 kms
Total Distance traveled by both buses together = 20 D = 340 Kms
Cost = 20 x 340 = 6800 Rs...
@sonamaries7 said:, approach plz
let d be the distance between the two
then ratio of speeds of buses=7/d-7=d-3/d+3
from above d=17
then,cost =17*5*4*20=6800
then ratio of speeds of buses=7/d-7=d-3/d+3
from above d=17
then,cost =17*5*4*20=6800
@IIM-A2013
Assuming weight of bucket = b, capacity of bucket = w (b and w are integers)
So, b + w/2 = 4b/3 => w = 2b/3 => b is divisible by 3
Taking b = 3x and w = 2x (x is an integer)
Take y = 50% of Weight of bucket when it is filled to capacity
= 1/2 * (b + w)
= (1/2) * (3x + 2x)
= (1/2) * 5x
= 5x/2
=> x = 2y/5. For x to be an integer, y has to be divisible by 5 => (b) 5kg
Assuming weight of bucket = b, capacity of bucket = w (b and w are integers)
So, b + w/2 = 4b/3 => w = 2b/3 => b is divisible by 3
Taking b = 3x and w = 2x (x is an integer)
Take y = 50% of Weight of bucket when it is filled to capacity
= 1/2 * (b + w)
= (1/2) * (3x + 2x)
= (1/2) * 5x
= 5x/2
=> x = 2y/5. For x to be an integer, y has to be divisible by 5 => (b) 5kg
@rkshtsurana said:If "3 + 2i" is one of the root of x^2 + bx + 10 = 2i ; Then find the another root and value of "b"
if r1 and r2 are the roots then
r1*r2 = 10-2i
=>(3+2i)*r2 = (10 - 2i)
=>r2 = (10 - 2i)/(3 + 2i)
=>r2 = (10 - 2i)*(3 - 2i)/(9 + 4) = (30 - 6i - 20i - 4)/13 = (2 - 2i)
=>r1 + r2 = (3 + 2i) + (2 - 2i) = 5
=>b = -(r1 + r2) = -5
ATDH.
Guys solution please along with the answer....
In a circle RP and RQ are two tangents to a circle of radius 6 cm at P and Q,respectively. Find dis between the center of d circle and the in centre of triangle RPQ:-
a)6
b)9
c)6 sqrt2
d)3 sqrt3
R is a rectangular floor completely covered with square tiles of identical size.Tiles are of red and blue colour .The tiles at the edge of the floor are red and the tiles in interior are blue.There are twice as many blue tiles as red tiles. What is the num of tiles on any of the edges of R?
@VINAYAK108 answer is 12 min which u have got after making a smal mistake.I wanted to like the next post to tell that u got the right answer.By mistake liked the wrong one :)
In how many ways can 2013^2 be written as a product of 2 distinct integers?
@aimiift2012 said:In how many ways can 2013^2 be written as a product of 2 distinct integers?
2013^2 = 3^2*11^2*61^2
Number of factors = 27 => Number of ways to write as product of 2 distinct integers = 13
But negative integers are also possible => 26 ways ?
@bhatkushal said:Guys solution please along with the answer....In a circle RP and RQ are two tangents to a circle of radius 6 cm at P and Q,respectively. Find dis between the center of d circle and the in centre of triangle RPQ:-a)6b)9c)6 sqrt2d)3 sqrt3
@rkshtsurana said:If "3 + 2i" is one of the root of x^2 + bx + 10 = 2i ; Then find the another root and value of "b"
sum= -b
product-(10-2i)
Hence,other root= 2-2i
and, b=-5
@bhatkushal said:Guys solution please along with the answer....In a circle RP and RQ are two tangents to a circle of radius 6 cm at P and Q,respectively. Find dis between the center of d circle and the in centre of triangle RPQ:-a)6b)9c)6 sqrt2d)3 sqrt3
a)6
Incentre lies on the circle hence distance is equal to the radius
Incentre lies on the circle hence distance is equal to the radius
@bhatkushal said:R is a rectangular floor completely covered with square tiles of identical size.Tiles are of red and blue colour .The tiles at the edge of the floor are red and the tiles in interior are blue.There are twice as many blue tiles as red tiles. What is the num of tiles on any of the edges of R?
12 and 5
2m+2n-4=(m-2)(n-2)
2m+2n-4=(m-2)(n-2)
@deedeedudu said:a)6Incentre lies on the circle hence distance is equal to the radius
Can you please specify the reason for this..........
I mean whu will iy lie on the circle..........
@anytomdickandhary said:if r1 and r2 are the roots thenr1*r2 = 10-2i=>(3+2i)*r2 = (10 - 2i)=>r2 = (10 - 2i)/(3 + 2i)=>r2 = (10 - 2i)*(3 - 2i)/(9 + 4) = (30 - 6i - 20i - 4)/13 = (1 - i)=>r1 + r2 = (10 - 2i) + (1 - i) = 11 - 3i=>b = -(r1 + r2) = -11 + 3iATDH.
there is a correction i would like to make-
bold part should be- (26-26i)/13= (2-2i)
and so b= -[(3+2i)+(2-2i)]= -5 !!