@sujamait said:There is a park which is in the shape of a right-angled triangle. A tower is situated at the mid-point of the largestedge of the park. The two perpendicular edges of the park subtend angles of 60์งธand 90์งธ at the top of the tower.Area of the park is 2592*root(2) m^2.What is the height of the tower?A. 72 2 mB. 36 2 mC. 36 mD. 72 mE. None of
without stoppage,a train travels at an average speed of 75km/h,with stoppages it covers the same distance at an average speed of 60 km/h.how many minutes per hour does the train stop.
I didn't understand what the question meant.How to solve this ?
@nole said:without stoppage,a train travels at an average speed of 75km/h,with stoppages it covers the same distance at an average speed of 60 km/h.how many minutes per hour does the train stop.I didn't understand what the question meant.How to solve this ?
@nole said:without stoppage,a train travels at an average speed of 75km/h,with stoppages it covers the same distance at an average speed of 60 km/h.how many minutes per hour does the train stop.I didn't understand what the question meant.How to solve this ?
@nole said:without stoppage,a train travels at an average speed of 75km/h,with stoppages it covers the same distance at an average speed of 60 km/h.how many minutes per hour does the train stop.I didn't understand what the question meant.How to solve this ?
@nole said:without stoppage,a train travels at an average speed of 75km/h,with stoppages it covers the same distance at an average speed of 60 km/h.how many minutes per hour does the train stop.I didn't understand what the question meant.How to solve this ?
@nole said:without stoppage,a train travels at an average speed of 75km/h,with stoppages it covers the same distance at an average speed of 60 km/h.how many minutes per hour does the train stop.I didn't understand what the question meant.How to solve this ?
@nole said:A boat sails downstream from point A to point B which is 10 km from A and then returns to A .If the actual speed of the boat is 3km/h,the trip from A to B takes 8 hours less than trip from B to A.What must be the actual speed of the boat for the trip from A to B to take exactly 100 minutes.I did it like this stream- x km/h10/(x+3) +8 = 10/(x-3)then after getting x,i substituted in 10(3+x) = 100/60 but not getting the answer.Where did i go wrong?answer is 4km/h
@nole said:A boat sails downstream from point A to point B which is 10 km from A and then returns to A .If the actual speed of the boat is 3km/h,the trip from A to B takes 8 hours less than trip from B to A.What must be the actual speed of the boat for the trip from A to B to take exactly 100 minutes.I did it like this stream- x km/h10/(x+3) +8 = 10/(x-3)then after getting x,i substituted in 10(3+x) = 100/60 but not getting the answer.Where did i go wrong?answer is 4km/h
@ScareCrow28 said:Taking speed of boat greater than speed of stream we get the answer but if we take speed of stream greater than speed of boat we don't get the answer matching answer 10/(3+x) + 8 = 10/(3-x)x = 2100/60 = 10/(2+x')x' = 4 ..
@Torque024 said:If speed of stream would be greater than that of boat, then trip from B to A(Upstream) will not be possible.
@deedeedudu said:Sir 2nd angle 90 hi hai?
@ScareCrow28 said:Sir, edges subtend angles ka matlab samajh ni aya Aur wo bhi 90 deg??
@deedeedudu said:B. 10
@sujamait said:Q is correct.and it is 90 degrees only..angle subtended by the edge...means..taking the endpoints of edge and joining with top of pole..the the angle between these to lines is ...90 or 30 as per the case..I guess now you can proceed.5 rt3
@pari19O1 said:ye kaise aaya??mera toh 4*(4-rt(3)) aa rha hai...
@tani90 said:Since a tangent makes 90 degree with the radius. In the figure the side BC is at roght angle with AO, now the right triangle is formed, i.e BAD, taking AO meets BC at D...The hypo is 8, perpendicular is 6, hence the base comes out to be 2 root...but BC= 2* base= 4 root 7Hope you got the solution...