@ScareCrow28 said:b) 6 ??
OA is 12 bro... I havent tried yet ..havin lunch
Try again buddy
@jain4444 said:all correctFind the 6-digit number beginning and ending in the digit 2 that is the product ofthree consecutive even integers.
(2x)(2x+2)(2x+4)
last digit of x should be either 2 or 7
32 Satisfy this
64*66*68-> 287232
last digit of x should be either 2 or 7
32 Satisfy this
64*66*68-> 287232
@ScareCrow28 said:b) 6 ??f(n) is an odd functionPut, n= 4f(4) = f(2) + f(6)=> f(6) = f(4) - f(2)Also, f(2) = f(0) + f(4)=> f(4) - f(2) = -f(0) = f(0)And f(0) Hence, f(6) = f(0) Hence pperiod = p =6
f(6) =- f(0) is coming :O
@jain4444 said:How many ways can the digits 1,2,3,4,5,6,7,8,9 be arranged so that no even digit is in its original position?
9!-9 ????
Total Arrangement - dearrangement of 4 even digits
Total Arrangement - dearrangement of 4 even digits
@jain4444 said:How many ways can the digits 1,2,3,4,5,6,7,8,9 be arranged so that no even digit is in its original position?
Sir, have to use all the digits??
@jain4444 said:all correctFind the 6-digit number beginning and ending in the digit 2 that is the product ofthree consecutive even integers.
60^3=216000
4,6,8...last digit
so..no.s are=64,66,68?
@Aman.Malhotra said:9!-9 ????Total Arrangement - dearrangement of 4 even digits
how is the derangement of 4 even digits 9? plz explain
off to lunch
@jain4444 said:Find a,b and c if the number "abc" in base 5 is equal to the number "cba" in base 8.
the no. comes out to be 331 and 133..i.e a=3, b=3, c=1
using the equation c+5b+25a=a+8b+64c
this gives 8a=b+21c
now we also know that a,b,c are all less than 5(since the no. also exists in base 5)
so the values which satisfies it are a=3, b=3, c=1
P.S: the other value could be 0,0,0 also if we have to consider all the nos. including zero
@jain4444 said:all correctFind the 6-digit number beginning and ending in the digit 2 that is the product ofthree consecutive even integers.
219232 = 64.66.68
@jain4444 said:72 is correct for last one In a natural number a the digits were swapped round (put in different order), after which the number decreased by 3 times. (was 3 times less then the original) . initial number is divisible by I - 9II - 27 III - 15 a) only I b) I and II c) only III d) I , II and III
din get it.
@Budokai001 said:f(n)=f(n-2)+f(n+2)If it is given that f(x)=f(x+p)What is min value of p ?a)12b)6c)8d)4e)5
12?
f(n-2)+f(n+2)=f(n)
f(n+4)+f(n)=f(n+2)
adding these two
f(n+4)+f(n-2)=0
f(n+6)+f(n)=0
f(n+8)+f(n+2)=0
f(n+10)+f(n+4)=0
f(n+12)+f(n+6)=0
f(n+12)-f(n)=0
f(n+12)=f(n)
@jain4444 said:How many ways can the digits 1,2,3,4,5,6,7,8,9 be arranged so that no even digit is in its original position?
9!-8!?
options chahiye..
@jain4444 said:How many ways can the digits 1,2,3,4,5,6,7,8,9 be arranged so that no even digit is in its original position?
9! / 4! ?? :O
Please solve these series questions...
Directions for questions 82 €“ 86: In the following number series only one number is wrong. Find out the wrong number
82. 202 102 55 36.5 34.25 42.125 57.625
82. 202 102 55 36.5 34.25 42.125 57.625
(1) 55 (2) 202 (3) 36.5 (4) 57.625
83. 12 18 26.25 40.5 60.75 91.125 136.6875
(1) 26.25 (2) 18 (3) 136.6875 (4) 60.75
(1) 26.25 (2) 18 (3) 136.6875 (4) 60.75
84. 3 7 16 32 57 96 142
(1) 57 (2) 96 (3) 142 (4) 16
(1) 57 (2) 96 (3) 142 (4) 16
85. 12 11 24 72 280 1395 8376
(1) 12 (2) 24 (3) 72 (4) 1395
(1) 12 (2) 24 (3) 72 (4) 1395
86. 16 17 37 50 83 133 216
(1) 17 (2) 216 (3) 133 (4) 50
Please explain ur method as well :)
@jain4444
8*7*6*5*5! (for 2, 8 option..for 4, 6 options and so on) rest of them can be arranged in 5! ways.
@paridhi11890
for last
37 is wrong
16+17 = 33
33+17 =50 and so on
3 7 16 32 57 96 142
(1) 57 (2) 96 (3) 142 (4) 16
(1) 57 (2) 96 (3) 142 (4) 16
7-3 =4
66-7 =9 (square of 2,3)
96 is wrong, should be 57+36
96 is wrong, should be 57+36
@paridhi11890 said:Please solve these series questions...Directions for questions 82 €“ 86: In the following number series only one number is wrong. Find out the wrong number85. 12 11 24 72 280 1395 8376(1) 12 (2) 24 (3) 72 (4) 1395
72 is the wrong one... It should be 69.
It is...
12,
(12*1 -1)=11,
(11*2 +2)=24,
(24*3 -3)=69,
(69*4 +4)= 280,
(280*5 -5)= 1395,
(1395*6 +6)=8376
@paridhi11890 said:Please solve these series questions...Directions for questions 82 €“ 86: In the following number series only one number is wrong. Find out the wrong number84. 3 7 16 32 57 96 142(1) 57 (2) 96 (3) 142 (4) 16
96 is the wrong one... It should be 93...
3+4=7
7+9=16
16+16=32
32+25=57
57+36=93
93+49=142
Circular track with perimeter - 300 meters.
Two joggers A and B start from the same point and run at ratio 5 :10 meter/min respectively. at what point they will meet for first time.