Official Quant thread for CAT 2013

@sparklingaubade India and Brazil play the Soccer World Cup final in which India defeats Brazil 10 창€“ 4. In how many different ways could the goals have been scored given that Brazil never had a lead over India during the match?
1024??
@shashankbapat23 said:
Mark 1: If the questions can be answered by using one of the statements alone, but cannot be answered using the other statement alone.Mark 2: If the question can be answered by using either statement alone.Mark 3: If the questions can be answered by using both statements together, but cannot be answered using either statement alone.Mark 4: If the question cannot be answered even by using both statements together.Each question is followed by two statements, A and B. Answer each questions using the following instructions :Question:Three professors A, B and C are separately given three sets of numbers to add. They were expected to find the answers to 1 + 1, 1 + 1 + 2 and 1 + 1 respectively. Their respective answers were 3, 3 and 2. How many of the professors are mathematicians?Statement A : A mathematician can never add two numbers correctly, but can always add three numbers correctly.Statement B : When a mathematician makes a mistake in a sum, the error is +1 or €“ 1.
I think it should be 4

We don't know about "Professor but not Mathematician" whether he does the summation alwys correct or makes an error of +1 or -1
@htomar said:
is the answer 12?
oa is diff
@Cat.Aspirant123 said:
What is the maximum number of quadratic equations that can be formed such that both of its roots are the roots of an equation having 4 roots? 461012

10?

(x-a)(x-b) =0

when a=b no of possible eqns= 4

when a not = b no of possible eqns =6

total =10
Tejash and Sushil were playing a game. The game was such that Tejash and Sushil will have to guess a sequence of three outcomes that may come by tossing an unbiased coin. For example, THH or HTT can be a sequence where T is Tails and H is Heads. Tejash will be the one who will toss the coin. Tejash will first announce his sequence and then Sushil will announce his. The person whose mentioned sequence arrives first will win the game. What could be Tejash €™s optimal strategy?

@gnehagarg said:
Tejash and Sushil were playing a game. The game was such that Tejash and Sushil will have to guess a sequence of three outcomes that may come by tossing an unbiased coin. For example, THH or HTT can be a sequence where T is Tails and H is Heads. Tejash will be the one who will toss the coin. Tejash will first announce his sequence and then Sushil will announce his. The person whose mentioned sequence arrives first will win the game. What could be Tejash €™s optimal strategy?
Announce THT or HTH ?
@ravi.theja said:
@sparklingaubadeIndia and Brazil play the Soccer World Cup final in which India defeats Brazil 10 €“ 4. In how many different ways could the goals have been scored given that Brazil never had a lead over India during the match?1024??
210 I feel. 10C4. OA pliss?

regards
scrabbler

@grkkrg said:
Announce THT or HTH ?
Approach..

Cheap and Best, a kirana shop bought some apples at 4 per rupee and an equal number at 5 per rupee.he then sold the entire quantity at 9 for 2 rupees. what is his percentage profit or loss?

a. 1.23 % loss b. 6.66% c.8.888% d no profit no loss
@ravi.theja said:
@sparklingaubadeIndia and Brazil play the Soccer World Cup final in which India defeats Brazil 10 창€“ 4. In how many different ways could the goals have been scored given that Brazil never had a lead over India during the match?
Goal scored by Brazil - B
Goal scored by India - I

Cases:
1) I I I I _ _ _ _ _ _ _ _ _ _ => 10!/(6!4!) = 210

2) I I I B _ _ _ _ _ _ _ _ _ _ => 10!(7!3!) - 1 = 119

3) I I B _ _ _ _ _ _ _ _ _ _ _ => 11!/(8!3!) - 9!(8!1!) = 156

4) I B I _ _ _ _ _ _ _ _ _ _ _ => 11!/(8!3!) - 9!/(8!1!) = 156

Total = 210 + 119 + 156 + 156 = 641 :splat:

I think I have messed up a lot in this ! :banghead:

@sparklingaubade
@IIM-A2013 said:
Cheap and Best, a kirana shop bought some apples at 4 per rupee and an equal number at 5 per rupee.he then sold the entire quantity at 9 for 2 rupees. what is his percentage profit or loss?a. 1.23 % loss b. 6.66% c.8.888% d no profit no loss
option 1

1 apple price 1/4

another variety 1/5

now 2 kg will cost CP=9/20

entire quantity is sold at SP =4/9

calculate to get 1.23% loss
@IIM-A2013 said:
Cheap and Best, a kirana shop bought some apples at 4 per rupee and an equal number at 5 per rupee.he then sold the entire quantity at 9 for 2 rupees. what is his percentage profit or loss?a. 1.23 % loss b. 6.66% c.8.888% d no profit no loss
a. 1.23%?

CP = a/4 + a/5 = 9a/20 = 81a/180
SP = (2a)*(2/9) = 4a/9 = 80a/180

Percentage loss = 1/81 * 100 = 1.23%
@IIM-A2013 said:
Cheap and Best, a kirana shop bought some apples at 4 per rupee and an equal number at 5 per rupee.he then sold the entire quantity at 9 for 2 rupees. what is his percentage profit or loss?a. 1.23 % loss b. 6.66% c.8.888% d no profit no loss
1.23%
@Cat.Aspirant123 said:
What is the maximum number of quadratic equations that can be formed such that both of its roots are the roots of an equation having 4 roots? 461012
10
@Cat.Aspirant123 said:
What is the maximum number of quadratic equations that can be formed such that both of its roots are the roots of an equation having 4 roots? 461012
For the maximum number, I will assume distinct roots for the equation having 4 roots,
i.e. (x-a)*(x-b)*(x-c)*(x-d)

Case 1: I create quadratic with distinct roots => 4C2 = 6
Case 2: I create quadratic with equal roots => 4C1 = 4

Total = 10 ?
@IIM-A2013 said:
Cheap and Best, a kirana shop bought some apples at 4 per rupee and an equal number at 5 per rupee.he then sold the entire quantity at 9 for 2 rupees. what is his percentage profit or loss?a. 1.23 % loss b. 6.66% c.8.888% d no profit no loss
cp=1/4+1/5=9/20
sp=4/9
loss%=1.23%

For Quants.....Which book is better???


Arun Sharma or T.I.M.E Material???


@tmohan02 said:
For Quants.....Which book is better???Arun Sharma or T.I.M.E Material??? http://www.pagalguy.com/forums/prep-resources/crack-section-cat-t-82497/p-3531936
Here you will get to know how to prepare for quants. Each n everything 😃
@YouMadFellow said:
Goal scored by Brazil - BGoal scored by India - ICases:1) I I I I _ _ _ _ _ _ _ _ _ _ => 10!/(6!4!) = 2102) I I I B _ _ _ _ _ _ _ _ _ _ => 10!(7!3!) - 1 = 1193) I I B _ _ _ _ _ _ _ _ _ _ _ => 11!/(8!3!) - 9!(8!1!) = 1564) I B I _ _ _ _ _ _ _ _ _ _ _ => 11!/(8!3!) - 9!/(8!1!) = 156Total = 210 + 119 + 156 + 156 = 641 I think I have messed up a lot in this ! @sparklingaubade
I think its not correct

In case 2:- I I B _ _ _ _ _ _ _ _ _ _ _, you have excluded I I B B B, but you didn't remove
I I B B I B B and I I B I B B B cases
In case 3:- I B I _ _ _ _ _ _ _ _ _ _ _, you have excluded I B I B B but not I B I B I B B,
I B I I B B B

So, removing these 4 cases you will also get 637 ways which is exactly the same I got using Catalan numbers

C(14, 4) - C(14, 3) = 637
@chillfactor Oops, yes, I missed that :), I was not aware of Catalan numbers :splat: . Thanks 😃