What is the radius of the circum-circle of the triangle formed by the line 12x + 5y = 60 and the coordinate axes?
3.5
4.5
6.5
7.5
What is the area (in cm2) of the triangle with medians of lengths 10 cm, 12 cm and 18 cm?
Australia scored a total of x runs in 50 overs . India tied the scores in 20% less over . If India's average run rate had been 33.33% higher the scores would have been tied10 overs earlier.
Find how many runs were scored by Australia?
(a) 250 (b) 240 (c) 200 (c) can not be determined
@TootaHuaDil said:Difference in speedscreated due to stoppages =9km/hrNow, 9km=54km/hr * time of stoppagesSo, time of stoppages=10mins. Is my logic right??
Absolutely right!! :thumbsup:
When we include stoppage time also, average speed reduced by 9 km/hr
=> in every one hour, bus covers 9 km less.
speed of bus=54 km/hr
==> stoppage time=9/54=1/6=10 minutes
@Cat.Aspirant123 said:What is the area (in cm2) of the triangle with medians of lengths 10 cm, 12 cm and 18 cm?
there is direct formula to find the area...when median are given
area=4/3*_/{s(s-a)(s-b)(s-c)}
where s=(a+b+c)/2
a,b,c are lenght of medians....
area=160/3*_/2
@Cat.Aspirant123 said:What is the radius of the circum-circle of the triangle formed by the line 12x + 5y = 60 and the coordinate axes?3.54.56.57.5
it will form a right triangle...
with cordinates (0,0) (5,0) (0,12) { x/5+ y/12=60 representing in point slope form}
hypotenuse length is 13
so circum radius =13/2=6.5
@IIM-A2013 said:Australia scored a total of x runs in 50 overs . India tied the scores in 20% less over . If India's average run rate had been 33.33% higher the scores would have been tied10 overs earlier.Find how many runs were scored by Australia?(a) 250 (b) 240 (c) 200 (c) can not be determined
solve using options. 240 should be the answer
@IIM-A2013 said:Australia scored a total of x runs in 50 overs . India tied the scores in 20% less over . If India's average run rate had been 33.33% higher the scores would have been tied10 overs earlier.Find how many runs were scored by Australia?(a) 250 (b) 240 (c) 200 (c) can not be determined
d) cannot be determined?
Aus: x in 50 overs
Ind: x in 40 overs
India's run rate = x / 40
New run rate = 4/3 * (x/40) = x/30
So India would have scored x in 30 overs irrespective of x.
So CBD
Aus: x in 50 overs
Ind: x in 40 overs
India's run rate = x / 40
New run rate = 4/3 * (x/40) = x/30
So India would have scored x in 30 overs irrespective of x.
So CBD
@grkkrg said:d) cannot be determined?Aus: x in 50 oversInd: x in 40 oversIndia's run rate = x / 40New run rate = 4/3 * (x/40) = x/30So India would have scored x in 30 overs irrespective of x.So CBD
@IIM-A2013 said:Australia scored a total of x runs in 50 overs . India tied the scores in 20% less over . If India's average run rate had been 33.33% higher the scores would have been tied10 overs earlier.Find how many runs were scored by Australia?(a) 250 (b) 240 (c) 200 (c) can not be determined
cannot be determined
x= 40y {y is avg of india}
x= 30 (4/3*y)
not getting any unique value...
@IIM-A2013 said:Australia scored a total of x runs in 50 overs . India tied the scores in 20% less over . If India's average run rate had been 33.33% higher the scores would have been tied10 overs earlier.Find how many runs were scored by Australia?(a) 250 (b) 240 (c) 200 (c) can not be determined
(x/30)/(x/40) = 1.33
irrespective of value of x average rate turns out to be 33.33% higher if india scored in 10 overs less. Hence CBD.
ATDH.
Consider the set P = {–5, –3, –1, 1, 3, 5….} consisting of 1998 numbers. If 'a' be the average of the elements in P and 'b' be twice the average of the first 1998 natural numbers, then find the value of (a – b)?
@IIM-A2013 said:Australia scored a total of x runs in 50 overs . India tied the scores in 20% less over . If India's average run rate had been 33.33% higher the scores would have been tied10 overs earlier.Find how many runs were scored by Australia?(a) 250 (b) 240 (c) 200 (c) can not be determined
Everyone gearing up for 21st Dec'12 ??? This eerie silence...
Run rate of India in 20% less overs = x/40
If run rate were 33.33% higher, run rate would be = x/30
Run rate in 10 less overs than previous case: x/30
Hence, it is true irrespective of x
So, D) CBD
@bullseyes said:Consider the set P = {–5, –3, –1, 1, 3, 5….} consisting of 1998 numbers. If 'a' be the average of the elements in P and 'b' be twice the average of the first 1998 natural numbers, then find the value of (a – b)?
A.M of elements of P = [1998/2] * [(3984)/1998] = 1992
A.M of 1st 1998 natural numbers = 1998*1999/2*1998 = 1999/2
2(A.M of 1st 1998 natural numbers) = 1999
Difference = 1999 - 1992 = 7 .. = (b-a)
Hence, (a-b) = -7 ..
:P
@bullseyes said:Consider the set P = {–5, –3, –1, 1, 3, 5….} consisting of 1998 numbers. If 'a' be the average of the elements in P and 'b' be twice the average of the first 1998 natural numbers, then find the value of (a – b)?
-7 ?
first term = -5
n = 1998
d = 2
a = 1/2 ( -10 + 1997(2)) = 1/2 * (3984) = 1992
b = (1999/2) * 2 = 1999
a - b = -7
first term = -5
n = 1998
d = 2
a = 1/2 ( -10 + 1997(2)) = 1/2 * (3984) = 1992
b = (1999/2) * 2 = 1999
a - b = -7
@Enceladus said:€Ž4 dies are thrown. find the probability that the sum of them will be 18?
x1+x2+x3+x4 =18 (where x1,x2,x3 and x4
(6-x1')+(6-x2')+(6-x3')+(6-x4') = 18
=>x1'+x2'+x3'+x4' = 6 { x1' x2' x3' x4'
=C(9,3) - 4 (cases like 6,0,0,0)
=80
=>p(18) = 80/6^4 = 5/81
ATDH
@veertamizhan said:"A person travels from P to Q at the speed of 40 kmph. By what percent should he increase his speed on the return journey so that his average speed for the round trip is 48 kmph."
average speed for round trip is HM of two speeds
hence 1/40 + 1/x = 2/48
=>1/x = 1/24 - 1/40
=>x = 120/2 = 60
=>his speed should be increased by 33%
ATDH.
@IIM-A2013 said:Australia scored a total of x runs in 50 overs . India tied the scores in 20% less over . If India's average run rate had been 33.33% higher the scores would have been tied10 overs earlier.
Find how many runs were scored by Australia?
(a) 250 (b) 240 (c) 200 (c) can not be determined
X score of india
20% less means India finished in 40 overs
so net run rate = x/40
now if the run rate is increased by 33.33% i.e 4/3*x/40= x/30 i.e the run rate for 30 overs which is already given in the question.. and X still remains to be unkown 
so CBD
so CBD
How much simple interest is earned after 2 years?
I. The difference between the simple interest and the corresponding compound interest is 12.
II. The compound interest on the same sum for the 2 years at the same rate is 252.
A alone, B alone, either alone, neither, Both required
I. The difference between the simple interest and the corresponding compound interest is 12.
II. The compound interest on the same sum for the 2 years at the same rate is 252.
A alone, B alone, either alone, neither, Both required