A train left station X at A hour B minutes.It reached station Y at B hour C minutes on the same day, after traveling for C hours A minutes (clock shows from 0 hours to 24 hours).Number of possible values of A is:
A) 3
B) 1
C) 2
D) 0
E) none of the above.
@vijay_chandola said:A train left station X at A hour B minutes.It reached station Y at B hour C minutes on the same day, after traveling for C hours A minutes (clock shows from 0 hours to 24 hours).Number of possible values of A is:A) 3B) 1C) 2D) 0E) none of the above.
D) 0 ??? Maine XAT prep me kia apne btaya he ni? :P
@sujamait said:A medical practitioner has created differentpotencies of a commonly used medicine bydissolving tables in water and using the resultantsolution.Potency 1 solution: When 1 tablet is dissolved in 50ml, the entire 50 ml is equivalent to one dose.Potency 2 solution: When 2 tablets are dissolved in50 ml, the entire 50 ml of this solution is equivalentto 2 doses,… and so on.This way he can give fractions of tablets based onthe intensity of infection and the age of thepatient.For particular patient, he administers 10 ml ofpotency 1, 15 ml of potency 2 and 30 ml ofpotency 4. The dosage administered to thepatient is equivalent to (1 mark)(1) > 2 and ≤ 3 tablets(2) > 3 and ≤ 3.25 tablets(3) > 3.25 and ≤ 3.5 tablets(4) > 3.5 and ≤ 3.75 tablets(5) > 3.75 and ≤ 4 tablets
10/50+2*15/50+4*30/50=160/50=3.2=> option 2
@sujamait said:nhn bhai 3.2 aa rha tha mera toh...option 2City Bus Corporation runs two buses fromterminus A to terminus B, each bus making 5round trips in a day. There are no stops inbetween. These buses ply back and forth on thesame route at different but uniform speeds. Eachmorning the buses start at 7 AM from therespective terminuses. They meet for the firsttime at a distance of 7 km from terminus A. Theirnext meeting is at a distance of 4 km fromterminus B, while travelling in oppositedirections. Assuming that the time taken by thebuses at the terminuses is negligibly small, andthe cost of running a bus is 20 per km, find thedaily cost of running the buses (in ). (1 mark)(1) 3200 (2) 4000 (3) 6400(4) 6800 (5) None of the above
6800?
@sujamait said:nhn bhai 3.2 aa rha tha mera toh...option 2City Bus Corporation runs two buses fromterminus A to terminus B, each bus making 5round trips in a day. There are no stops inbetween. These buses ply back and forth on thesame route at different but uniform speeds. Eachmorning the buses start at 7 AM from therespective terminuses. They meet for the firsttime at a distance of 7 km from terminus A. Theirnext meeting is at a distance of 4 km fromterminus B, while travelling in oppositedirections. Assuming that the time taken by thebuses at the terminuses is negligibly small, andthe cost of running a bus is 20 per km, find thedaily cost of running the buses (in ). (1 mark)(1) 3200 (2) 4000 (3) 6400(4) 6800 (5) None of the above
6800
Let speed of bus-1 be S1 and bus-2 be S2
And total distance be D
Then, 7/S1 = (D-7)/S2
And, (D+D-4)/S2 = (D-4)/S1
From both equations we get D = 17km
Hence, One round trip = 34kms
Total cost = 5*34*20*2 =6800
@ScareCrow28 said:D) 0 ??? Maine XAT prep me kia apne btaya he ni?
You did? Sorry I didn't see you solution. Let me check :splat:
@sujamait said:nhn bhai 3.2 aa rha tha mera toh...option 2City Bus Corporation runs two buses fromterminus A to terminus B, each bus making 5round trips in a day. There are no stops inbetween. These buses ply back and forth on thesame route at different but uniform speeds. Eachmorning the buses start at 7 AM from therespective terminuses. They meet for the firsttime at a distance of 7 km from terminus A. Theirnext meeting is at a distance of 4 km fromterminus B, while travelling in oppositedirections. Assuming that the time taken by thebuses at the terminuses is negligibly small, andthe cost of running a bus is 20 per km, find thedaily cost of running the buses (in ). (1 mark)(1) 3200 (2) 4000 (3) 6400(4) 6800 (5) None of the above
Let x be the distance between the two terminals and v1 and v2 be the speeds of two buses.
v1/v2=7/(x-7)=(x-4)/(2*x-4)
=> x^2-17*x=0=> x=17
=> Total distance traveled by both the buses=2*(17*2*5)=340
=> total cost incurred =340*20=6800
@sujamait said:nhn bhai 3.2 aa rha tha mera toh...option 2City Bus Corporation runs two buses fromterminus A to terminus B, each bus making 5round trips in a day. There are no stops inbetween. These buses ply back and forth on thesame route at different but uniform speeds. Eachmorning the buses start at 7 AM from therespective terminuses. They meet for the firsttime at a distance of 7 km from terminus A. Theirnext meeting is at a distance of 4 km fromterminus B, while travelling in oppositedirections. Assuming that the time taken by thebuses at the terminuses is negligibly small, andthe cost of running a bus is 20 per km, find thedaily cost of running the buses (in ). (1 mark)(1) 3200 (2) 4000 (3) 6400(4) 6800 (5) None of the above
let speed of bus A = 7 and of bus B = x
|A|------7-----(1st meeting point)----(x - 4) -------(2nd meeting point)-----4-----|B|
(x + 4)/7 = (10 + x)/x
x^2 + 4x = 70 + 7x
=> x = 10
total distance = 7 + 10 = 17
so , there are 20 trips in total , total cost = 17*20*20 = 6800
A and B together can do a piece of work in 16 days.B and C can do the same work in 32 days.After A worked for 4 days,B for 12 days,C takes up and finished it alone in 48 days.In how many days will each of them complete the work?
@ScareCrow28 said:6800Let speed of bus-1 be S1 and bus-2 be S2And total distance be DThen, 7/S1 = (D-7)/S2And, (D+D-4)/S2 = (D-4)/S1From both equations we get D = 17kmHence, One round trip = 34kmsTotal cost = 5*34*20*2 =6800
@vijay_chandola said:You did? Sorry I didn't see you solution. Let me check Let x be the distance between the two terminals and v1 and v2 be the speeds of two buses. v1/v2=7/(x-7)=(x-4)/(2*x-4)=> x^2-17*x=0=> x=17=> Total distance traveled by both the buses=2*(17*2*5)=340=> total cost incurred =340*20=6800
@19rsb said:6800?
6800 is rite..
but are these buses starting from A n B respectively ? or both start from A...sorta confused in language..
A computer program was tested 300 times before
its release. The testing was done in three stages
of 100 tests each. The software failed 15 times in
Stage I, 12 times in Stage II, 8 times in Stage III, 6
Suresh, who runs a bakery, uses a conical shaped
equipment to write decorative labels (e.g., Happy
Birthday etc.) using cream. The height of this
equipment is 7 cm and the diameter of the base is
5 mm. A full charge of the equipment will write
330 words on an average. How many words can
be written using three fifth of a litre of cream?
(1.5 marks)
(1) 45090 (2) 45100
(3) 46000 (4) 43200
(5) None of the above.
its release. The testing was done in three stages
of 100 tests each. The software failed 15 times in
Stage I, 12 times in Stage II, 8 times in Stage III, 6
times in both Stage I and Stage II, 7 times in both
Stage II and Stage III, 4 times in both Stage I and
Stage III, and 4 times in all the three stages. How
many times the software failed in a single stage
only? (1 mark)
(1) 10 (2) 13 (3) 15 (4) 17 (5) 35
Stage II and Stage III, 4 times in both Stage I and
Stage III, and 4 times in all the three stages. How
many times the software failed in a single stage
only? (1 mark)
(1) 10 (2) 13 (3) 15 (4) 17 (5) 35
Suresh, who runs a bakery, uses a conical shaped
equipment to write decorative labels (e.g., Happy
Birthday etc.) using cream. The height of this
equipment is 7 cm and the diameter of the base is
5 mm. A full charge of the equipment will write
330 words on an average. How many words can
be written using three fifth of a litre of cream?
(1.5 marks)
(1) 45090 (2) 45100
(3) 46000 (4) 43200
(5) None of the above.
.........................................................
OA
2
5
@jain4444 said:A and B together can do a piece of work in 16 days.B and C can do the same work in 32 days.After A worked for 4 days,B for 12 days,C takes up and finished it alone in 48 days.In how many days will each of them complete the work?
A----> 160/7 days
B----> 160/3 days
C---->80 days ??
@jain4444 said:A and B together can do a piece of work in 16 days.B and C can do the same work in 32 days.After A worked for 4 days,B for 12 days,C takes up and finished it alone in 48 days.In how many days will each of them complete the work?
A=160/7
B=160/3
C=80
B=160/3
C=80
@jain4444 said:A and B together can do a piece of work in 16 days.B and C can do the same work in 32 days.After A worked for 4 days,B for 12 days,C takes up and finished it alone in 48 days.In how many days will each of them complete the work?
A takes 160/7 days
B takes 160/3 days
C takes 80 days
1/A + 1/B = 1/16
1/B + 1/C = 1/32
4/A + 12/B + 48/C = 1
4/A + 4/B + 8/B + 8/C + 40/C = 1
1/4 + 1/4 + 40/C = 1
40/C = 1/2
C = 80 days
1/B = 1/32 - 1/80 = 6/320 = 3/160
B = 160/3 days
1/A = 1/16 - 3/160 = 7/160
A = 160/7
B takes 160/3 days
C takes 80 days
1/A + 1/B = 1/16
1/B + 1/C = 1/32
4/A + 12/B + 48/C = 1
4/A + 4/B + 8/B + 8/C + 40/C = 1
1/4 + 1/4 + 40/C = 1
40/C = 1/2
C = 80 days
1/B = 1/32 - 1/80 = 6/320 = 3/160
B = 160/3 days
1/A = 1/16 - 3/160 = 7/160
A = 160/7
@jain4444 said:A and B together can do a piece of work in 16 days.B and C can do the same work in 32 days.After A worked for 4 days,B for 12 days,C takes up and finished it alone in 48 days.In how many days will each of them complete the work?
a+b = 100/16 = 6.25%
b+c= 3.125%
4a + 12b + 48c = 100%
a=4.375,b=1.875,c=1.25
so,
days,
a=22.8
b=53.33
c=80
@sujamait said:6800 is rite..but are these buses starting from A n B respectively ? or both start from A...sorta confused in language..
Each morning the buses start at 7 AM from the respective 'terminuses' ==> One bus would start from A and the other one would from B
A train, an hour after starting, meets with an
accident which detains it for a half hour, after
which it proceeds at 3/4 of its former rate and
arrives 3(1/2) hours late. Had the accident
happened 90 kilometers farther along the line, it
would have arrived only 3 hour late.What was the length of
the trip in kilometers?......Dont hav the OA so post answer with your approach
accident which detains it for a half hour, after
which it proceeds at 3/4 of its former rate and
arrives 3(1/2) hours late. Had the accident
happened 90 kilometers farther along the line, it
would have arrived only 3 hour late.What was the length of
the trip in kilometers?......Dont hav the OA so post answer with your approach
@sujamait said:A computer program was tested 300 times beforeits release. The testing was done in three stagesof 100 tests each. The software failed 15 times inStage I, 12 times in Stage II, 8 times in Stage III, 6 times in both Stage I and Stage II, 7 times in bothStage II and Stage III, 4 times in both Stage I andStage III, and 4 times in all the three stages. Howmany times the software failed in a single stageonly? (1 mark)(1) 10 (2) 13 (3) 15 (4) 17 (5) 35
easy one. (venn diagram)
9+3+1=13times
9+3+1=13times
@vijay_chandola said:Each morning the buses start at 7 AM from the respective 'terminuses' ==> One bus would start from A and the other one would from B
how wud i knoe what are here respective terminuses ? i cud assume both to be A also .. 
@vijay_chandola said:easy one. (venn diagram)9+3+1=13times
han yar yeh sitters exam mein rah jate hein..pata nhn chal pata...
Ram, a farmer, managed to grow shapedwatermelons
inside glass cases of different
shapes. The shapes he used were: a perfect cube,
hemi-spherical, cuboid, cylindrical along with the
normal spherical shaped watermelons. Thickness
of the skin was same for all the shapes. Each of
the glass cases was so designed that the total
volume and the weight of the all the watermelons
would be equal irrespective of the shape.
A customer wants to but water-melons for
making juice, for which the skin of the watermelon
has to be peeled off, and therefore is a
waste. Which shape should the customer buy? (1
mark)
(1) Cube (2) Hemi-sphere
(3) Cuboid (4) Cylinder
(5) Normal spherical
inside glass cases of different
shapes. The shapes he used were: a perfect cube,
hemi-spherical, cuboid, cylindrical along with the
normal spherical shaped watermelons. Thickness
of the skin was same for all the shapes. Each of
the glass cases was so designed that the total
volume and the weight of the all the watermelons
would be equal irrespective of the shape.
A customer wants to but water-melons for
making juice, for which the skin of the watermelon
has to be peeled off, and therefore is a
waste. Which shape should the customer buy? (1
mark)
(1) Cube (2) Hemi-sphere
(3) Cuboid (4) Cylinder
(5) Normal spherical
@19rsb said:A train, an hour after starting, meets with anaccident which detains it for a half hour, afterwhich it proceeds at 3/4 of its former rate andarrives 3(1/2) hours late. Had the accidenthappened 90 kilometers farther along the line, itwould have arrived only 3 hour late.What was the length ofthe trip in kilometers?......Dont hav the OA so post answer with your approach
690?
90/(3v4)-90/v=30/60
v=60 km/h
in 30 mins train cover 90 km
so in 210 mins train will cover....210*90/30=630km
initial distance=1*60 =60km
total dist=630+60=690km