A train meets with an accident 150 km from the originating station. It completetd the remaining journey at half of the usual speed and reached an hour late at the destination. Had the accident took palce 30 km later, it would have been only half an hour late. Find the distance between the two stations.
No need of any calculation.The answer is given in statement. Statement says it would have taken 30 mins less if accident had taken 30 km later, that means the distance he needs to travel to reach station is 60 km, hence he is taking 60 mins..So total distance is 150+60=210km
@chillfactor thanks.I understood your solution,it may sound silly but i want to know how did u realise that c(6,4) approach would lead to redundant cases ? I mean is there any way to avoid such approach in exam to save time ?
Duels in the town of discretion are rarely fatal. There, each contestant comes at a random moment between 5 a.m. and 6 a.m. on the appointed day and leaves exactly 5 minutes later, honor served, unless his opponent arrives within the time interval then they fight. What fraction of duels lead to violence? ..
Let A be at origin A(0,0) B(20,0) C(20,10) D(0,10) W(x,y) Required distance=2WC where C is the center of rectangle C=(20/2,10/2)=(10,5) WC=20, WD=12 x^2+y^2-20y=12^2-10^2---1 x^2-40x+y^2-20y=16^2-20^2-10^2--2 Subtract 1 and 2 40x=288; x=7.2, y=19.6 Req distance=2*WC=2*sqrt((2.8)^2+(14.6)^2)=2sqrt(221)
Duels in the town of discretion are rarely fatal. There, each contestant comes at a random moment between 5 a.m. and 6 a.m. on the appointed day and leaves exactly 5 minutes later, honor served, unless his opponent arrives within the time interval then they fight. What fraction of duels lead to violence? ..
Duels in the town of discretion are rarely fatal. There, each contestant comes at a random moment between 5 a.m. and 6 a.m. on the appointed day and leaves exactly 5 minutes later, honor served, unless his opponent arrives within the time interval then they fight. What fraction of duels lead to violence? ..
Ashish is studying late into the night and id hungry . He opens his mother's snack cupboard without switching on the lights . Knowing that his mother has kept 10 packets of chips and biscuits in the cupboards . He pulls out 3 packets from the cupboards and all of them turn out to be chips . what is the probability that the snack cupboard contains 1 packets of biscuits and 9 packets of chips ?
i approached it like this.
number of possible cases
3chips packet 7biscuit 4chips 6 biscuit 5chips 5 biscuits 6chips 4biscuits 7chips 3 biscuits 8chips 2 biscuits 9chips 1biscuits 10 chips 0 biscuits(although i took this case also,because in forums everyone was taking it,but when it is given 10 packets of chips and biscuits,then i think ATLEAST 1 biscuits packet must be there.isn't it?? )
so my answer was 1/8,because above there are total 8 cases.
but the answer is Probability = C(9, 3)/{C(10, 3) + C(9, 3) + .... + C(3, 3)} = 84/330 = 14/55.
How??
This was IIFT 2012 question. can anyone explain why 1/8 is wrong answer and how we got 14/55 ?
Ashish is studying late into the night and id hungry . He opens his mother's snack cupboard without switching on the lights . Knowing that his mother has kept 10 packets of chips and biscuits in the cupboards . He pulls out 3 packets from the cupboards and all of them turn out to be chips . what is the probability that the snack cupboard contains 1 packets of biscuits and 9 packets of chips ?i approached it like this.number of possible cases3chips packet 7biscuit4chips 6 biscuit5chips 5 biscuits6chips 4biscuits7chips 3 biscuits8chips 2 biscuits9chips 1biscuits10 chips 0 biscuits(although i took this case also,because in forums everyone was taking it,but when it is given 10 packets of chips and biscuits,then i think ATLEAST 1 biscuits packet must be there.isn't it?? )so my answer was 1/8,because above there are total 8 cases.but the answer is Probability = C(9, 3)/{C(10, 3) + C(9, 3) + .... + C(3, 3)} = 84/330 = 14/55.How??This was IIFT 2012 question. can anyone explain why 1/8 is wrong answer and how we got 14/55 ?
Was discussed many times before http://www.pagalguy.com/forums/quantitative-ability-and-di/official-quant-thread-c-t-88456/p-3611604/r-4108616?page=355
The annual production in cement industry is subjected to business cycles.The production increases for two consecutive years consistently by 18% and decreases by 12% in the third year.Again in the next two years,it increases by 18% each year and decreases by 12% in the third year.Taking 2008 as the base year,what will be the approximate effect on cement production in 2012 ?
IFT 2012 questionThe annual production in cement industry is subjected to business cycles.The production increases for two consecutive years consistently by 18% and decreases by 12% in the third year.Again in the next two years,it increases by 18% each year and decreases by 12% in the third year.Taking 2008 as the base year,what will be the approximate effect on cement production in 2012 ?a)24%increaseb)37%increasec)45%increased)60%increaseHow to approach this question?
IFT 2012 questionThe annual production in cement industry is subjected to business cycles.The production increases for two consecutive years consistently by 18% and decreases by 12% in the third year.Again in the next two years,it increases by 18% each year and decreases by 12% in the third year.Taking 2008 as the base year,what will be the approximate effect on cement production in 2012 ?a)24%increaseb)37%increasec)45%increased)60%increaseHow to approach this question?
100 lekar kiya tha..45% aaya tha exam mein i guess
IFT 2012 questionThe annual production in cement industry is subjected to business cycles.The production increases for two consecutive years consistently by 18% and decreases by 12% in the third year.Again in the next two years,it increases by 18% each year and decreases by 12% in the third year.Taking 2008 as the base year,what will be the approximate effect on cement production in 2012 ?a)24%increaseb)37%increasec)45%increased)60%increaseHow to approach this question?
Let cement production in 2008 be 1 in 2012 it will be 1*1.18*1.18*.88*1.18 =1.445 ,so it increases .445*100=44.5%