@ankita14 said:Oh ha sorry
ankita ji aapka ans bhi wrong ho sakta hai..????
@19rsb said:10 boxes each has n balls, you have a spring balance which can measure accurate weights . Each ball is 100gm.Only one box contains lighter balls of 90gm each.You can take out any number of balls from any number of boxes.m=number of minimum weighings find m ,when n=1)92)83)14)25)3
0,1,2,3,4,5,6,7,8,9
We can take 0,1,2,3,4,5,6,7,8,9 balls from boxes 1,2,3,4,5,6,7,8,9,10
Had ball with weight 90gm in first box sum=4500
Had in second box sum=4490
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Had ball with weight in 10th box sum = 4410
We can take 0,1,2,3,4,5,6,7,8,9 balls from boxes 1,2,3,4,5,6,7,8,9,10
Had ball with weight 90gm in first box sum=4500
Had in second box sum=4490
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Had ball with weight in 10th box sum = 4410
m=10
@viewpt said:Q: in how many ways six diffenrnt balls can be put in 5 different boxes?sabhi puys ko__/\__
5^6
@viewpt said:5^6 hona chahiye na??==================================================Q: on a rectilinear path in same direction A is running at a speed of p=7.5 m/s and B is running at q=6.9 m/s where p>q and the distance b/w A and B =1mt. A is ahead of B. then wtithin how many seconds A will catch B?
1/(7.5-6.9) na bhai??
kya mai kuch miss kar raha hu??
PS : back to PG after a long time 😃
@chandrakant.k said:1/(7.5-6.9) na bhai??kya mai kuch miss kar raha hu??PS : back to PG after a long time
bhai now chk I have edited sorry for mistake.
@chandrakant.k said:1/(7.5-6.9) na bhai??kya mai kuch miss kar raha hu??PS : back to PG after a long time
It's given that A is ahead of B so possible nai hoga,
I think, had it been, B is ahead of A then (1/7.5-6.9) hota.
I think, had it been, B is ahead of A then (1/7.5-6.9) hota.
@viewpt said:bhai now chk I have edited sorry for mistake.
A is a head of B so not possible..? 
@Torque024 : i missed it 😁
@viewpt : bhai question aur ek baar post karo.. i am still getting the same question.. refreshed, closed and opened the thread again 😞
Q: In how many ways a regular hexagon can be painted with a yellow color?
A student took examination in 6 papers. The Marks are in the ratio 2:3:4:5:6:7. Total marks of all these papers = 60% of the maximum marks. In how many papers he scored more than 50% marks?
@tmohan02 said:A student took examination in 6 papers. The Marks are in the ratio 2:3:4:5:6:7. Total marks of all these papers = 60% of the maximum marks. In how many papers he scored more than 50% marks?
4?
2x + 3x + 4x + 5x + 6x + 7x = 27x
27x = 0.6 T
T = 45x
Assuming the maximum marks are the same for all papers
t = T/6 = 7.5x
t/2 = 3.75x
So he scored more than 50% in 4 papers.
2x + 3x + 4x + 5x + 6x + 7x = 27x
27x = 0.6 T
T = 45x
Assuming the maximum marks are the same for all papers
t = T/6 = 7.5x
t/2 = 3.75x
So he scored more than 50% in 4 papers.
@viewpt said:Q: In how many ways a hexagon can be painted with a yellow color?
Where are we painting the hexagon ? The edges ? Hollow hexagon ?
I considered hollow symmetrical hexagon, so only painting the edges
painted 1 edge- 1 way
painted 2 edges - 3 ways
painted 3 edges - 4 ways
painted 4 edges - 3 ways
painted 5 edges - 1 way
painted 6 edges - 1 way
13 ways ? I am doubtful though 😐 ...
@viewpt said:Q: In how many ways a hexagon can be painted with a yellow color?
only 1 edge painted => 1 way
2 edges painted => 3 ways (2 opposite face, or 2 adjacent, 2 faces with 1 gap)
3 edges painted => 4 ways (3 adjacent, no 2 adjacent, 2 adjacent 1 with 1 gap (2 ways))
4 edges painted => 3 ways (just as 2 edges painted)
5 edges painted => 1 way
6 edges painted => 1 way
total = 13 ways
20+30+40+50+60+70 =270
270=MM*.6; MM=450, For each paper MM=450/6
50%=450/12=37.xy
So more than 37.xy=40, 50, 60, 70 Total 4
@tmohan02 said:A student took examination in 6 papers. The Marks are in the ratio 2:3:4:5:6:7. Total marks of all these papers = 60% of the maximum marks. In how many papers he scored more than 50% marks?
27x = 0.6T
T= 27x/0.6 = 9x/0.2 = 45x
so total marks = 45x
consider each sub max = 45x/6 = 7.5x
more than 50% 4 5 6 7
so 4 papers??
@culdip said:only 1 face painted => 1 way2 faces painted => 2 ways (2 opposite face, or 2 adjacent)3 faces painted => 2 ways (2 of 3 is opposite, or no 2 opposite)4 faces painted => 2 ways (just as 2 faces painted)5 faces painted => 1 way6 faces painted => 1 waytotal = 9 ways
culdip bhai__/\__
iska 1 nahi hoga kya..? [ i means if the no. of ways of coloring a dice with a color is by only one way. then wudn't it holds good for other polygons>>
iska 1 nahi hoga kya..? [ i means if the no. of ways of coloring a dice with a color is by only one way. then wudn't it holds good for other polygons>>
@tmohan02 said:A student took examination in 6 papers. The Marks are in the ratio 2:3:4:5:6:7. Total marks of all these papers = 60% of the maximum marks. In how many papers he scored more than 50% marks?
4 no. of papers
@tmohan02 said:A student took examination in 6 papers. The Marks are in the ratio 2:3:4:5:6:7. Total marks of all these papers = 60% of the maximum marks. In how many papers he scored more than 50% marks?
4 papers
@viewpt said:culdip bhai__/\__iska 1 nahi hoga kya..? [ i means if the no. of ways of coloring a dice with a color is by only one way. then wudn't it holds good for other polygons>>
koi jaruri nahi sare faces paint hi karne hon.
1 se 6 tak kitne bhi faces painted ho sakte hain