A car overtakes an auto at point A at 9 am. The car reaches pont B at 11 am and immediately turns back. It again meets the auto at point C at 11:30 am. At what time will the auto reach B?
A car overtakes an auto at point A at 9 am. The car reaches pont B at 11 am and immediately turns back. It again meets the auto at point C at 11:30 am. At what time will the auto reach B?
A car overtakes an auto at point A at 9 am. The car reaches pont B at 11 am and immediately turns back. It again meets the auto at point C at 11:30 am. At what time will the auto reach B?
A car overtakes an auto at point A at 9 am. The car reaches pont B at 11 am and immediately turns back. It again meets the auto at point C at 11:30 am. At what time will the auto reach B?
let AB=x since car takes 2hrs from A to B and half an hour from B to C , then BC =x/4 implies CA=3x/4 now auto takes 150 min to travel A to C ,implies it will take 50 min from C to B therefore time at which auto will reach B = 11:30 +(50min)= 12:20
A car overtakes an auto at point A at 9 am. The car reaches pont B at 11 am and immediately turns back. It again meets the auto at point C at 11:30 am. At what time will the auto reach B?
(So am I, but I can at least be convinced by good logical reasons ;)
My reasoning - the speeds are in the ratio 5 : 3 (as the distances covered till their meeting are in that ratio) and so the times for a full lap also should be the same. The car took 2 hours or 120 min so the auto should take 200 min which is 3 hr 20 min which implies 12:20. regards scrabbler
A car overtakes an auto at point A at 9 am. The car reaches pont B at 11 am and immediately turns back. It again meets the auto at point C at 11:30 am. At what time will the auto reach B?
12.20 pm
Time taken by auto to travel from A to C = 2.5 hours Time taken by car to travel from A to B = 2 hours Time taken by car to travel from B to C = 0.5 hours So time taken by car to travel from A to C = 1.5 hours
So time taken by auto to travel from C to B = 2.5*0.5/1.5 = 50 minutes
A trader has bought some goods at a discount of 20% on the list price. He wants to mark them at such a price that even if he gives a discount of 20% on the marked price he still makes a profit of 25%. If he marks the goods by 20% points more than the proposed price and allows a discount of 50%, then what will be the profit / loss percentage? (1) 27.5% profit (2) 30% loss (3) 27.5% loss (4) 30% profit (5) None of these
a right angled triangle with longest side 80,construct 3 paths from the corner point opposite to the longest side such that these three paths divide the longest side into four equal segments.determine the sum of the lengths of three paths.
A trader has bought some goods at a discount of 20% on the list price. He wants to mark them atsuch a price that even if he gives a discount of 20% on the marked price he still makes a profit of25%. If he marks the goods by 20% points more than the proposed price and allows a discount of50%, then what will be the profit / loss percentage?(1) 27.5% profit (2) 30% loss (3) 27.5% loss (4) 30% profit (5) None of these
A trader has bought some goods at a discount of 20% on the list price. He wants to mark them atsuch a price that even if he gives a discount of 20% on the marked price he still makes a profit of25%. If he marks the goods by 20% points more than the proposed price and allows a discount of50%, then what will be the profit / loss percentage?(1) 27.5% profit (2) 30% loss (3) 27.5% loss (4) 30% profit (5) None of these
NOT?L.P at which he buys= 80(assume) S.P=100 (25% PROFIT)M.P=125NOW, 20% INCREASE IN M.P= 150Discount-= 50%= 75S.P=75, Hence loss of 5 rs.5/80*100= 6.25% loss
i also got 6.25 but oa they have given is 27.5 i think its there printing mistake