Official Quant thread for CAT 2013

@sujamait said:
1. 12. 0.85*0.2 = 0.17 ? ...........
I am getting weird contradictions :banghead: correct me please :p
P(c)= c fails and similarly for E
P(c)*P(e)=0.15
P(e)=0.75
Isme Kya galat hai? It contradicts the given probability for e failing alone.
Two litres of a mixture of spirit and water contains 12% water. This is added to 3 L of another mixture
of spirit and water containing 5% of water. Now, this mixture is mixed with 10 L mixture of
30% water. What is the percentage of water in final mixture?
(1) 22.6% (2) 20% (3) 28% (4) 25% (5) 26.2%
@sowmyanarayanan said:
When a trader buys goods at a price which is 10.5% less than the usual cost price and sells them at a price which is 20% less than the usual sale price, his profit decreases by an amount equal to 12.5% of the usual sale price. What is the usual percentage of profit made by the trader?
40 ?
@Cat.Aspirant123 said:
Two litres of a mixture of spirit and water contains 12% water. This is added to 3 L of another mixtureof spirit and water containing 5% of water. Now, this mixture is mixed with 10 L mixture of30% water. What is the percentage of water in final mixture?(1) 22.6% (2) 20% (3) 28% (4) 25% (5) 26.2%
1 ?
@Cat.Aspirant123 said:
Two litres of a mixture of spirit and water contains 12% water. This is added to 3 L of another mixtureof spirit and water containing 5% of water. Now, this mixture is mixed with 10 L mixture of30% water. What is the percentage of water in final mixture?(1) 22.6% (2) 20% (3) 28% (4) 25% (5) 26.2%
200 , 300 , 1000

24 + 15 + 300 = 339

1500*x% = 339
=> x = 22.6
@19rsb said:
An automobile car assembly system consists of two independent subsystems: chassis assembly (C) and engine assembly (E). Based on the prior maintenance data, the following probabilities are available. The probability that C fails is 0.2. The probability that both C and E fail together is 0.15. The probability that E fails alone is 0.15. The event €œC fails alone €? implies that C fails when E is working and vice versa.1)What is the probability that C fails when E has failed? 2)What is the probability that C fails alone?

It is independent
C fails alone=.15/.15=1
C fails alone=both C and E fail together/(E fails alone)



@Cat.Aspirant123 said:
Two litres of a mixture of spirit and water contains 12% water. This is added to 3 L of another mixtureof spirit and water containing 5% of water. Now, this mixture is mixed with 10 L mixture of30% water. What is the percentage of water in final mixture?(1) 22.6% (2) 20% (3) 28% (4) 25% (5) 26.2%
(0.24 + 0.15 + 3)/15 = 22.6%
@ankita14 said:
I am getting weird contradictions correct me please P(c)= c fails and similarly for EP(c)*P(e)=0.15P(e)=0.75Isme Kya galat hai? It contradicts the given probability for e failing alone.
office se nikale aur first Q he probility
in Q..there is diff in say..prob C fails and prob C fails alone.
in case of alone..it means the other one passes.
and when alone is not there it simply means what are the chances of C failing.{not concerned abt E}
So, I think you gotta take it into consideration.
@Cat.Aspirant123 said:
Two litres of a mixture of spirit and water contains 12% water. This is added to 3 L of another mixtureof spirit and water containing 5% of water. Now, this mixture is mixed with 10 L mixture of30% water. What is the percentage of water in final mixture?(1) 22.6% (2) 20% (3) 28% (4) 25% (5) 26.2%
2*12+3*5+10*30/(15)
339/15=22.6%
@Cat.Aspirant123 said:
Two litres of a mixture of spirit and water contains 12% water. This is added to 3 L of another mixtureof spirit and water containing 5% of water. Now, this mixture is mixed with 10 L mixture of30% water. What is the percentage of water in final mixture?(1) 22.6% (2) 20% (3) 28% (4) 25% (5) 26.2%
22.6%
@sujamait said:
office se nikale aur first Q he probility in Q..there is diff in say..prob C fails and prob C fails alone.in case of alone..it means the other one passes.and when alone is not there it simply means what are the chances of C failing.{not concerned abt E}So, I think you gotta take it into consideration.
Ha I know that. So 0.75 is probability that E fails(alone+not alone)
So p(e failing alone) = p(e failing)*p(c not failing)= 0.75*0.8 =0.6 :banghead:
@Cat.Aspirant123 said:
Two litres of a mixture of spirit and water contains 12% water. This is added to 3 L of another mixtureof spirit and water containing 5% of water. Now, this mixture is mixed with 10 L mixture of30% water. What is the percentage of water in final mixture?(1) 22.6% (2) 20% (3) 28% (4) 25% (5) 26.2%
22.6% got this one
@19rsb said:
An automobile car assembly system consists of two independent subsystems: chassis assembly (C) and engine assembly (E). Based on the prior maintenance data, the following probabilities are available. The probability that C fails is 0.2. The probability that both C and E fail together is 0.15. The probability that E fails alone is 0.15. The event €œC fails alone €? implies that C fails when E is working and vice versa.1)What is the probability that C fails when E has failed? 2)What is the probability that C fails alone?
1. 1/2
2. 1/17
@ankita14 said:
Ha I know that. So 0.75 is probability that E fails(alone+not alone) So p(e failing alone) = p(e failing)*p(c not failing)= 0.75*0.8 =0.6
okies,
but can we do this ? P(c)*P(e)=0.15 ? frm Q it seems they have some relation...not completely independent to me.and the condition which u have used is incase of independent events if I am rite !!
I am 2nd year CSE B.Tech student at IIT Ropar. I want to start preparing for CAT 2014.Could any of you please suggest good books for the same as I don't have much idea about CAT. I have heard that "Quantum CAT" is good for Quant, "RS Aggrawal" for reasoning (both logical and verbal), and "Word Power made easy by Norman Lewis" for vocab. building.
Still I am confused as reviews of RS Aggrawal are not much satisfying.
Also suggest some good book for DI.
Thanks..
An agricultural field is in the form of a rectangle of length 20 m and width 14 m. A pit 6 m long,
3 m wide and 2.5 m deep is dug in a corner of the field and the earth taken out of the pit is spread
uniformly over the remaining part of the field. In order to raise the height of the field by 30 cm how
much more soil is required?
(1) 29.8 m3 (2) 31 m3 (3) 30.2 m3 (4) 33.6 m3 (5) 78.6 m3
@sujamait said:
okies,but can we do this ? P(c)*P(e)=0.15 ? frm Q it seems they have some relation...not completely independent to me.and the condition which u have used is incase of independent events if I am rite !!
It says they are two independent subsystems :'(
@deedeedudu said:
1. 1/22. 1/17
appraoch ??
@ankita14 said:
It says they are two independent subsystems :'(
yeah but C fails...and C fails alone..are different anyways lOA dekhte hein, 19rsb post solution plz.

.....................
@Cat.Aspirant123 said:
An agricultural field is in the form of a rectangle of length 20 m and width 14 m. A pit 6 m long,3 m wide and 2.5 m deep is dug in a corner of the field and the earth taken out of the pit is spreaduniformly over the remaining part of the field. In order to raise the height of the field by 30 cm howmuch more soil is required?(1) 29.8 m3 (2) 31 m3 (3) 30.2 m3 (4) 33.6 m3 (5) 78.6 m3
78.6-45 = 33.6