@pratyush9811 said:Higest power of 6 that will divide the L.C.M. of 1st 200 natural numbers?a)4b)5c)6d)7
2^7 ---highest power
3^4---highest power
So, Ans should be 4
11. In a bombing attack there is 50% chance that anyone bomb will strike the target. Two direct hits are required to destroy the target. How many bombs must be dropped to give a 99% chance or better of completely destroying the target.
@vijay_chandola said:Clock has gained 15 minutes in 6 hours.Hence, it will gain 5 minutes in 2 hours.So, at 2 P.M.?
@ScareCrow28
kaise kia ?
@ScareCrow28 said:2^7 ---highest power3^4---highest powerSo, Ans should be 4
kaise kia ?@pratyush9811 said:Higest power of 6 that will divide the L.C.M. of 1st 200 natural numbers?a)4b)5c)6d)7
3^4
highest power 4
PS: cat mein aaya tha..
@SAHILVANSIL Please don't post the same question again and again..There's a limit to everyone's/everything's capacity. Have patience someone would provide the solution if he/she has to.
Don't get offended
@mailtoankit said:kaise hoga?
The clock gains 15 minutes in 30 hours (from -5 to +10)
At 12:00 noon it is 5 minutes behind, hence it has to cover 5 minutes to show the correct time
which it can do in 10 hours
12 noon + 10 hours = 22:00
@pratyush9811 : Please don't discuss the CAT 2012 questions. You are under NDA. If somebody reports, it might result in cancellation of your CAT'12 registration.
@AIM_IIM_2013 said:@ScareCrow28 kaise kia ?
LCM is all about the highest power of the prime no.
We have to find the powers of 6 here. 6=2*3
So, find the highest power of 2 and 3 in a number
Highest power of 2 in a number less than 200 is 7 (128)
and that of 3 is 4(81)
Hence the highest power of 6 will be 4
Q)At 7:00 AM,Ravish started from A towards B and Amit started from B towards A.At 9:00 AM they crossed each other and continued towards respective destination.if time taken by Ravish is 3 hours more than time taken by Amit. Find ratio of Ravish speed to Amit's speed?
Could someone explain it using V1/V2=sqrt(t1/t2)?
@vijay_chandola said:@pratyush9811 : Please don't discuss the CAT 2012 questions. You are under NDA. If somebody reports, it might result in cancellation of your CAT'12 registration.
I didnt know it is from CAT.. will remove 
thanks..
thanks..@bhatkushal said:Q)At 7:00 AM,Ravish started from A towards B and Amit started from B towards A.At 9:00 AM they crossed each other and continued towards respective destination.if time taken by Ravish is 3 hours more than time taken by Amit. Find ratio of Ravish speed to Amit's speed?Could someone explain it using V1/V2=sqrt(t1/t2)?
The funda behind the formula is:
1. if two person A and B start at the same time from different points and travel in opposite direction towards each other then, the ratio of speed of Sa/Sb = root(Tb/Ta) where Ta and Tb are the time take by A and B to reach the destination after they meet.
2. if two person A and B start at the different times from different points and travel in opposite direction towards each other then, the ratio of speed of Sa/Sb = root(Tb/Ta) where Ta and Tb are the time take by A and B to reach the meeting point.
@Torque024 said:A watch, which gains time uniformly, was 5 minutes behind the correct time when it showed 11:55 AM on Monday.It was 10 minutes ahead of the correct time when it showed 06:10 PM on the next day. When did the watch show the correct time?
In 30hrs incorrect clock has travelled 15 mins ahead
It'll gain 5 mins in 10 hrs
Hence correct time is shown at 10pm
It'll gain 5 mins in 10 hrs
Hence correct time is shown at 10pm
@bhatkushal said:Q)At 7:00 AM,Ravish started from A towards B and Amit started from B towards A.At 9:00 AM they crossed each other and continued towards respective destination.if time taken by Ravish is 3 hours more than time taken by Amit. Find ratio of Ravish speed to Amit's speed?Could someone explain it using V1/V2=sqrt(t1/t2)?
1/2
@sowmyanarayanan said:The funda behind the formula is:1. if two person A and B start at the same timefrom different points and travel in opposite direction towards each other then, the ratio of speed of Sa/Sb = root(Tb/Ta) where Ta and Tb are the time take by A and B to reach the destination after they meet.2. if two person A and B start at the different times from different points and travel in opposite direction towards each other then, the ratio of speed of Sa/Sb = root(Tb/Ta) where Ta and Tb are the time take by A and B to reach the meeting point.
How can I use the 1) scenario here