If N is a seven digit natural number such that when it is added to the sum of its own digits the result is the least eight digit number. What is the remainder when N is divided by 9?
@SAHILVANSIL said:1. A bag contains 6 white and 9 black balls. Three drawings of 1 ball each are made such that (i) the balls are replaced before the next drawing (ii) balls are not replaced before the next drawing. Find the probability that all the black balls are drawn in each case.
i) Drawing first ball, drawing 2nd ball and drawing 3rd ball all are independent events
So, probability = (9/15)(9/15)(9/15) = 27/125
ii) Drawing first ball, drawing 2nd ball and drawing 3rd ball all are independent events
So, probability = (9/15)(8/14)(7/13) = 12/65
So, probability = (9/15)(8/14)(7/13) = 12/65
@chillfactor Yup, The same doubt came up while solving it too. But, I didn't assume that the P(lying) is equiprobable, and hence went ahead with the simpler approach. But yes, if the man lies about 6 in an equiprobable way, it should be 3/4
@SAHILVANSIL said:1. A bag contains 6 white and 9 black balls. Three drawings of 1 ball each are made such that (i) the balls are replaced before the next drawing (ii) balls are not replaced before the next drawing. Find the probability that all the black balls are drawn in each case.
1) 9/15*9/15*9/15=27/125
2) C(9, 3)/C(15, 3)=12/65
@sowmyanarayanan said:If N is a seven digit natural number such that when it is added to the sum of its own digits the result is the least eight digit number. What is the remainder when N is divided by 9?
N + S(N) = 10000000
10000000 is of form 9k + 1
10000000 is of form 9k + 1
Suppose N is of form 9a + r, the S(N) will also be of form 9b + r, where r can be anything from 0 to 8
9a + r + 9b + r = 9k + 1
2r = 9c + 1
So, only possible value of r is 5
Remainder when N is divided by 9 is 5
2. Under certain conditions, the probability of hitting the target is only 0.5. Find the probability of destroying the target if 5 trials are made.
@sowmyanarayanan said:If N is a seven digit natural number such that when it is added to the sum of its own digits the result is the least eight digit number. What is the remainder when N is divided by 9?
number =9999950
sum=10000000
9999950 mod 9=5 mod 9
@SAHILVANSIL said:2. Under certain conditions, the probability of hitting the target is only 0.5. Find the probability of destroying the target if 5 trials are made.
5/32 hai kya answer???
@sowmyanarayanan said:If N is a seven digit natural number such that when it is added to the sum of its own digits the result is the least eight digit number. What is the remainder when N is divided by 9?
Remainder when no is divided by 9 is same as when the sum of its digits is divided by 9.
Let no be 9k+r
Now, (9k+r)+(9p+r) = 10000000
9(k+p) + 2r= 10000000
2r = 10000000-9(k+p) = 9(1111111-k-p) +1
From here r has to be 5..
r=5
Aarav, who lived on Earth, went to Mars and met Jadoo, Badoo, Kadoo and Ladoo there. All four of them, who were residents of Mars, had some chocolates with them. On the arrival of Aarav, they became so happy that all of them gave away all their chocolates to Aarav. The number of chocolates with Jadoo, Badoo, Kadoo and Ladoo were 15, 40, k01 and 122 respectively as per the number system prevalent on their planet. They also told Aarav that the number of chocolates they had was in an arithmetic progression in the number system used on their planet. Aarav was an expert in number systems. If Aarav counted the chocolates that he received, which of the following cannot represent the number of chocolates that he counted?
1)122
2)233
3)442
4)278
5)None of these
1)122
2)233
3)442
4)278
5)None of these
@SAHILVANSIL said:2. Under certain conditions, the probability of hitting the target is only 0.5. Find the probability of destroying the target if 5 trials are made.
1/2+1/2*1/2+1/2*1/2*1/2+1/2*1/2*1/2*1/2+1/2*1/2*1/2*1/2*1/2
=1/2{1-(1/2)^5}/(1-1/2)
=31/32
@SAHILVANSIL said:2. Under certain conditions, the probability of hitting the target is only 0.5. Find the probability of destroying the target if 5 trials are made.
31/32
@sowmyanarayanan said:If N is a seven digit natural number such that when it is added to the sum of its own digits the result is the least eight digit number. What is the remainder when N is divided by 9?
Let N be the number
N+SUMOFD=10000000
Nmod9+SumOfDmod9=1
Nmod9+Nmod9=-8
Nmod9=-4=5
@chillfactor sir aise kia ja sakta hai?
N+SUMOFD=10000000
Nmod9+SumOfDmod9=1
Nmod9+Nmod9=-8
Nmod9=-4=5
@chillfactor sir aise kia ja sakta hai?
3.Find the chance of throwing head or tail alternately in 3 successive tossing of a coin.
@SAHILVANSIL said:3.Find the chance of throwing head or tail alternately in 3 successive tossing of a coin.
HTH or THT
2(1/2)^3
2(1/2)^3
@SAHILVANSIL said:3.Find the chance of throwing head or tail alternately in 3 successive tossing of a coin.
1/4?
@SAHILVANSIL said:2. Under certain conditions, the probability of hitting the target is only 0.5. Find the probability of destroying the target if 5 trials are made.
1-(1/2)^5 = 31/32
@SAHILVANSIL said:3.Find the chance of throwing head or tail alternately in 3 successive tossing of a coin.
2*1/2*1/2*1/2= 1/4
