You are sitting in a large waiting room, waiting for a final job interview with a reputed software giant. In the room with you are a large number of other candidates from all over India. The interviewer says that the first person to be interviewed, who's birthday is today, will be guaranteed a job. But only the first person. It is your birthday today! If it is your father's birthday in one week's time, how many people can be interviewed before you, before your probability of getting the job falls below 90%?
@nick_baba so people interviewed b4 me shudnt have their b'days 2day ryt . prob.for each --> 364/365 so v have to find (364/365)^n >= .90 ; n is maximum . ryt ?? here n comes around 38
@nick_babaso people interviewed b4 me shudnt have their b'days 2day ryt .prob.for each --> 364/365so v have to find (364/365)^n >= .90 ; n is maximum . ryt ??here n comes around 38
" so people interviewed b4 me shudnt have their b'days 2day"..but this condition is valid even if the first person is not having b'day but each and every one who follows, has.!!.
@nick_babaso people interviewed b4 me shudnt have their b'days 2day ryt .prob.for each --> 364/365so v have to find (364/365)^n >= .90 ; n is maximum . ryt ??here n comes around 38
If there is no person before him having b'day today, then his probabilty is 1 na.
If there is no person before him having b'day today, then his probabilty is 1 na.
yup. but the question is how many people can be interviewed before probability falls below .9 . as you said if he is first -->1 ; if second then probability decreases .and goes on decreasin as no.of people before him increases.
@nick_babaso people interviewed b4 me shudnt have their b'days 2day ryt .prob.for each --> 364/365so v have to find (364/365)^n >= .90 ; n is maximum . ryt ??here n comes around 38
" so people interviewed b4 me shudnt have their b'days 2day"..but this condition is valid even if the first person is not having b'day but each and every one who follows, has.!!.lets wait what others have to say.
You are sitting in a large waiting room, waiting for a final job interview with a reputed software giant. In the room with you are a large number of other candidates from all over India. The interviewer says that the first person to be interviewed, who's birthday is today, will be guaranteed a job. But only the first person. It is your birthday today! If it is your father's birthday in one week's time, how many people can be interviewed before you, before your probability of getting the job falls below 90%?@anytomdickandhary @naga25french @deedeedudu @krum @vijay_chandola @ScareCrow28@Zedai @scrabbler @techsurge @chillfactor @Brooklyn @sujamait @soumitrabengeri @rkshtsurana @Estallar12 P.S: I don't have an OA to this..so do post your answers with approaches.
What is the significance of the father's birthday here?
@nick_babaso people interviewed b4 me shudnt have their b'days 2day ryt .prob.for each --> 364/365so v have to find (364/365)^n >= .90 ; n is maximum . ryt ??here n comes around 38
this makes perfect sense I don't understand your argument here but you don't know whether the person before you has his birthday todayPS: I don't know the significance of my father's birthday here
what i'm saying is that even if the candidates before you, except the first one, have b'day but are not the first ones to be interviewed, what change would it make..???..i mean then in that case the prob of 364/365 may or may not hold.!!
what i'm saying is that even if the candidates before you, except the first one, have b'day but are not the first ones to be interviewed, what change would it make..???..i mean then in that case the prob of 364/365 may or may not hold.!!
no . i think , what the question means is that whoever has their b'day today and the first one to be interviewed(among people having b'day today) will get hired . if this is not the case , the problem is pretty weird as we dont have the probability of others getting hired when its not their b'day .
what i'm saying is that even if the candidates before you, except the first one, have b'day but are not the first ones to be interviewed, what change would it make..???..i mean then in that case the prob of 364/365 may or may not hold.!!
See here we are banking on the fact that no candidate before me has his birthday today. If any one candidate who goes before me has his birthday today then that case is not in my favour. So that case is not considered. For me to be the first candidate who has his birthday today, ALL the candidates who go before me should have their birthdays on other days.
