@Ibanez said:no
11/7 then? 😲
have you solved it?? I cudn't find any easy way!
have you solved it?? I cudn't find any easy way!
@hanushanand said:11/7 then? have you solved it?? I cudn't find any easy way!
11/7 correct. I tried differentiating and equating to 0 but getting weird cubic equation. :S
solution has a very simple logic though.
solution has a very simple logic though.
@hanushanand said:Any else you got?
Function f(n) is defined on the set of intergers.
f(n)= n-3 if n>=1000
f(f(n+5)) if n
find f(84)
1. 100
2. 84
3. 998
4. 997
f(n)= n-3 if n>=1000
f(f(n+5)) if n
find f(84)
1. 100
2. 84
3. 998
4. 997
@Ibanez said:Function f(n) is defined on the set of intergers. f(n)= n-3 if n>=1000 f(f(n+5)) if nfind f(84)1. 1002. 843. 9984. 997
Solved it few weeks back, it is 997 right ?
For n
f(even) = 997
f(odd) = 998
@Ibanez said:Function f(n) is defined on the set of intergers. f(n)= n-3 if n>=1000 f(f(n+5)) if n
Ye kya hai?? 
@soham2208 said:Solved it few weeks back, it is 997 right ?For n f(even) = 997f(odd) = 998
qns daalo! 
@Ibanez said:Ok ill post a ques then,Consider points A(1,-3) and B(5,2). Let P be a point on y=x. Find co-ordinates of P for which |AP+PB| is minimum1. (10/9,10/9)2. (11/7,11/7)3. (11/9,11/9)4. (13/7,13/7)
11/7, 11/7
@Ibanez said:11/7 correct. I tried differentiating and equating to 0 but getting weird cubic equation. :Ssolution has a very simple logic though.
Both points are on the same side of line.
So, take a mirror image of any one point wrt y=x.
And then equate both slopes.
Mirror image point of 5, 2 =2, 5
so, (x-2)/(x-5)=(x-1)/(x+3)
==>(x-2)*(x+3)=(x-1)(x-5)
==> x^2+x-6=x^2-6x+5
==> x=11/7
so coordinates of the point =11/7
@vijay_chandola said:Both points are on the same side of line.
Sir, What would we do, if they are on different sides? If there is any thing we can do!
If there is any thing we can do! @hanushanand said:Sir, What would we do, if they are on different sides?
Then the straight line connecting those two points would meet the given line at a point P 😃 and so answer will be straightaway the distance between those two points. :|
@hanushanand said:Sir, What would we do, if they are on different sides?
The point is, We have to make it on different side.
if the two points in the given question are on different side of the line x=y then we would simply join the points and point of intersection with line y=x would give the coordinates of P. But in this case both the points are on same side of x=y. So we take reflection of point A about line x=y (In order to find the a similar distant point on different side)
@soham2208 said:Then the straight line connecting those two points would meet the given line at a point P and so answer will be straightaway the distance between those two points.
Ohh! Sorry! I went beyond the question, linking it with some fixed point!
Sorry! I went beyond the question, linking it with some fixed point!
An easy one :
The product of two integers is 25, then the minimum possible sum is
@grkkrg said:An easy one :The product of two integers is 25, then the minimum possible sum is
-26 
@grkkrg said:An easy one :The product of two integers is 25, then the minimum possible sum is
-25*-1 = 25
sum = -26