@chillfactor said:
25?
@gupanki2 said:Kunal has only 25 paise and 50 paise coins with him. The total amount in 50 paise denomination is Rs 4 more than the total amount in 25 paise denomination. The no. of 25 paise coins is 20 more than the number of 50 paise coins. What s the total amount with kunal?
@rubikmath said:25
@mailtoankit said:25?
@chillfactor said:Yup, 25 is correct.Three cases:-i) No diagonal movement, three east steps and 2 northC(5, 2) = 10 waysii) One diagonal movement, so 1 NE step, 2 east step and 1 north step4!/(1!1!2!) = 12 waysiii) Two diagonal movements, so 2 NE steps, 1 east step3!/(1!2!) = 3 waysTotal = 25Another question in the attachement
@grkkrg said:6!/2! = 360 PS: Please check the question again. I don't think the question is correct. From the options I think the question should be 6999999>n>6000000. (I may be wrong though)

@chillfactor said:Yup, 25 is correct.Three cases:-i) No diagonal movement, three east steps and 2 northC(5, 2) = 10 waysii) One diagonal movement, so 1 NE step, 2 east step and 1 north step4!/(1!1!2!) = 12 waysiii) Two diagonal movements, so 2 NE steps, 1 east step3!/(1!2!) = 3 waysTotal = 25Another question in the attachement
@chillfactor said:Yup, 25 is correct.Three cases:-i) No diagonal movement, three east steps and 2 northC(5, 2) = 10 waysii) One diagonal movement, so 1 NE step, 2 east step and 1 north step4!/(1!1!2!) = 12 waysiii) Two diagonal movements, so 2 NE steps, 1 east step3!/(1!2!) = 3 waysTotal = 25Another question in the attachement
@chillfactor said:Yup, 25 is correct.Three cases:-i) No diagonal movement, three east steps and 2 northC(5, 2) = 10 waysii) One diagonal movement, so 1 NE step, 2 east step and 1 north step4!/(1!1!2!) = 12 waysiii) Two diagonal movements, so 2 NE steps, 1 east step3!/(1!2!) = 3 waysTotal = 25Another question in the attachement
2- [ rt(640522209)/rt(3600840049)]? 
0.6663039
0.666029
0.666009
none of the above
@sonamaries7 said:OA IS 540..it seemed weird to me as well, hence posted..IIFT qs, it is
@maddy2807 said:it is an IIFT question and one digit '4' is missing in it.
@kingsleyx said:A simple one :A couple has two children. The probability that the first child is a girl, is 50%. The probability that the second child is a girl, is also 50%. They tell you that they have a daughter. What is the probability that their other child is also a girl ?
@kingsleyx said:A simple one :A couple has two children. The probability that the first child is a girl, is 50%. The probability that the second child is a girl, is also 50%. They tell you that they have a daughter. What is the probability that their other child is also a girl ?
@kingsleyx said:A simple one :A couple has two children. The probability that the first child is a girl, is 50%. The probability that the second child is a girl, is also 50%. They tell you that they have a daughter. What is the probability that their other child is also a girl ?
@grkkrg said:Possible casesDD -> prob. = 1/2SD -> prob. = 1/2DS -> prob. = 1/2Required probability = (1/2)/(3/2) = 1/3@Brooklyn
@pankaj1988 said:DD=>1/2*1/2 =1/4 ? same for others ...isn't? Though ans wont change