Official Quant thread for CAT 2013

@sujamait said:
the sum of 1st 7 terms of1+4+18+96+600 +..
(n-1)! n^2 --> 40319???
@sujamait said:
the sum of 1st 7 terms of1+4+18+96+600 +..
40319?
@sauravd2001 said:
@19rsb bhai sahi hai m so tard n stupid i canttell u i took it out right upto 80 match in first round later i didnot count the last 3 matches ohh man katta ho gaya itni mehnat ke baad :/
koi nhin guru... agr kal bachna hai toh aaj thodi bahut galti toh hogi hi ........its bettr 2 b safe dan sry......
@19rsb yupp but seriously bahut bura laga iska solution dekh ke .......:( pura yahi kiya aur poora question ni padha
:( koi ni n thanx for that piece of advice
@kingsleyx said:
(n-1)! n^2 --> 40319???
option mein hai..general term ka kya jugad mara hai ?
@sujamait bhai ne itna tagda approach diya aur tu use jugad kah raha hai 😛 aar paar ka hi queston tha
@sauravd2001 said:
@sujamait bhai ne itna tagda approach diya aur tu use jugad kah raha hai aar paar ka hi queston tha
arey bhai jugad matlab approach...

2 sides of a triangle are 2^1/3 and 3+rt(5).which can be the length of third side.
20^1/3
3rt6
rt12
2rt8
@sujamait 2 sides hue 1.25 aur 5.25 something so
third side should be smaller than 6.5 and greater than 4
nd option bane 2.66,7.3,3.4,8.4 toh koi option fit ni baitha
none of these :P
@sauravd2001 said:
@sujamait 2 sides hue 1.25 aur 5.25 something so third side should be smaller than 6.5 and greater than 4 nd option bane 2.66,7.3,3.4,8.4 toh koi option fit ni baitha none of these
me too gettin d same......
@sujamait said:
arey bhai jugad matlab approach...2 sides of a triangle are 2^1/3 and 3+rt(5).which can be the length of third side.20^1/33rt6rt122rt18
None of these. If option D) is just rt18 , then it wud be the answer !!
@19rsb said:
me too gettin d same......
@kingsleyx said:
None of these. If option D) is just rt18 , then it wud be the answer !!
sorry option D is 2rt8..and that fits.
there are 6 couples in a tennies tournament.the 6 men and 6 women have to play mixed double games among themselves such that a team is never a couple.Find the maximum number of mixed double matches possible with diffrent combination of people.
How to Prepare for Quantitative Aptitude for the CAT by arun sharma vs Quantitative Aptitude Quantum CAT by Sarvesh K Verma. which is good in terms of concept explanation? experts pls help
@sujamait said:
there are 6 couples in a tennies tournament.the 6 men and 6 women have to play mixed double games among themselves such that a team is never a couple.Find the maximum number of mixed double matches possible with diffrent combination of people.
Select 2 guys (X,Y)-> C(6,2)
Select 2 females (None being wives of either of X,Y) -> C(4,2)
Total ways = 15*6* 2! = 180

There are more cases where 1 or more husbands plays against his wife
Case of 1 couple in a game -> C(6,2) * C(4,1) * 2 = 15 * 8 = 120
Case of 2 couples in a game -> C(6,2) * 1 = 15

Total ways = 180 + 120 + 15 = 315
@Angadbir said:
Select 2 guys (X,Y)-> C(6,2)Select 2 females (None being wives of either of X,Y) -> C(4,2)Total ways = 15*6* 2! = 180There are more cases where 1 or more husbands plays against his wifeCase of 1 couple in a game -> C(6,2) * C(4,1) * 2 = 15 * 8 = 120Case of 2 couples in a game -> C(6,2) * 1 = 15Total ways = 180 + 120 + 15 = 315
OA is 765
DP
a spherical gulab jamun contains 30% sugar syrup by volume and 45% sugarsyrup by mass.A gulab jamun weighing 100g by mass is 200 cc by volume.find the radius of each gulab jamun ,which has 26.325 gm of sugar syrup in it.

Probability of a team gng to semis if both ajay and varun played is 0.8, if only ajay played is 0.52, if only varun played is 0.62 and if none of them plays is 0.45. The prob that ajay playing is 0.88. what should be the prob of varun playing if the prob of team making to semis is 0.63 ?
@sujamait said:
there are 6 couples in a tennis tournament.the 6 men and 6 women have to play mixed double games among themselves such that a team is never a couple.Find the maximum number of mixed double matches possible with different combination of people.
C(6, 2)*C(6, 2)*2 - C(6, 2) - C(6, 1)*C(5, 1)*C(4, 1)
= 450 - 15 - 120
= 315

@sujamait C(6, 2)*C(6, 2)*2 se zyaada kaise ho sakta hai answer
@chillfactor said:
C(6, 2)*C(6, 2)*2 - C(6, 2) - C(6, 1)*C(5, 1)*C(4, 1) = 450 - 15 - 120= 315@sujamait C(6, 2)*C(6, 2)*2 se zyaada kaise ho sakta hai answer
sir can u explain a lil more???
@sujamait said:
a spherical gulab jamun contains 30% sugar syrup by volume and 45% sugarsyrup by mass.A gulab jamun weighing 100g by mass is 200 cc by volume.find the radius of each gulab jamun ,which has 26.325 gm of sugar syrup in it.
3.xx ?