@maddy2807 option b?
@19rsb said:Two cards are drawn at random from a deck of cards.What is the probability that both the cards are of same number or honour?
1/17
@seetharam7 said:A manufacturing unit can produce one or more of the commodities A, B and C. If x units of A, y units of B and z units of C are produced then the cost of production is x + y + z (in Rupees) while the net profit equals f(x, y, z) (in Rupees). A total amount of Rs 30000 is available to cover the cost of production. If f(x, y, z) = x + 2y + 3z, then the maximum possible profit (in Rupees) is ??Options are 60000,70000,80000,90000, 100000
90000?
@seetharam7 said:A manufacturing unit can produce one or more of the commodities A, B and C. If x units of A, y units of B and z units of C are produced then the cost of production is x + y + z (in Rupees) while the net profit equals f(x, y, z) (in Rupees). A total amount of Rs 30000 is available to cover the cost of production. If f(x, y, z) = x + 2y + 3z, then the maximum possible profit (in Rupees) is ??Options are 60000,70000,80000,90000, 100000
90000?
@sauravd2001 said:@seetharam7 90000
Ya. Correct. Can you post the method ? (x,y and z have to be positive integers )
@maddy2807 said:90000?
@19rsb said:90000?
Correct. Can you please post the method in case it's mentioned x,y and z are +ve integers. :)
@seetharam7 said:Ya. Correct. Can you post the method ? (x,y and z have to be positive integers )
directly take z=30000. x,y=0 for max
John has to paint a wall with seven horizontal stripes. He only has enough paint for four red stripes, four blue stripes, and four yellow stripes. If he can use at most two colors, how many different ways can he paint the wall?
(A) 420
(B) 210
(C) 84
(D) 35
(E) 7
no OA
(A) 420
(B) 210
(C) 84
(D) 35
(E) 7
no OA
@maddy2807 kara toh tha woh __ OPO __QOPQ __ RQPO __ POR __ O iska
yaar pahle b lag raha tha ab none of these hi hona chahiye
dekh
qop opq opq orq aur reapeat hona chhaiye toh por por lekin same alphabest ni hai toh non eof these?
@rubikmath said:John has to paint a wall with seven horizontal stripes. He only has enough paint for four red stripes, four blue stripes, and four yellow stripes. If he can use at most two colors, how many different ways can he paint the wall?(A) 420 (B) 210 (C) 84 (D) 35 (E) 7no OA
We have 3 colors -
Now, two among them can be selected in 3C2 ways = 3.
Now those two can be arranged as 4,3 or 3,4 (4 colors of one paint and then 3 other colors or vice versa)
Now those two can be arranged as 4,3 or 3,4 (4 colors of one paint and then 3 other colors or vice versa)
Hence, 2 ways.
Now, for Arrangements : 7!/(3!*4!) = 35 ways.
Total = 3*2*35 = 210 ways?
Now, for Arrangements : 7!/(3!*4!) = 35 ways.
Total = 3*2*35 = 210 ways?
@rubikmath said:John has to paint a wall with seven horizontal stripes. He only has enough paint for four red stripes, four blue stripes, and four yellow stripes. If he can use at most two colors, how many different ways can he paint the wall?(A) 420 (B) 210 (C) 84 (D) 35 (E) 7no OA
210?
@soumitrabengeri said:We have 3 colors - Now, two among them can be selected in 3C2 ways = 3.Now those two can be arranged as 4,3 or 3,4 (4 colors of one paint and then 3 other colors or vice versa) Hence, 2 ways.Now, for Arrangements : 7!/(3!*4!) = 35 ways.Total = 3*2*35 = 210 ways?
think so.thats wat i got too 
@rubikmath said:John has to paint a wall with seven horizontal stripes. He only has enough paint for four red stripes, four blue stripes, and four yellow stripes. If he can use at most two colors, how many different ways can he paint the wall?(A) 420 (B) 210 (C) 84 (D) 35 (E) 7no OA
210
a min of two colors wud be needed.
choose two colors. 3C2=3
Now choose the color for 3 strips= 2C1=2
total no of wys= 2C1*3C2* 7!/4!*3!= 210
correct me if wrng?
@maddy2807 said:directly take z=30000. x,y=0 for max
Ok. In case the question is, for what +ve values of x,y and z does the function give max value ?
@seetharam7 said:Ok. In case the question is, for what +ve values of x,y and z does the function give max value ?
take x=y=1 and z= 29998
will be the max.
@soumitrabengeri bhai good one i was doing something out of this owrld for this thinking of
7 strips so 4,3 ka pair and 4 strips in 4! ways and 3 in 3! ways so 144 ways with one strip and pata ni kahan pahunch agay answeer but ur approach is ryt