Official Quant thread for CAT 2013

@grkkrg said:
There were 4 parcels all of whose weights were integers (in kg). The weights of all the possible pairsof parcels were noted down and amongst these the distinct values observed were 94 kg, 97 kg,101 kg and 104 kg. Which of the following can be the weight of one of the parcels?(a) 40 kg (b) 45 kg (c) 48 kg (d) 53 kg
3* sigma(weights)=94+97+101+104=396
=> sigma (weights)=132

==> weights will be, 28(132-104), 31(132-101), 35(132-97), 38(132-94)

kyagalati ho rahi @Brooklyn bhai :neutral: ?

Got it, took 3 at a time
@grkkrg said:
There were 4 parcels all of whose weights were integers (in kg). The weights of all the possible pairsof parcels were noted down and amongst these the distinct values observed were 94 kg, 97 kg,101 kg and 104 kg. Which of the following can be the weight of one of the parcels?(a) 40 kg (b) 45 kg (c) 48 kg (d) 53 kg
Let weights be a, b, c and d
Equations CAN be formed like following:
a+b = 104
a+c = 101
a+d = 97
c+d = 94 ( I tried using b+c , b+d but results were non-integers)
From above equations.. a=b=52, c=49 and d=45
Hence answer is: b) 45
@vijay_chandola said:
3* sigma(weights)=94+97+101+104=396=> sigma (weights)=132==> weights will be, 28(132-104), 31(132-101), 35(132-97), 38(132-94)kyagalati ho rahi @Brooklyn bhai ?
You can't say for sure that the weights reeated 3 times...Only distinct values were noted.. Had all the possible pairsd been added then it would have been correct.. what say?
@grkkrg said:
Raj invests Rs.2400 partly in 3% stock at 75 and partly in 4% stock at 96. If the total income from both is Rs.97.50, find the sum invested in each.(a) Rs.1500 in 3%, Rs.900 in 4% (b) Rs.900 in 3%, Rs.1500 in 4%(c) Rs.1200 in each (d) Rs.2000 in 3%, Rs.400 in 4%
assuming face value of stock = 100.

(x/75)*3 + (2400-x)*4/96 = 97.5
=>x/25 +(2400-x)/24 = 97.5
=>100 + (x/25 - x/24) = 97.5
=>2.5 = x/600
=>x=1500

hence 1500 in 3% stock and 900 in 4%

ATDH.
@ScareCrow28 said:
You can't say for sure that the weights reeated 3 times...Only distinct values were noted.. Had all the possible pairsd been added then it would have been correct.. what say?
Didn't read the question properly. I took three weights at a time :splat:
A,B,C started to reach varanasi from delhi 300 km away they have only one bike which travel at a speed of 60 km/hr and every one can walk at a speed of 15 km/hr condition is every one has to reach at the same time and only two person can travel on the bike at the same time. wat is the minimum time required for them to reach there.
P.S. All of them start at same time and onlyA can drive the bike
P.P.S.. : Question was posted yesterday..but i Couldn't reach to the answer matching with OA

JAAGO GRAHAK JAAGO

PPPS : I Got the answer now
Find remainder when 25! is divided by 10^7?
@19rsb said:
Find remainder when 25! is divided by 10^7?
4000000??

@19rsb said:
Find remainder when 25! is divided by 10^7?
Highest power of 10 in 25! = 6
So find the last non zero digit in 25!
25 = 5(5) + 0
R(25) = 2^5 * R(5!) * R(0!)
= 2 * 2 * 1
= 4

EDITED:
So remainder = 4 * 10^6 = 4000000
@Brooklyn said:
4000000??
@grkkrg said:
Highest power of 10 in 25! = 6So find the last non zero digit in 25!25 = 5(5) + 0R(25) = 2^5 * R(5!) * R(0!)= 2 * 2 * 1= 4
http://www.wolframalpha.com/input/?i=25!%20mod%2010%5E7&t;=crmtb01
@19rsb said:
Find remainder when 25! is divided by 10^7?
4??
@19rsb said:
Find remainder when 25! is divided by 10^7?
4*10^6

4

For last non-zero digit refer :http://quantomania.blogspot.ch/

Three squares are chosen at random on a chessboard. Find the probability that they lie in a diagonal line.
@19rsb said:
Find remainder when 25! is divided by 10^7?
4000000
@LeoN88 said:
4For last non-zero digit refer :http://quantomania.blogspot.ch/
http://quantomania.blogspot.in/2011/08/last-non-zero-digit-of-factorial.html (Same thing diff URL checked just now)
I too got the formula from here :P
@LeoN88 said:
4For last non-zero digit refer :http://quantomania.blogspot.ch/
4*10^6
@Brooklyn said:
4*10^6
Yes, even I have checked the same on WA but 25! gives ______4000000, all the zeroes will get cancelled..4 will be left behind..I am a bit confused here !
@LeoN88 said:
Yes, even I have checked the same on WA but 25! gives ______4000000, all the zeroes will get cancelled..4 will be left behind..I am a bit confused here !
We are not dividing by 10^7..We are just finding the remainder
2500 mod 1000 = 500 and not 5 ..I hope you get the point :)
@LeoN88 said:
Yes, even I have checked the same on WA but 25! gives ______4000000, all the zeroes will get cancelled..4 will be left behind..I am a bit confused here !
nop you are not dividing bt finding remainder,

40 mod 10 = 0

40 /10 = 4 hope you get it