Official Quant thread for CAT 2013

MBA CAT 2024
6201
In how many different ways three persons A, B, C having 6, 7 and 8 one rupee coins respectively can donate Rs.10 collectively.
6202
@pankaj1988 said:
OA -55/100=11/20...Condition satisfied for x=1, 2 and x>=48
After getting the desired result, mistake in counting :banghead:
6203
@akansh_1 thanks a lot for the detailed solution 😁

6204
@pankaj1988 said:
In how many different ways three persons A, B, C having 6, 7 and 8 one rupee coins respectively can donate Rs.10 collectively.
47?
6205
@pankaj1988 said:
In how many different ways three persons A, B, C having 6, 7 and 8 one rupee coins respectively can donate Rs.10 collectively.
Is it 5+4+3 = 12 ways?
6206
@pankaj1988 said:
In how many different ways three persons A, B, C having 6, 7 and 8 one rupee coins respectively can donate Rs.10 collectively.
47 ?
6207
@techsurge said:
The quadratic equation ax^2-6x+b has equal and real roots. If a and b are natural numbers. how many ordered pairs of (a,b) are possible?0123
3?
6208
@pankaj1988 bhai OA?
6209
@pankaj1988 said:
In how many different ways three persons A, B, C having 6, 7 and 8 one rupee coins respectively can donate Rs.10 collectively.
46?
6210
@mailtoankit said:
46?
@maddy2807 said:
@pankaj1988 bhai OA?
@rubikmath said:
47 ?
@akansh_1 said:
Is it 5+4+3 = 12 ways?
OA-47...bhai approach bhi bata dijiye..
6211
In an examination, the maximum marks for each of the three papers are 50 each. Maximum marks for the fourth paper is 100. Find the number of ways in which the candidate can score 60% marks in the aggregate.
6212
@pankaj1988 said:
OA-47...bhai approach bhi bata dijiye..
A+B+C= 10
no of ways= 12C2= 66
deleting cases when A= 7 to 10
A'+7+B+C=10
A'+B+C=3
no of ways= 10
similarly, for B and C it will be 6 and 3 ways.
66-10-6-3=47
6213
@pankaj1988 said:
OA-47...bhai approach bhi bata dijiye..
a+b+c=10
12c2=66

when a>6
5c2=10
when b>7
4c2=6
when c>8
3c2=3

66-10-6-3=47
6214
@pankaj1988 said:
In an examination, the maximum marks for each of the three papers are 50 each. Maximum marks for the fourth paper is 100. Find the number of ways in which the candidate can score 60% marks in the aggregate.
4?
6215
@pankaj1988 said:
In an examination, the maximum marks for each of the three papers are 50 each. Maximum marks for the fourth paper is 100. Find the number of ways in which the candidate can score 60% marks in the aggregate.
153C3-3*102C3-52C3 ?
6216
@pankaj1988 said:
In an examination, the maximum marks for each of the three papers are 50 each. Maximum marks for the fourth paper is 100. Find the number of ways in which the candidate can score 60% marks in the aggregate.
a+b+c+d=150
153c3

when d>100
52c3

when a>50
102c3

but this includes cases when b,c>50
b+c+db+c+d+e=99
b>50
51c3


153c3-52c3-3*(102c3-51c3)
=585276-22100-3*(171700-20825)
=110551

6217
@rubikmath said:
153C3-3*102C3-52C3 ?
3*102C3 includes cases when others are >50
6218
@maddy2807 said:
4?
@rubikmath said:
153C3-3*102C3-52C3 ?
Bhai log OA nhi hai....
6219
@krum said:
3*102C3 includes cases when others are >50
got it
6220
@krum said:
a+b+c+d=150153c3when d>10052c3when a>50102c3but this includes cases when b,c>50b+c+db+c+d+e=99b>5051c3153c3-52c3-3*(102c3-51c3)=585276-22100-3*(171700-20825)=110551
shudnt it be 2*51C3 , since b or c > 50 ??