@sumit99 said:How many different values N can take if,
N = ± 8 ± 16 ± 24 ± 32 ± 40 ± 48 ± 56 ± 64 ± 72 ± 80
a) 56
b) 111
c) 881
d) 1024
bhai ek baat batao ye - ka sign + ke neeche kaise post kiya ???
@sumit99 said:How many different values N can take if,N = ± 8 ± 16 ± 24 ± 32 ± 40 ± 48 ± 56 ± 64 ± 72 ± 80a) 56b) 111c) 881d) 1024
56 hai kya?
@rubikmath said:a.56
take 8 out as common --> 8(+-1 till +-10)
can form only 56 terms
nahi smajh aaya
thodo vistaar mein please 
A music class has a group of 5 students. Three subgroups, A,B,C are formed by choosing the students at random from the main group. Some students can be put in two or more groups as well. What is the probability that no student is common in all the three sub groups ?
OA: (7/8)^5
@techsurge said:bhai ek baat batao ye - ka sign + ke neeche kaise post kiya ???
copy kiya tha question fb se
@techsurge said:nahi smajh aaya thodo vistaar mein please
from 1 to 10 we have 10 terms --> 5 odd , 5 even
so watever calc. we do , we get only odd nos.
max . possilble here --> 8*55
min . possible --> -8*55
take only the odd terms
so watever calc. we do , we get only odd nos.
max . possilble here --> 8*55
min . possible --> -8*55
take only the odd terms
@rubikmath said:a.56 take 8 out as common --> 8(+-1 till +-10)can form only 56 terms
yes its ri8 but kaise kiya, thoda aaram se samjhao yaar :D
@rubikmath said:from 1 to 10 we have 10 terms --> 5 odd , 5 even so watever calc. we do , we get only odd nos.max . possilble here --> 8*55min . possible --> -8*55take only the odd terms
take only the odd terms??? ye ni aaya samajh
@sumit99 said:take only the odd terms??? ye ni aaya samajh
we have terms from -55 to +55 using +-1,+2,----+-10 ryt ? (leav out the 8 )
but we cant form all the nos. from -55 to +55 using these 10 nos.
we have 5 odd nos. --> 1,3,5,7,9
5 even nos. --> 2,4,6,8,10
so watever calc. we perform , result be a odd no.
so take all the odd nos. in the range -55 to +55
but we cant form all the nos. from -55 to +55 using these 10 nos.
we have 5 odd nos. --> 1,3,5,7,9
5 even nos. --> 2,4,6,8,10
so watever calc. we perform , result be a odd no.
so take all the odd nos. in the range -55 to +55
@rachit_28 said:A music class has a group of 5 students. Three subgroups, A,B,C are formed by choosing the students at random from the main group. Some students can be put in two or more groups as well. What is the probability that no student is common in all the three sub groups ?OA: (7/8)^5
total case :
a student in one of the 3 groups --> 3 ways
in 2 of the 3 groups --> 3 ways
in all 3 group --> 1way
in none of the group --> 1way
total --> 8 ways
similarly for all 5 students --> 8^5
fav.case :
remove, in all 3 group in prev.case --> total 7 ways
--> 7^5
prob. --> 7^5/8^5
but this includes , no students selected .
a student in one of the 3 groups --> 3 ways
in 2 of the 3 groups --> 3 ways
in all 3 group --> 1way
in none of the group --> 1way
total --> 8 ways
similarly for all 5 students --> 8^5
fav.case :
remove, in all 3 group in prev.case --> total 7 ways
--> 7^5
prob. --> 7^5/8^5
but this includes , no students selected .
@rubikmath said:total case :a student in one of the 3 groups --> 3 waysin 2 of the 3 groups --> 3 ways in all 3 group --> 1wayin none of the group --> 1way total --> 8 ways similarly for all 5 students --> 8^5fav.case : remove, in all 3 group in prev.case --> total 7 ways--> 7^5prob. --> 7^5/8^5but this includes , no students selected .
yeah, but there is no constraint as such given in the question, what do you say ?
@gautam22 said:sorry not related to this thread but koi plz ye bata do ki IIFT mein sectionals cutoff hoti hai kya?
i wish i know the answer for this question....
but here's some history:
in the last year's paper, nothing was mentioned abt secn cutoffs....And, they did not take into account the secn scores...only the final was considered
but here's some history:
in the last year's paper, nothing was mentioned abt secn cutoffs....And, they did not take into account the secn scores...only the final was considered
Sum of five real numbers is 7.: the sum of their squares is 10. Find the minimum, max possible values of any one of the numbers !!
Find the smallest positive integer such that when its leftmost digit is removed, the resulting number becomes 1/57th of original number.
@insane.vodka said:Find the smallest positive integer such that when its leftmost digit is removed, the resulting number becomes 1/57th of original number.
let the number be aX...so:
(10^n)+X = 57X ==> 10^n=56X....is this even possible...?
@gautam22 i am no sir dude.....calling that makes me feel old(which I am not)
(10^n)+X = 57X ==> 10^n=56X....is this even possible...?
@gautam22 i am no sir dude.....calling that makes me feel old(which I am not)
@rachit_28 said:yeah, but there is no constraint as such given in the question, what do you say ?
yup . so (7/8)^5 it is ..
@shadowwarrior said:let the number be aX...so:(10^n)+X = 57X ==> 10^n=56X....is this even possible...?@gautam22 i am no sir dude.....calling that makes me feel old(which I am not)
haan bhai possible hein 