2.
149^646 = 1 mod 647
149^149226 = 1 mod 647
149^3 N -1 = 0 mod 647
3307949*N -1 should be divisible by 647.
now by options .ok
1. E(3293) = 3168
247^3168 = 1 mod 3293
247^250272 = 1 mod 3293
247 * N -1 is divisible by 3293..now by options
@gautham87
@rkshtsurana said:@gautham872.149^646 = 1 mod 647149^149226 = 1 mod 647149^3 N -1 = 0 mod 6473307949*N -1 should be divisible by 647.now by options .ok1. E(3293) = 3168 247^3168 = 1 mod 3293 247^250272 = 1 mod 3293 247 * N -1 is divisible by 3293..now by options@gautham87
How do you arrive at the 3rd step ? 😲
149^3 N -1 = 0 mod 6473307949*N -1 should be divisible by 647.
and
247^250272 = 1 mod 3293247 * N -1 is divisible by 3293..now by options
pls explain
149^3 N -1 = 0 mod 6473307949*N -1 should be divisible by 647.
and
247^250272 = 1 mod 3293247 * N -1 is divisible by 3293..now by options
pls explain
@19rsb said:In a family there are 4 members.The father is 38 yrs older than his son and the mother is 26 yrs older than her daughter.The sum of their ages today is 82. All member are at least one year old.Eight years ago sum of their ages was 57.Which of these will be the possible value for the age of the son in 8yrs?1)182)193)164)17
16 hi gogi
f=38+s
m=26+d
f+m+s+d=82
2s+2d=18
s+d=9
Among the given options only 16 satisfy the condition of each member atleast 1 year old :)
f=38+s
m=26+d
f+m+s+d=82
2s+2d=18
s+d=9
Among the given options only 16 satisfy the condition of each member atleast 1 year old :)
@gautham87 said:@rkshtsurana bro... am sorry its unclear.. please explain the concept
u knw euler theorem? ..i have done with inverse euler ?
check dem out
http://www.pagalguy.com/news/cat-2012-quant-basic-applications-remainder-theorem-a-27784
http://www.pagalguy.com/news/remainders-reloaded-euler-fermat-wilsons-theorems-cat-2011-a-19067
http://www.pagalguy.com/news/cat-2011-quant-finding-out-remainders-really-scary-looking-numbers-divide-each-other-a-18969
@gautham87 said:How do you arrive at the 3rd step ? 149^3 N -1 = 0 mod 6473307949*N -1 should be divisible by 647.and247^250272 = 1 mod 3293247 * N -1 is divisible by 3293..now by optionspls explain
i have used inverse euler
concept - http://www.pagalguy.com/pings/inverse-euler-ping-21676
A,B,C started to reach varanasi from delhi 300 km away they have only one bike which travel at a speed of 60 km/hr and every one can walk at a speed of 15 km/hr condition is every one has to reach at the same time and only two person can travel at a time. wat is the minimum time required for them to reach there.
@arumugadas said:A,B,C started to reach varanasi from delhi 300 km away they have only one bike which travel at a speed of 60 km/hr and every one can walk at a speed of 15 km/hr condition is every one has to reach at the same time . wat is the minimum time required for them to reach there.
I think the quest is incomplete...and this type of question has been done before..it'a ans was 65/7 ..I guess this q has incomplete info..like whether only 1 person can travel on bike or 2??
I am nt sure..can be horribly wrong..please correct me if i am wrong..
@rkshtsurana
@rkshtsurana said:i have used inverse euler concept - www.pagalguy.com/pings/inverse...
@rkshtsurana said:u knw euler theorem? ..i have done with inverse euler ?check dem outwww.pagalguy.com/news/cat-2012...www.pagalguy.com/news/remainde...www.pagalguy.com/news/cat-2011...
I'm going through it 😃 brb 😃 thanks :)
@ScareCrow28 said:I think the quest is incomplete...and this type of question has been done before..it'a ans was 65/7 ..I guess this q has incomplete info..like whether only 1 person can travel on bike or 2?? I am nt sure..can be horribly wrong..please correct me if i am wrong..
ques is crrect..9 2/7 hrs..iift ques,,,
Bohat jaldi thread ban gaya 2013 ka bhai.. aaj dekha ..
aur 296 pages ho bhi gaye 
Anywz... Will try to be active this time .. 
P.S. Pranam .. rkshtsurana bhai 😃
@htomar said:Bohat jaldi thread ban gaya 2013 ka bhai.. aaj dekha ..aur 296 pages ho bhi gaye Anywz... Will try to be active this time .. P.S. Pranam .. rkshtsurana bhai
bht late aaye ho..
Can any1 help me with easiest way to compare 497/3189 and 483/3230 for greater value b/w them....is der any trick to solve such calculations...or make such comparisons...pls help..
(20^2004) + (16^2004) - (3^2004) - 1 is divisible by?
1)317
2)323
3)253
4)91
1)317
2)323
3)253
4)91
@rkshtsurana said:bht late aaye ho..
Life enjoy kar raha tha ji kuch din ke liye ..
Better late then never.. 
Post the solution for last question... solve nai ho raha.
@quant89 said:Can any1 help me with easiest way to compare 497/3189 and 483/3230 for greater value b/w them....is der any trick to solve such calculations...or make such comparisons...pls help..
Numerator is less and denominnator is more in 2nd number ...so 2nd number is less
@19rsb said:(20^2004) + (16^2004) - (3^2004) - 1 is divisible by?1)3172)3233)2534)91
323?
Taking pairs of (20,3) and (16,1) ---> divisible by 17
(20,1) and (16,3) ----> divisible by 19
17*19 = 323
@quant89 said:Can any1 help me with easiest way to compare 497/3189 and 483/3230 for greater value b/w them....is der any trick to solve such calculations...or make such comparisons...pls help..
I tried this..
497/3189 = 483/3230 ( start assuming them to be equal.. and cross multiply)
497*3230 = 483 * 3189
(483 + 14)*( 3189 + 41) > 483*3189 ( LHS sounds to be greater than RHS)
Hence 497/3189 > 483/3230
497*3230 = 483 * 3189
(483 + 14)*( 3189 + 41) > 483*3189 ( LHS sounds to be greater than RHS)
Hence 497/3189 > 483/3230
The ratio of monthly income of A and B is 3:4.the ratio of monthly expenditure of A and B is 4:5 . Wat should be the ratio of saving of A and B.
OA 13:20
OA 13:20