The value of (222)baseX in base 'X' when converted to base 10 is 'P'. The value of (222)baseY in base 'Y' when converted to base 10 is Q. If (P – Q)base10 = 28, then what is the value of (Q – X)base10?(a) 10(b) 92(c) 79(d) Cannot be determined
2*(x^2+x+1) = P
2*(y^2+y+1) = Q
P-Q = 28
=>2(x^2+x+1) - 2*(y^2+y+1) = 28
=>(x^2-y^2) + (x-y) = 14
=>(x-y)(x+y+1) = 14
two possibilities
case1: (x-y) = 1 and (x+y+1) = 14 =>x=7 and y=6
case2: (x-y) = 2 and (x+y+1) = 7 =>x=4 and y=2
but y=2 not possible as in this case we cannot have 222.
A mixture comprises two chemicals A and B. The price of A is Rs. 100/- per litre and that of B is Rs.200/- per litre. We can spend a maximum of Rs. 600/- for making the mixture. The densities of A andB are 10 kg/litre and 12 kg/litre respectively. The mixture must contain each of the chemicals to theextent of at least 25% by weight. The maximum weight of the mixture that can be made is closestto:a. 60 kg b. 51 kg c. 54 kg d. 48 kg Equation will be - (3x/4)*100*(1/10) +(x/4)*200*1/12 = 600 Solving, x = 51 kg (Approx.)
Could you please explain this in detail. What is the connection between density and percentages ? .. i'm sorry if its simple sir.. i couldn't follow :(
Vidya has to call her friend Arati, but she doesn't remember Arati's phone number. She has two options, first to try calling Arati directly and in case she doesn't get the number right she could try the second option of calling up Divya, another friend of her who would in turn give Twinkle's number who finally give her Arati's number. Alternatively, Vidya can try the second option first. Given Vidya needs to minimize the total number of calls she has to make, what should be the minimum level of certainity that Vidya should have regarding the number she already has so that it would be advisable for her to try the first option before the second?
Take (1,2,3,4,5,6,7,8,17)----Difference of no two is=8
Bhai v r asked it should give diff of 8 surely If v take 9 nos like this (1,2,3,4,5,6,7,8,20) None of the nos r giving a difference of 8 For making sure a difference of 8 is obtained 13 nos should be taken eg for worst case scenario (1,2,3,4,5,6,7,8,20,19,18,17,16)
Vidya has to call her friend Arati, but she doesn't remember Arati's phone number. She has two options, first to try calling Arati directly and in case she doesn't get the number right she could try the second option of calling up Divya, another friend of her who would in turn give Twinkle's number who finally give her Arati's number. Alternatively,
Vidya has to call her friend Arati, but she doesn't remember Arati's phone number. She has two options, first to try calling Arati directly and in case she doesn't get the number right she could try the second option of calling up Divya, another friend of her who would in turn give Twinkle's number who finally give her Arati's number. Alternatively, Vidya can try the second option first. Given Vidya needs to minimize the total number of calls she has to make, what should be the minimum level of certainity that Vidya should have regarding the number she already has so that it would be advisable for her to try the first option before the second?(a) 25% (b) 75% (c) 100/3% (d) 200/3% (e) 50%
Bhai v r asked it should give diff of 8 surelyIf v take 9 nos like this (1,2,3,4,5,6,7,8,20)None of the nos r given a difference of 8For making sure a difference of 8 is obtained13 nos should be taken eg for worst case scenario(1,2,3,4,5,6,7,8,20,19,18,17,16)
Bhai..i have given the answer as 13 only only 😛 I was juat giving an example to him that taking numbers may not suffice the condition..We have to take 13 numbers.. :)
Bhai....i have given the answer as 13 only I was just giving an example to him that taking 9 numbers may not suffice the condition..We have to take 13 numbers..
My bad sorry didn't read ur earlier post PS: @soumitrabengeri yaar why did u change ur DP? U were one of the very few who used their original pic (if it was u 😃 )
a, b, c, d, e, f, g are non-negative such that a+b+c+d+e+f+g = 1. Then the minimum value of max(a+b+c, b+c+d, c+d+e, d+e+f, e+f+g) is(a) 1/3 (b) 3/7 (c) 1 (d) 0 (e) none of the foregoing
Crux of the problem: many of us are tempted to make all the variables equal. This technique would help only when expression is cyclical in nature. for example (ab,bc,ca) is cyclical, i.e if we replace a by b, b by c and c by a ...we get back the original expression. However, in the problem under consideration a closer look reveals that all the terms inside the bracket are not fully cyclical. Hence variables are not interchangeable
out of all the five values i.e a+b+c, b+c+d, c+d+e, d+e+f, e+f+g we observe that terms containing a,d,g are disjoint. i.e if any expression contains a then it does not contain d and g.
so we set a=d=g=1/3 and rest all the other variables = 0.
Vidya has to call her friend Arati, but she doesn't remember Arati's phone number. She has two options, first to try calling Arati directly and in case she doesn't get the number right she could try the second option of calling up Divya, another friend of her who would in turn give Twinkle's number who finally give her Arati's number. Alternatively, Vidya can try the second option first. Given Vidya needs to minimize the total number of calls she has to make, what should be the minimum level of certainity that Vidya should have regarding the number she already has so that it would be advisable for her to try the first option before the second?(a) 25% (b) 75% (c) 100/3% (d) 200/3% (e) 50%
sorry didn't read ur earlier post