@19rsb said:E???getting 4/9
Nai bhai :P
@adream27 @pankaj1988 @19rsb Please share your methods..Ans can be wrong sometimes, if you share your method we can discuss the answer or we can do only 
@adream27 said:can u explain??
see total no.of operations=42
so if there are n rays to reverse them i need n operations.
so 42>n
after reversing all rays
i can keep playing with 1 ray reversing and re-reversing.
n+2K=42 where k is no.of times i play with the ray.
n has to be even
so if there are n rays to reverse them i need n operations.
so 42>n
after reversing all rays
i can keep playing with 1 ray reversing and re-reversing.
n+2K=42 where k is no.of times i play with the ray.
n has to be even
Consider two different cloth cutting processes. In the first one, n circular cloth pieces are cut from a square cloth piece of side s in the following steps: the original square of side s is divided into n smaller squares, not necessarily of the same size; then a circle of maximum possible area is cut from each of the smaller squares. In the second process, only one circle of maximum possible area is cut from the square of side s and the process ends there. The cloth pieces remaining after cutting the circles are scrapped in both the processes. The ratio of the total scrap cloth generated in the former to that in the latter is: (∏ = circumference of the circle/diameter of the circle)
(a) 1:1 (b) √2:1 (c) n(4-∏)/(4n-∏) (d) (4n-∏)/n(4-∏) (e) 1:√2
(a) 1:1 (b) √2:1 (c) n(4-∏)/(4n-∏) (d) (4n-∏)/n(4-∏) (e) 1:√2
@ScareCrow28 said:In a triangle PQR, PQ = QR, S and T are points on PR and PQ respectively such that RQ = QS = ST = TP. Then (a) (75, 90) (b) (105, 120) (c) (135, 150) (d) (120, 135) (e) none of the foregoing
smthng missing here...
@wovfactorAPS said:smthng missing here...
Sorry Edited the question..have a look
Edited the question..have a lookP.S. With this i complete my 1001th post!! 
@ScareCrow28 said:Consider two different cloth cutting processes. In the first one, n circular cloth pieces are cut from a square cloth piece of side s in the following steps: the original square of side s is divided into n smaller squares, not necessarily of the same size; then a circle of maximum possible area is cut from each of the smaller squares. In the second process, only one circle of maximum possible area is cut from the square of side s and the process ends there. The cloth pieces remaining after cutting the circles are scrapped in both the processes. The ratio of the total scrap cloth generated in the former to that in the latter is: (∏ = circumference of the circle/diameter of the circle)(a) 1:1 (b) √2:1 (c) n(4-∏)/(4n-∏) (d) (4n-∏)/n(4-∏) (e) 1:√2
1:1?
what is the smallest integer n for which any subset of (1,2,3,4....20) of size n must contain two numbers that differ by 8?
@audiq7 said:what is the smallest integer n for which any subset of (1,2,3,4....20) of size n must contain two numbers that differ by 8?
is it a probability question. coz otherwise n cud be 2. please explain.
@audiq7 said:what is the smallest integer n for which any subset of (1,2,3,4....20) of size n must contain two numbers that differ by 8?
13?
@ScareCrow28 said:In a triangle PQR, PQ = QR, S and T are points on PR and PQ respectively such that RQ = QS = ST = TP. Then /_ PTS (in degrees) lies in the range(a) (75, 90) (b) (105, 120) (c) (135, 150) (d) (120, 135) (e) none of the foregoing
pls.check the question again
is it PQ=PR by any chance?
S doesnt exist as per the given condition..atleast iam getting so..
is it PQ=PR by any chance?
S doesnt exist as per the given condition..atleast iam getting so..
@ScareCrow28 said:In a triangle PQR, PQ = QR, S and T are points on PR and PQ respectively such that RQ = QS = ST = TP. Then /_ PTS (in degrees) lies in the range(a) (75, 90) (b) (105, 120) (c) (135, 150) (d) (120, 135) (e) none of the foregoing
is it an equlateral triangle. point S and T are coinciding with P and Q repectively. so angle shud be 60.
please clarify.
@sujamait said:There are 8 poles on the same side of a straight road. Two of these poles are without flags; two ofthese have a flag of the same country and each of the rest of the four poles has a plain flag of adifferent colour. What is the probability that the first four poles from either end have two flags of thecountry and two plain colored flags?A.1/140B.6/35C.1/70D. None of these
4C2*2C1/8C4 = 6/35 ?
@maddy2807 @ScareCrow28 OA:13
consider all the pairs with difference of 8. e.g.(1,9)(2,10)....(8,16)
a subset of 12 elements can be formed with no elements differing by 8. like (1 2 3 4 5 6 7 8 17 18 19 20)