@krum said:T-(1,0)S-(0,2)U-(2,y)root(4+(y-2)^2)+root(1+y^2)b) _/5 +_/2 ?
tune vo eqn kaise solve ki distance ki??? differentiation seems too long 😞
vaise to directly even i thot mid pt shld d ans
vaise to directly even i thot mid pt shld d ans
@vijay_chandola
@rachit_28
koi alternate approach batao yaar iska
@rachit_28
koi alternate approach batao yaar iska
@vijay_chandola said:In a square PQRS, T is the midpoint of PQ and U is any variable point on QR. What is the minimum possible value of 창€˜SU + UT창€™ (in cm) if the side of the square is 2 cm?(a) 2_/2 (b) _/5 +_/2 (c) 1+2_/2 (d) _/13
@rachit_28 said:Differentiation is not long bro,Let RU = x Then D = SU + UT = 4+x^2 + 1 + (4-x)^2dD/dx = 0 gives x = 1Put the value x=1 and find SU + UT and you are done
4-x
4+x
kaha se aaya :wow:
4+x
kaha se aaya :wow:
@Brooklyn said:tune vo eqn kaise solve ki distance ki??? differentiation seems too long vaise to directly even i thot mid pt shld d ans
y=2/3 pe root13 aa rha hai
@Brooklyn said:tune vo eqn kaise solve ki distance ki??? differentiation seems too long vaise to directly even i thot mid pt shld d ans
dude tune SU n UT ka square liya??? dis cant be done here, if it were min ST or UT u can bt here i dont think it's correct
@vijay_chandola said:In a square PQRS, T is the midpoint of PQ and U is any variable point on QR. What is the minimum possible value of €˜SU + UT €™ (in cm) if the side of the square is 2 cm?(a) 2_/2 (b) _/5 +_/2 (c) 1+2_/2 (d) _/13
rt(13)
@rachit_28 said:Differentiation is not long bro,Let RU = x Then D = SU + UT = 4+x^2 + 1 + (4-x)^2dD/dx = 0 gives x = 1Put the value x=1 and find SU + UT and you are done
@Brooklyn said:dude tune SU n UT ka square liya??? dis cant be done here, if it were min ST or UT u can bt here i dont think it's correct
Extremely sorry bhaiyo, blunder kar diya tha ...
@Ashmukh said:how many integral slon are possible fora^2+2*b^2=1947
Crux of the problem: a must be of form 6k+/-1
clearly a has to be an odd number
also 1947 = 3*11*59
=> a cannot be multiple of 3, because in that case a^2 is a multiple of 9. And if a^2 is a multiple of 9 then b^2 must be a multiple of 3 but not a multiple of 9, which is not possible. Hence a must be of form 6k+/-1.
By same logic a cannot be a multiple of 11.
case1: a=6k+1
=>(6k+1)^2 + 2b^2 = 1947
max possible value of k can be k=7 as (6*7+1)^2 =1936 which is just less than 1947
so we try for k=1,2....7
only for k=6,7 we get b=17 and b=7 i.e (37,17) and (43,7)
case2: a = 6k-1
=>(6k-1)^2 + 2b^2 = 1947
again we try for k=1,2,..6,7
only for k=1 and k=6 we get b=31 and b=19 respectively => (5,31) and (35,19)
hence we get 4 solutions
(5,31),(35,19),(37,17) and (43,7)
now each one of them can be -ve (as each number gets squared).
so, from each ordered pair above, we can derive 4 solution (-ve,+ve), (+ve,-ve) and (-ve,-ve).
Hence total no. of integral solutions = 4*4 = 16.
ATDH.
@rachit_28 said:(b) ?
@Anivesh90 said:B?.._/5
@krum said:T-(1,0)S-(0,2)U-(2,y)root(4+(y-2)^2)+root(1+y^2)d) _/13
OA D h :splat:
gs4890 : ye kon de rha h aisi kahabr bhai? Last 1 week se 1-2 ghante se jyada nahi pada
:splat:
gs4890 : ye kon de rha h aisi kahabr bhai? Last 1 week se 1-2 ghante se jyada nahi pada
:splat:@vijay_chandola said:In a square PQRS, T is the midpoint of PQ and U is any variable point on QR. What is the minimum possible value of €˜SU + UT €™ (in cm) if the side of the square is 2 cm?(a) 2_/2 (b) _/5 +_/2 (c) 1+2_/2 (d) _/13
option B ?
@gs4890 said:@vijay_chandola@rachit_28koi alternate approach batao yaar iska
take a projection of the square PQRS about the
edge QR
TU + US
edge QR
TU + US
= TU + US €™=TS'
=_/3^2+_/2^2=_/13
@krum said:T-(1,0)S-(0,2)U-(2,y)root(4+(y-2)^2)+root(1+y^2)d) _/13
y = 1 put krne pe toh option B aayega na ?
@vijay_chandola said:take a projection of the square PQRS about theedge QRTU + US = TU + US €™=TS'=_/3^2+_/2^2=_/13
rt(9) + rt(4) = rt(13)kese hgya ?????
@vijay_chandola said:In a square PQRS, T is the midpoint of PQ and U is any variable point on QR. What is the minimum possible value of €˜SU + UT €™ (in cm) if the side of the square is 2 cm?(a) 2_/2 (b) _/5 +_/2 (c) 1+2_/2 (d) _/13
option d (rt 13)
If the roots of the equation ax3 + bx2 + cx + d = 0 are in Geometric Progression, then which of the following relations is true?
(a) a*c^2 = b^2*d
(a) a*c^2 = b^2*d
(b) a*c^3 = b^3*d
(c) a^2*c = b*d^2
(d) a^3*c = b*d^3