Official Quant thread for CAT 2013

@gs4890 said:
2. An atom A forms an ionic bond with an atom B by complete transfer of one electron to B. If internuclear distance is 2.67 × 10–10 m and charge on electron is 1.602 × 10–19 C, the dipole moment of the bond is(1) 4.277 × 10–29 cm (2) 3.09 × 10–30 cm (3) 1.96 × 10–30 cm (4) 4.56 × 10–28 cm
op 1..
2. In a one-day cricket match, Agarkar, Sehwag, Sachin. Dravid and Ganguly scored an average of 39 runs. Dravid scored 7 more than Ganguly, Ganguly secored 9 fewer than Agarkar, Sehwag scored as many as Dravid and Ganguly combined; and Sehwag and Sachin scored 110 runs between them. How many runs did Sachin score?

(1) 47 (2) 51
(3) 53 (4) None of the above

easy pessy
@gs4890 said:
2. In a one-day cricket match, Agarkar, Sehwag, Sachin. Dravid and Ganguly scored an average of 39 runs. Dravid scored 7 more than Ganguly, Ganguly secored 9 fewer than Agarkar, Sehwag scored as many as Dravid and Ganguly combined; and Sehwag and Sachin scored 110 runs between them. How many runs did Sachin score?(1) 47 (2) 51 (3) 53 (4) None of the aboveeasy pessy
4 .not??
@gs4890 said:
2. An atom A forms an ionic bond with an atom B by complete transfer of one electron to B. If internuclear distance is 2.67 × 10–10 m and charge on electron is 1.602 × 10–19 C, the dipole moment of the bond is(1) 4.277 × 10–29 cm (2) 3.09 × 10–30 cm (3) 1.96 × 10–30 cm (4) 4.56 × 10–28 cm
Dipole moment=charge*internuclear distance
=2.67*1.602*10^-29
=4.277*10^-29
@gs4890 said:
2. In a one-day cricket match, Agarkar, Sehwag, Sachin. Dravid and Ganguly scored an average of 39 runs. Dravid scored 7 more than Ganguly, Ganguly secored 9 fewer than Agarkar, Sehwag scored as many as Dravid and Ganguly combined; and Sehwag and Sachin scored 110 runs between them. How many runs did Sachin score?(1) 47 (2) 51 (3) 53 (4) None of the aboveeasy pessy
D=G+7
G=A-9
Sh=D+G
Sh+Sa=110

A+Sh+Sa+D+G=195
A+D+G=85
G+9+G+7+G=85
3G=69
G=23
D=30
Sh=53
Sa=57

@rubikmath said:
Sara has 5 flower pots each with a unique flower. The pots are arranged along a line. One day she decided to change their order under the condition that no two pots that were originally next to each other remain next to each other. no.of possible orders is ?a.12b.44c.14d.8
dearrangement of 5!=44
@maddy2807 said:
The difference between compound interest and simple interest for 3 years at the rate of 5% per annum is Rs. 61. What is the principal amount? A. Rs. 9,000 B. Rs. 8,000 C. Rs. 7,000 D. Rs. 6,000 E. Rs. 5,000
P(1.05)^3-P(1.15)=61
P(1.1025*1.05)-1.15=61
P(1.157625)-1.15=61
P(.007625)=61
P=61*1000000/7625
=1000000/125
=8000


Find the area bound by the graph |x-2y| + |y-2x | = 3 and the co-ordinate axes in the first quadrant of x-y plane?

@Nihilist1002 said:
Find the area bound by the graph |x-2y| + |y-2x | = 3 and the co-ordinate axes in the first quadrant of x-y plane?
2.5 sq units

@Nihilist1002 tag me with the correct approach ,tia

@krum well your ans is right

draw the graph ............ rest will be resolved
@rubikmath
Ans. is 14 ?
Approach is lengthy one..will post if the ans. is correct !
@Nihilist1002 said:
@krum well your ans is right draw the graph ............ rest will be resolved
Can you plz show how we can draw the graph quickly from |x-2y| + |y-2x | = 3, I mean to say shortcut !
@LeoN88 Draw the graph for x -2y and y-2x..... den after go by inequality approach...........well I do noe that it is bit tedious but I solved this question in that manner only........If you came across any short cut for this lemme noe
@gs4890 said:
2. An atom A forms an ionic bond with an atom B by complete transfer of one electron to B. If internuclear distance is 2.67 × 10–10 m and charge on electron is 1.602 × 10–19 C, the dipole moment of the bond is(1) 4.277 × 10–29 cm (2) 3.09 × 10–30 cm (3) 1.96 × 10–30 cm (4) 4.56 × 10–28 cm
1??
@Nihilist1002 said:
Find the area bound by the graph |x-2y| + |y-2x | = 3 and the co-ordinate axes in the first quadrant of x-y plane?
@krum @LeoN88
The graph is in the attachment.. From that it's clear the area is 2.5 sq units..

To get the integer solutions.. First put x = 0 you'll get y value as +- 1
then y = 0, x = +- 1

put x = 1, y = 2
x = -1, y = -2
y = 1, x = 2
y = -1, x = -2

and for the equation x and y can't go beyond two..
@gnehagarg said:
dearrangement of 5!=44
@rubikmath is it 12?

it can't be derangement of 5..

take an eg.. a b c d e

a c e b d is a valid arrangement but a is still in its original position..
@antodaya said:
Which of the following will come in place of the question mark in the following series.TU2 PMB 8A3 ? V7L(1) DEH (2) E9Z (3) IL7 (4) 9W5 (5) None of these
DEH??
@gs4890 said:
2. In a one-day cricket match, Agarkar, Sehwag, Sachin. Dravid and Ganguly scored an average of 39 runs. Dravid scored 7 more than Ganguly, Ganguly secored 9 fewer than Agarkar, Sehwag scored as many as Dravid and Ganguly combined; and Sehwag and Sachin scored 110 runs between them. How many runs did Sachin score?(1) 47 (2) 51 (3) 53 (4) None of the aboveeasy pessy
None of these
@antodaya said:
no..kaisekia ..? ye ans nahi hai...
Let the big people say about the question..it was jus a guess.
There are 6 person with 6 tasks. Task 1 cannot be assigned to either 1 or 2 . Task 2 must be assigned to either 3 or 4..every person must assigned one task. In how many ways does assignement be done??