@ScareCrow28 said:A queue of n + m people is waiting at a box office; n of them have 5-pound notes and m have 10-pound notes. The tickets cost 5 pounds each. When the box office opens there is no money in the till. If each customer buys just one ticket, what is the probability that none of them will have to wait for change?
@Brooklyn said:@ScareCrow28[(n!*m!) + ((n+1) P m * n!) ]/(n+m)!
@Brooklyn said:@ScareCrow28 : wats wrong with mine??
(n-m)/(n+m) kaise ho sakta hai??? If n=m, then probability comes 0 by this...In actuality it is not so...I am getting this as the answer when n is different from m
@ScareCrow28 said:I cant tell how you reached at that equation..thoda explain karo to pta chale shayad mistake kaha hui
@Brooklyn said:i did ws : ways of ordering all people= (n+m)!ordering all n poeple first and den m people= n!*m!ordering n and m people alternatively = (n+1)P m *n!den made probab out of it.
@ScareCrow28 said:A queue of n + m people is waiting at a box office; n of them have 5-pound notes and m have 10-pound notes. The tickets cost 5 pounds each. When the box office opens there is no money in the till. If each customer buys just one ticket, what is the probability that none of them will have to wait for change?
@Brooklyn said:wat more cases??
@ScareCrow28 said:You again took one of the cases..right?
@Brooklyn said:i did ws : ways of ordering all people= (n+m)!ordering all n poeple first and den m people= n!*m!ordering n and m people alternatively = (n+1)P m *n!den made probab out of it.
@ScareCrow28 said:You cant say that all "n" are before m or "n" and "m" are alternately only... There can be more cases than that..
@catter2011 said:infact that is easier to thinkconsider 3 persons n(2)+m(1) = 3 ,n= a,bm=ctotal line arrangement possible = 3*2*1 = 6abcacbbcabaccabcbaexcept in last two cases.. in all other cases theres is no need to wait for changehence 4/6 = 2/3 = 2m/n+m(please correct if there is anything wrong)
@rachit_28 said:bhai fir toh 2n/m+n hona chayiye naa ?
@ayushnasa said:@ScareCrow28 And first things first, is there any way we can get this level questions in IIFT??
@catter2011 said:wots da final answer in n.m terms ? also please check my soln above..
@ScareCrow28 said:I don't think that probability se itne tough questions aa sakte h..but i do think that IIFT has a few personal favourite topics jisme se wo tough questions puch sakte hai.. BTW You only asked for more questions I can stop anytime you want