find ratio of square inside equilateral triangle ??
shouldn't the answer be 5/8 ??
1) area of the small triangle / big triangle == 1 :: 4 .
2) so area of small triangle is x and area of ( trapezium + smaller triangle ) is 3x
3) so , required ratio = ar . of trap / ar of triangle
== (3x - 0.5x) / 4x == 5/8
but the answer is 5 / ( 6* (3^0.5) )
LR set. i don't have the OA. post ur answer. i need to check mine.
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a+b+c+d= 12, a,b,c,d
a+b+c+s=12 , a,b,c,d =1 , (CASE 2)
Any suitable link for the same, will be appreciated. (post edited)
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