Official Quant thread for CAT 2013

N is a 4 digit number that satisfies the following conditions.The sum of the squares of the extreme digits is 13. The sum of the squares of middle digit is equal to 85. If we subtract 1089 from the desired number we obtain a number containing the same digits in reverse order?

How many N;s are possible?
1
2
3
4

KIindly explain attached

N is a 4 digit number that satisfies the following conditions.The sum of the squares of the extreme digits is 13. The sum of the squares of middle digit is equal to 85. If we subtract 1089 from the desired number we obtain a number containing the same digits in reverse order?


What is the sum of the digits of N?

18
27
16
Indeterminable

The number of roots of the equations x+log (1+2^x) = x* log 5 + log 6 is (All the base is to 10)

0
1
2
More than 2

In how many ways , counting ties, can four horses finish the crossing line ?

For example two horses A and B can finish in three ways A wins, B wins and A and B tie

75
71
85
NOT

A, B and C started a business by investing money in the ratio of 4:6:3 respectively. They get the returns in the ratio of 5:8:6 according to the investment and the work done by them. Find the ratio of work done by A, B and C respectively?

15:18:42
15:16:24
24:18:15
24:18:9

1 small clarification puys..


Mr. Sam has a wife and three children. Mrs. Sam is three years younger to Mr. Sam. The ages of the three children, being in AP, add up to 6/5 times that of Mr. Sam's age. While the youngest child of Mr. Sam is a female, the sum of the ages of the three males in the family is 85 years. The age of the second son of Mr. Sam can be:


So the 3 children's are a-d,a,a+d. In the question it is given as SECOND SON. So now will it be a or a+d??

How to interpret this one? 1st daughter, 2nd son and 3rd son? Or Daughter, 1st son and 2nd son? πŸ‘ΌπŸ‘Ό

7^7^7^.....7
Find the Last Digit for the above expression?

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0 voters

7 different objects must be divided into three people. In how many ways this can be done if one or two of them must get no object.

My approach :
7 distinct object should be given to 3 distinct people.
Condition : either one or two person must not bet any object, that means

7 object should be given to two of them OR 7 object should be given to one of them

1st: two persons selected in 7C2 and distributed in 2^7 ways i.e. 7C2*2^7
2nd: only one should be given all 7 object, that one person selected in 7C1 ways and only one way to distribute = 7C1*1

i.e. 7C2*2^7 + 7

OA - 381 whats wrong ?


@sagarcat @jasneetdua



N/D gives a remainder of 52. 5N/D gives a remainder of 4. how many values of D are possible?

Find the remainder when 135713571357...(upto 1000 digits) is divided by 101.

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0 voters

hi

can any one please send me the link to "download the Quant aptitutde preparation pdf by Arun sharma"

Thanks in Advance

hi

can any one please send me the link to "download the Quant aptitutde preparation pdf by Arun sharma"

Thanks in Advance

hey guys.how many mock tests do u think is good to take??

32^32^32/7 by eulers theorem..pls explain

A speaks truth in 30% cases.

B speaks truth in 40% cases.

C speaks truth in 25% cases.
All of them are interrogated for murder case.
Probability that police catch murderer if police goes by majority of the answers given by A,B,C.

a).24
b).45
c).285
d)None of these


Find the remainder when 59^73^5! is divided by 37

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0 voters

All Will be Solved with the same logic, Can somebody please explain the logic behind the approach :banghead: :banghead:

Q. 7 different object must be divided into 3 groups (people) such that at least one of them get exactly one object.?

Q. How many 4 digit numbers are there whose notation contains not more than two distinct digit?

Q. How many 7 digit numbers are there such that the sum of whose digits are odd ?

Q. How many 6 digit number contain exactly 4 different digit ?


What is the difference between 'Train A overtakes Train B' and 'Train A crosses Train B'? Will the equations formed be different in both cases?

A teacher asks one of her students to divide a 30-digit number by 11. The number consists of six consecutive 1's, then six consecutive 2's, and likewise six 3's, six 4's and six 7's in that order from left to right. The student inserts a three-digit number between the last 4 and the first 7 by mistake and finds the resulting number to be divisible by 11. Find the number of possible values of the three-digit number.