@audiq7 said:frm a set of 3 capital and 5 small consonants and 4 small vowels, how many wrds can be formed each starting with a capital consonant and containing 3 small consonants and two small vowels?
3*5P3*4P2 ?
@amresh_maverick said:If all the 5 letter words are formed from the letters of MATHEMATICS , in how many of them will the letter E occur ?694563096069907012
M - 2
A - 2
T - 2
H - 1
I - 1
C - 1
S - 1
E - 1
Case 1: E and four letters of the form aabb
=> 3C2 * ( 5!/2!2!) = 90
Case 2: E and four letters of the form aabc
=> 3C1*6C2 *( 5!/2!) = 2700
Case 3: E and four letters of the form abcd
-> 7C4*5! = 4200
Total = 90 + 2700 + 4200 = 6990 ?
@amresh_maverick said:If all the 5 letter words are formed from the letters of MATHEMATICS , in how many of them will the letter E occur ?694563096069907012
OA : 6990
Ten people are seated in a row. No of ways in which 4 people can be selected such that no 2 of them are adjacent ?
@amresh_maverick said:Ten people are seated in a row. No of ways in which 4 people can be selected such that no 2 of them are adjacent ?
35?
@amresh_maverick said:Ten people are seated in a row. No of ways in which 4 people can be selected such that no 2 of them are adjacent ?
_ p1 _ p2 _ p3 _ p4 _
a + b + c + d + e = 6 , where (b,c,d >=1)
=> a + b' + c' + d' + e = 3 => Number of ways = 7C4 = 35
@amresh_maverick said:Ten people are seated in a row. No of ways in which 4 people can be selected such that no 2 of them are adjacent ?
OA : 35
@rachit_28 said:Can anyone tell isme kya galat ho raha hai ?
ARRANGEMENT PROB. 5P3*4P2 SAHI NAI HAI.
@rachit_28 said:Can anyone tell isme kya galat ho raha hai ?
Arrange them only after all the selections are done. In your case, you start arranging before all the selections are done.
In how many ways can 20 people be seated at two different circular tables , each of which can accomdate 10 people ?
@amresh_maverick said:In how many ways can 20 people be seated at two different circular tables , each of which can accomodate 10 people ?
Dividing the 20 people into distinct groups => 20!/(10!10!2!)
Distributing them in 2! ways, and then in each table, arrange them in 9! ways
-> 20!/(10*10) ?
@amresh_maverick said:In how many ways can 20 people be seated at two different circular tables , each of which can accomdate 10 people ?
20C10*(9!)^2
@amresh_maverick said:In how many ways can 20 people be seated at two different circular tables , each of which can accomdate 10 people ?
@maddy2807 said:20C10*(9!)^2
OA
@soham2208 said:What did I do wrong to not get tagged ?
nothing sorry for that. I missed out. I have seen ur explanations. You are the next big thing to happen on the quant thread
Two guns are fired from the same place at an interval of 10.5 mins but a person in the shatabdi express approaching the place hears the second shot 10mins after the first. the speed of the shatabdi express in kmph if the speed of sound is 330m/s is?a)59.6kmph b)45.1kmph c)120.35kmph d)none of these e)cannot be determined
@amresh_maverick said:Ten people are seated in a row. No of ways in which 4 people can be selected such that no 2 of them are adjacent ?
35?