A right triangle with hypotenuse 10 inches and other two sides of variable length is rotated about its longest side thus giving rise to a solid. Find the max possible area of such a solid? 1st solved example in Arun Sharma - Block IV but cant get the solution completely.
If one explaining book approach, kindly request to answer foll 2 ques : 1. why to take isocelese triangle to maximize the area. Is it a general rule? 2. area of cone taken = pi/3*r^2*h which is but the volume of cone.So how is it the total area? Trying to figure this out since long...Any other approach/solution much appreciated! 🍻
The 38th term and the 88th term of an arithmetic progression are 301/25 & 903/25 respectively. If the total number of terms in the progression is 175, what is the ratio of the sum of the first 75 terms to the sum of the last 100 terms of the progression?
a professor conducts an examination in which there are 50 questions, a correct question carries +1 mark , a wrong question gives a penalty of 1/3 whereas a question left gives +1/6 , marks. two persons abhishek and arushi attempts the paper such that all the questions abhishek attempts are correct , while aarushi attempts atleast 1 wrong question.
.1)what is the maximum common score these two can get?43.33 45 49.33 44.33
2) when aarushi and abhishek got maximum common score , how many question did aarushi do wrong?3 4 5 7
A dishonest dealer claims to sell a product at its cost price. He uses a counterfeit weight which is 20% less than the real weight. Further greed overtook him and he added 20% impurities to the product. Find the net profit percentage of the dealer?
Ise maine aise solve kiya tha..
let 100 units product be dere costing rs 100 Wen he uses counterfeit wt. he sells only 80 kg in name of 100 kg. Further He adds 20% impurity so the Final quantity wil be 80*4/5=64 Cost of this 64 kg wil be rs 64 So his profit=100-64/64*100=56.25
But the answer is 50%.
Somebody else did it this way:
Let say the dealer sells 1 kg of the product and cost of the product=100
Now, as per the faulty weight, it would weigh 1/.8=1.25 kg
Furthermore, 20 kg impurities are also added, => total weight=1.25*1.2=1.5 kg
Now, dealer will sell that 1.5 kg of product at 150 bucks as 1 kg of it costs 100 bucks.
=> he makes a total of (150-100)/100=50% of profit.