A man, starting from a point P, takes exactly six equal steps. Each step is in one of the four directions – East, West, North and South. What is the total number of ways in which the man ends up at point P after the six steps?
Four vehicles are travelling on a straight highway with constant speeds.The trucks overtook the car at 2:00 Pm and then met the scooter at 4:00 PM and the motorcycle at 6:00 PM.The motorcycle met the car at 7:00 pm then it overtook the scooter at 8:00.At what time scooter and the car meet?Choose one answer.
a. 5:00 pm b. 5: 40 pm c. 5: 30 pm d. 5: 20 pm
Solution
Truck--> X. X.
-----------------------.-----------------------
Car(2pm)-->.
The above fig is as per question: let distance travelled by truck in 2 hrs be X
1) Motorcycle meets car at 7 pm
Hence distance travelled by motorcycle in 1 hr + distance travelled by car in 5 hrs = X+X =2X
I.e 1M+5C = 2X
=> M=2X - 5C...........(1)
2) Motorcycle overtakes scooter at 8 pm
Hence distance travelled by motorcycle in 2 hrs - distance travelled by scooter in 4 hrs = X
I.e. 2M - 4S = X
=> M= (X+4S)/2.........(2)
Now from (1) and (2), we get
2X - 5C = (X+4S)/2
=> 3X =10C+4S
=> X = (10/3) C + (4/3) S
This means that car will meet scooter when car will travel for (10/3) hrs after 2 pm I.e. 5.20 pm
Or
Scooter will travel for (4/3) hrs after 4 pm I.e again 5.20 pm
Hence answer is D
P.s. apologies for posting it late. @shivamarora @nitya101289 @vidit9811
Let f(x) = – x2 + 35, g(x) = | x + 5 | + | x – 5 | and h(x) = min {f(x), g(x)}. What is the number of integer values of x for which h(x) is equal to 10?
How to find number of integral co-ordinates in a triangle(on the boundary and inside the triangle). Co-ordinates of the vertices are (6,0) , (2,4) , (2,-4)?
In how many ways can the letters of the word EDUCATION be rearranged so that the relative position of the vowels and consonants remain the same as in the word EDUCATION? (a) 9!/4 (b) 9!/(4!*5!) (c) 4!*5! (d) 9!/2! (e) None of these
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If B and C run in the clockwise direction and A runs in the anti-clockwise direction, how much distance would C cover by the time A and B met for the second time?
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do we have any other way other than normal counting.
Also this is from PG mocks, where the solution posted by one of us is:
72 = 2x2x2x3x3 72 = 2,2,2,3,3 We have to divide it into 3 groups.
For that i have to introduce 2 Saperator between these 5 numbers.
2_2_2_3_3
Remember we cannot place separator at the extreme end because one group will be 0 For First Saperator There are 4 spaces, and for Second saperator there are 3 spaces,
Hence 4 x 3 = 12 2 | 2 2 | 3 3 2 2 2 | 3 | 3
By this method we are not counting combinations like 1 x 1 x 72, 1 x 2 x 36…..??
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