@catter2011 said:Minimum value of root((x-4)^2 + (y-6)^2) if 8x+6y=28 ?
7?
@blade014 said:learning from the a.m. typo...option A would be my final take.
made the same mistake few days back, while solving previous year iifts
Q 4. x1, x2, x3... x50 are fifty real numbers such that xr
A. 20C2*30C2/50C3
B. 30C2*19C2/50C5
C. 19C2*31C2/50C5
D. NOT
@maddy2807 said:not sure of ans. did differentiation. ...wats the OA?
its nothing but perpendicular distance b/w (4,6) to the given line eqn....
@deedeedudu said:Q 4. x1, x2, x3... x50 are fifty real numbers such that xr for r = 1, 2, 3... 49. Five numbers out of these are picked up at random. The probability that the five numbers have x20 as the middle isNote: The expression in bold has been corrected.)A. 20C2*30C2/50C3B. 30C2*19C2/50C5C. 19C2*31C2/50C5D. NOT
option C?
@deedeedudu said:Q 4. x1, x2, x3... x50 are fifty real numbers such that xr for r = 1, 2, 3... 49. Five numbers out of these are picked up at random. The probability that the five numbers have x20 as the middle isNote: The expression in bold has been corrected.)A. 20C2*30C2/50C3B. 30C2*19C2/50C5C. 19C2*31C2/50C5D. NOT
is it b?????/
@Rage126 said:@soham2208Bhai Gussaa kun hote ho , then go other way 81*bahut badi value hogi aur 16*negative no choti value i.e. a*1-b*6=7(unit digit).
Hahah.. no no ghussa nahi hu.. 😛 Thoda sa high hu bas.. 😛
@deedeedudu said:Q 4. x1, x2, x3... x50 are fifty real numbers such that xr for r = 1, 2, 3... 49. Five numbers out of these are picked up at random. The probability that the five numbers have x20 as the middle isNote: The expression in bold has been corrected.)A. 20C2*30C2/50C3B. 30C2*19C2/50C5C. 19C2*31C2/50C5D. NOT
B
@catter2011 said:Minimum value of root((x-4)^2 + (y-6)^2) if 8x+6y=28 ?
if i put y=3 => x=1.25
sqrt( 2.75^2+ 3^2)
getting 4.069
to isse to kam hi hoga
@deedeedudu said:Q 4. x1, x2, x3... x50 are fifty real numbers such that xr for r = 1, 2, 3... 49. Five numbers out of these are picked up at random. The probability that the five numbers have x20 as the middle isNote: The expression in bold has been corrected.)A. 20C2*30C2/50C3B. 30C2*19C2/50C5C. 19C2*31C2/50C5D. NOT
d ?
@deedeedudu said:Q 4. x1, x2, x3... x50 are fifty real numbers such that xr for r = 1, 2, 3... 49. Five numbers out of these are picked up at random. The probability that the five numbers have x20 as the middle isNote: The expression in bold has been corrected.)A. 20C2*30C2/50C3B. 30C2*19C2/50C5C. 19C2*31C2/50C5D. NOT
B ?
@catter2011 said:its nothing but perpendicular distance b/w (4,6) to the given line eqn....
isse 4 aayega kya ???
yes 4
@deedeedudu said:Q 4. x1, x2, x3... x50 are fifty real numbers such that xr for r = 1, 2, 3... 49. Five numbers out of these are picked up at random. The probability that the five numbers have x20 as the middle is: (Note: The expression in bold has been corrected.)A. 20C2*30C2/50C3B. 30C2*19C2/50C5C. 19C2*31C2/50C5D. NOT
OA is B.
Thats it from my side guys nd gals
Thats it from my side guys nd gals
@catter2011 said:its nothing but perpendicular distance b/w (4,6) to the given line eqn....
bhai logic smajha do, kaise kiya
not getting how it fits to the question 
@techsurge Bhai ek baat bolon iska anwer mera 4 aa raha hai. circle ki equation hai with center 4 and 6 bas radius dhoondna hai, minimum tabhi hoga jab ye line tangent ho jaye . matlab 4,6 se perpendicular distance dhoondna hai to given line .
@catter2011 said:Minimum value of root((x-4)^2 + (y-6)^2) if 8x+6y=28 ?
Am I right?
@catter2011 said:Minimum value of root((x-4)^2 + (y-6)^2) if 8x+6y=28 ?
Am I right?
@soham2208 koi na weekend hai High hona banta hai. but High hoke quant karna nahin banta.
Sorry for Spamming :(
Sorry for Spamming :(