@Brooklyn none of these
@Nihilist1002 said:@hxparam it is 59.4 Bro
yes it is 59.4.. it is not present in the choices . so none of these. anyways.. could u please elaborate.. i still dont understand how it is solved... you can pm me.
@deedeedudu said:Q. Ashok a master adulterator cum grosser sells haldi powder (turmeric powder), which contains five percent saw dust. What quantity of pure haldi should be added to two kilos of haldi (containing five percent saw dust) so that the proportion of saw dust becomes four percent?A. 1 kg.B. 23 kgsC. 0.5 kg.D. None of these
0.5?
@deedeedudu said:Q. Ashok a master adulterator cum grosser sells haldi powder (turmeric powder), which contains five percent saw dust. What quantity of pure haldi should be added to two kilos of haldi (containing five percent saw dust) so that the proportion of saw dust becomes four percent?A. 1 kg.B. 23 kgsC. 0.5 kg.D. None of these
Current proportion in 2kg..haldi - 1400g and saw dust - 100g
If 0.5 kg is added..total mixture = 2.5kg
Out of this..haldi - 2.5kg and saw dust - 100g
100g = 40% of 2.5 kg
So the answer should be 0.5kg
@deedeedudu said:Q. Ashok a master adulterator cum grosser sells haldi powder (turmeric powder), which contains five percent saw dust. What quantity of pure haldi should be added to two kilos of haldi (containing five percent saw dust) so that the proportion of saw dust becomes four percent?A. 1 kg.B. 23 kgsC. 0.5 kg.D. None of these
is it c?????/
@techsurge Bhai wahi to value will change according to value you will take, d ke accordngingly p ke value aayegi. us accordingly options mold hongi . Hope i am clear enough.
@deedeedudu said:Q. Ashok a master adulterator cum grosser sells haldi powder (turmeric powder), which contains five percent saw dust. What quantity of pure haldi should be added to two kilos of haldi (containing five percent saw dust) so that the proportion of saw dust becomes four percent?A. 1 kg.B. 23 kgsC. 0.5 kg.D. None of these
Simple allegation problem
OA is 0.5 kg
OA is 0.5 kg
@deedeedudu said:Q. Ashok a master adulterator cum grosser sells haldi powder (turmeric powder), which contains five percent saw dust. What quantity of pure haldi should be added to two kilos of haldi (containing five percent saw dust) so that the proportion of saw dust becomes four percent?A. 1 kg.B. 23 kgsC. 0.5 kg.D. None of these
c .5
find integral values of and b if 16a+81b=337
approach pls..
approach pls..
Q 2. If the complex number z1 and z2 are such that |z1|=12 and |z2-3-4i|=5 then the minimum value of |z1-z2| is:
A. 0
B. 2
C. 7
D. None of these
@catter2011 said:find integral values of and b if 16a+81b=337approach pls..
16a = 337 - 81b
Divide by 16, the remainder on both the sides would be equal
LHS remainder = 0
RHS remainder = 1 - (1)*r
r should be 1 => b = 16k + 1
b = 1,17,33 and so on -> For each value of b, get a ..
Infinite values if integral
But if positive integral, then b = 1, a = 16 I guess
PS: There could be calculation mistakes ..
@deedeedudu said:Q 2. If the complex number z1 and z2 are such that |z1|=12 and |z2-3-4i|=5 then the minimum value of |z1-z2| is:A. 0B. 2C. 7D. None of these
B) 2
@deedeedudu Is Answer 2
Two circles one with center 0,0 and radius 12 and other with center 3,4 and radius 5?
Two circles one with center 0,0 and radius 12 and other with center 3,4 and radius 5?
@soham2208 said:16a = 337 - 81bDivide by 16, the remainder on both the sides would be equalLHS remainder = 0RHS remainder = 1 - (1)*rr should be 1 => b = 16k + 1b = 1,17,33 and so on -> For each value of b, get a .. Infinite values if integralBut if positive integral, then b = 1, a = 16 I guessPS: There could be calculation mistakes ..
+1......
@soham2208 said:16a = 337 - 81bDivide by 16, the remainder on both the sides would be equalLHS remainder = 0RHS remainder = 1 - (1)*rr should be 1 => b = 16k + 1b = 1,17,33 and so on -> For each value of b, get a .. Infinite values if integralBut if positive integral, then b = 1, a = 16 I guessPS: There could be calculation mistakes ..
Thanks., crct..
@deedeedudu said:Q 2. If the complex number z1 and z2 are such that |z1|=12 and |z2-3-4i|=5 then the minimum value of |z1-z2| is:A. 0B. 2C. 7D. None of these
2?
@deedeedudu said:Q 2. If the complex number z1 and z2 are such that |z1|=12 and |z2-3-4i|=5 then the minimum value of |z1-z2| is:A. 0B. 2C. 7D. None of these
B. 2
@deedeedudu said:Q 2. If the complex number z1 and z2 are such that |z1|=12 and |z2-3-4i|=5 then the minimum value of |z1-z2| is:A. 0B. 2C. 7D. None of these
Circles here..
C1: Centre (0,0) .. r1 = 12
C2: Centre (3,4) .. r2 = 5
C2 is inside C1 -> Minimum distance between any two points = 2 ? (r1 - 2*r2)