Official Quant thread for CAT 2013

@Brooklyn take alpha=2 Beta=1/2 and gamma=3 and delta=1/3. solve and get answer
@Brooklyn said:
wat did u assume??
by chance same as what deedeedudu assumed :)
@techsurge said:
Q3f(2x-1) = 3x +4 , what is the value of f(1) +f(2)+ f(3)......f(10)a) 130b) 137.5c)145d) 150
OPTION B
f(1)=3+4
f(2)=4.5+4
....

SUM= 10(4) + 5(6+13.5)
137.5

@deedeedudu said:
Take Alpha=2,Bita=1/2,Gaama=3, Delta =1/3
why 2,1/2,3,1/3 ?? :banghead:

why not 1,2,3,5 or anyother distinct roots ?
@techsurge we can do it assuming 11 th term square to be 2 and 5th term square term to be 1 .

PS question give us liberty to assume any value since variable p is involved.
@gs4890 said:
why 2,1/2,3,1/3 ?? why not 1,2,3,5 or anyother distinct roots ?
bhai ab = 1 he na so reciprocal roots ayenge..same for othr equation
@gs4890 said:
why 2,1/2,3,1/3 ?? why not 1,2,3,5 or anyother distinct roots ?
Product 1 chahiye just to make life easy assume easiest values :)
@gs4890 said:
why 2,1/2,3,1/3 ?? why not 1,2,3,5 or anyother distinct roots ?
bot possible const =1
@gs4890 in both of the equation pdt of root is 1 thats y
@gs4890 Bhai Product of roots need to be 1 .Your last constant term is given t be 1.
Q.4
[image was removed because it was too large]
@gs4890 said:
Q.4
A [-7,3)-{0}
@gs4890 said:
Q.4
a)
@gs4890 4. A

@deedeedudu , @Brooklyn , @gs4890 bhai isme - {0} kyu he ?
@gs4890 said:
Q.4
a
@gs4890 Q4. A
@gs4890 said:
Q.4
Take - A

since log is defined only for positive numbers
@deedeedudu option a
@rkshtsurana said:
@gs4890 4. A@deedeedudu bhai isme - {0} kyu he ?
I was also wondering that
@rkshtsurana said:
@gs4890 4. A@deedeedudu bhai isme - {0} kyu he ?
same question . :)