Official Quant thread for CAT 2013

Bostan is 4 hr ahead of Frankfurt and 2 hr behind India. X leaves Frankfurt at 6 p.m. on Friday and reaches Bostan the next day. After waiting there for 2 hr, he leaves exactly at noon and reaches India at 1 a.m. On his return journey, he takes the same route as before, but halts at Bostan for 1 hr less than previous halt there. He then proceeds to Frankfurt.
1) If the journey from F to I, including stoppage, is covered at an average speed of 180 mph, what is the distance between Frankfurt and India??
A) 3600miles
B) 4500 miles
C) 5580 miles
D) 4150 miles
E) Data insufficient

2) If X had started the return journey at 2.55 a.m. on the same day that he reached there, after how much time would he reach Frankfurt?
A) 24hr
B) 25 hr
C) 26 hr
D) 23 hr
E) Data insufficient

3) What is X's average speed for the entire journey(to and fro)?
A) 176mph
B) 180mph
C) 165 mph
D) 166 mph
E) Data insufficient

Cat is seating in a tunnel at a point which divides length of tunnel in 3:5. It listens to a horn blown by a train and starts running. In respective of, in whichever direction it runs. It will just manage to escape. What is the ratio of their speed?
A) 8:3
B) 2:5
C) 1:4
D) 5:8
E) can't be determined

PLEASE POST EXPLANATION...

If a sphere is inscribed in a cube of side a, the radius of the sphere will be__________&

If a sphere is

circumscribed about a cube of side a, the radius of the sphere will be_______________.🍻🍻


PLEASE POST EXPLANATION...

If a largest possible sphere is inscribed in a cylinder of radius 'a' and height h, its radius r will

be__________________{If 2a > h}

&

______________________{If 2a

🍻🍻

PLEASE POST EXPLANATION...

If a largest possible sphere is inscribed in a cone of radius r and slant height equal to 2r, then

the radius of sphere___________________________?

🍻🍻


PLEASE POST EXPLANATION...



If a cube is inscribed in a hemisphere of radius r, then the edge of the cube=________________??🍻🍻


Number of zeros at the end of 2! power 2! + 4! power 4! + 8! power 8! + 9! power 9! + 10! power 10! + 11! power 11!

check the explanation for the problem

explain pls


Kindly solve the attached questions. Please post your solution as well.

15.

There are four books. In each book all the pages (excluding the covers) are numbered. The first has 28 pages, the second 82 pages, the third 98 pages and the fourth 148 pages. If a book is selected at random and opened randomly, then what is the probability that it opens at page 84?

1/30

1/240

1/120

None of these

A spider is at one corner of a cuboidal room of dimensions 20m by 11m by 10m. It spots an ant at the farthest corner of the room. Find the minimum distance the spider needs to crawl along the faces of the room to get hold of the ant.


a) _/621 m

b) 29 m

c) 32 m

d) None of these

Kindly solve the attached questions.. Please post your solution as well .

Q.
If ((3!)!)! / 3! can be written as A*B!.Then Minimum Value of A+B is .....

2^10+4 of 9 of 6 of 10=?

  • 3260
  • 3180
  • 3175
  • 3084

0 voters

The remainder when 34^320 is divided by 214 is????

completely tired after solving so many questions of data interpretation no improvement, feeling so badembarrased

PLEASE ANSWER!!

In a certain examination paper, taken by a total of 36000 students, there are q questions. For p = 1, 2 .. q, there are 2^(q - p) students who answered p or more questions wrongly. The total number of wrong answers is 65,535.

I understood the solution till..

students with 1 or more wrong answers = 2^(q-1)students with 2 or more wrong answers = 2^(q-2) and so on

Hence, students with exactly 1 wrong answer = 2^(q-1) - 2^(q-2) = 2^(q-2) students with exactly 2 wrong answers = 2^(q-2) - 2^(q-3) = 2^(q-3)..

students with exactly q wrong answers = ??? (in solution its given 2^0)

So, No. of WRONG ANSWERS is summations of (students with exactly p wrong ans)*p = 1*2^(q-2) + 2*2^(q-3)+ 3*2^(q-4).....+ q*2^0 = 2^(q-1)+ 2^(q-2)+ 2^(q-3).....+1 How??

ANSWER =16



Zada has to distribute 15 chocolates among 5 of her children A,B,C,D,E. She has to make sure that A gets at least 3 and at most 6 chocolates. In how many ways can this be done?

a)495
b)77
c)417
d)435

two four digit numbers are written side by side to form an eight digit number which is divisible by the product of the two numbers. The pair is:
1) 1234,5678 2)5000,2000 3)1334,3667 4)3334,1667

want to know the approach for this....(.the answer is not known)...