Official Quant thread for CAT 2013

@chandrakant.k said:
hosakta hai.. i dint think that there can be typo i was thinking that i am wrong tats confidence off for 2 days.. c u all on monday
Woah!! Monday ?? Isn't that a bit late??
Anyways .. I am off for today..Happy learning!!
Please share the approach:-

20 teams of 5 archers each compete in achery competition.An archer
finishing in kth place contributes k points to his team and there are
no ties.The team that wins will be the one that has the least
score.Given that 1st position team's score is not the same as any
other team,the number of winning scores possible is?
1)236
2)237
3)238
4)239
ďťż

Find the Possible Integral values of x, |x-3|+2|x+1| = 4


a) 1 b) -1 c) 3 d)2
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@padmanabhan1989 said:
Find the Possible Integral values of x, |x-3|+2|x+1| = 4a) 1 b) -1 c) 3 d)2
is it b)-1

Ashish is given 158 rs in one rupee denominations.He has been asked to allocate them into a number of bags the amount required beetween Rs 1 and Rs 158 can be given by handing out certain number of bags without opening them.What is the minimum number of bags requied?


Please tell the approach also...................
@padmanabhan1989 said:
Find the Possible Integral values of x, |x-3|+2|x+1| = 4a) 1 b) -1 c) 3 d)2
-1
@rashmi5 said:
is it b)-1
Yep. Can u provide me the Steps. . . I am very poor in modulus..and new also
@bhatkushal said:
Ashish is given 158 rs in one rupee denominations.He has been asked to allocate them into a number of bags the amount required beetween Rs 1 and Rs 158 can be given by handing out certain number of bags without opening them.What is the minimum number of bags requied?Please tell the approach also...................
7 he kya ?
@bhatkushal said:
Ashish is given 158 rs in one rupee denominations.He has been asked to allocate them into a number of bags the amount required beetween Rs 1 and Rs 158 can be given by handing out certain number of bags without opening them.What is the minimum number of bags requied?Please tell the approach also...................
7?
@padmanabhan1989 said:
Find the Possible Integral values of x, |x-3|+2|x+1| = 4a) 1 b) -1 c) 3 d)2
x>3

3x - 1 = 4
x = 5/3 not possible

3>=x=> -1

-x + 3 + 2x + 2 = 4
x +5 = 4
x = -1

x
-x -3 - 2x - 1 = 4
-3x = 8
x = -8/3 not possible


so x = -1

@padmanabhan1989 said:
Find the Possible Integral values of x, |x-3|+2|x+1| = 4a) 1 b) -1 c) 3 d)2
-1 ?
@bhatkushal said:
Please share the approach:-20 teams of 5 archers each compete in achery competition.An archerfinishing in kth place contributes k points to his team and there areno ties.The team that wins will be the one that has the leastscore.Given that 1st position team's score is not the same as anyother team,the number of winning scores possible is?1)2362)2373)2384)239

lowest winning points = 1+2+3+4+5 = 15

highest winning points = n

n+19*(n+1) = 5050
n ~ 251

so winning score can be from 15 to 251 => 237 scores
A square field of size 72 — 72 is to be covered by rectangular tiles (with integral edges) with length
to breadth ratio is 3 : 2. What is the difference between minimum and maximum number of tiles
used?
(A) 864 (B) 210 (C) 426 (D) 860 (E) None
@rkshtsurana said:
x>33x - 1 = 4 x = 5/3 not possible3>=x=> -1-x + 3 + 2x + 2 = 4x +5 = 4 x = -1x-x -3 - 2x - 1 = 4-3x = 8x = -8/3 not possibleso x = -1
Thanks boss.. got it
@gs4890 said:
-1 ?
yes. Thanks
@Shray14 said:
A square field of size 72 — 72 is to be covered by rectangular tiles (with integral edges) with length to breadth ratio is 3 : 2. What is the difference between minimum and maximum number of tiles used? (A) 864 (B) 210 (C) 426 (D) 860 (E) None
max no of tiles when rectangles are of size 3 x 2 = 24 x 36 = 864
min no of tiles when rectangles are os size 36 x24 = 2 x 3 = 6
diff = 858
none of these
@gs4890 iift related kya hoga @ 8:30
yes,
x can have following ranges:-
1) for x3-x+2(x+1)=4
x= -1 (possible)
2) for -13-x+2(x+1) = 4
x = -1
3) for x>=3
x-3+2(x+1)=4
x = 5/3 (not possible)
thus x can take value = -1
@Shray14 :none