Official Quant thread for CAT 2013

In a triangle ABC, points p,Q and R divide the sides BC,CA and AB in the ratios 2:3,3:2 and 2:1 respectively. What is the area of triangle PQR to the area of triangle ABC.
I don't have the Original answer, but would really appreciate the help. please show your method. 😁

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In year 1980 the age in yrs of a person ws one-eighty ninth of his year of birth. Whats his age in 2012?




Can anyone explain me the question no. 5 of AIMCAT 1419? QA/DI

What equal annual investment will discharge a debt of 2070 due in 5 yrs at 10% SI (The ist instalment is paid at the end of ist year) ???


My yearly income for savings under SI comes down by 1200 due to the fall n interest rate by 2/3 percentage points. Find thee savings???????

27^100 mod 12 remainder

find the remainder of 21^22^23 mod 11......please explain the method

Itna Sannata kyu he bhai....

RF haar gaya isliye ya Sab Brazil ka match dekh rele he...?????



using binomial method while finding remainder of: 48^46 mod 49^2 (P.S how to solve when denominators are in powers)....😠

5 cards are to be drawn at one go from a well shuffled pack of 52 cards. find the probability that there are exactly 3 diamonds and exactly 2 Kings....??????

mg

if ABCD is a 4 digit no such that

ABCD = (AB + CD )^2

How many such no are there..????


👼mg

bhai logo...can u plz suggest sm good material for QA & LR practice ??


having tough questions like aimcat level...plzzzzz guyz help....time matrl already done..!!!!!

How many triangular numbers less than 1000 have the property that they are the difference of squares of two consecutive natural numbers.triangular number is a number that can be expressed as the sum of consecutive natural numbers


If u form a subset of integers chosen from between 1 to 3000 such that no two integers add up to a muliple of 9 what can be the max number of elements in the subset

What is the remainder when (1!)^3+(2!)^3+(3!)^3........(1152!)^3 is divided by 1152

Q5




A teacher wanted to administer a multiple choice (each question having six choices) based quiz of high difficulty levels to a class of sixty students. The quiz had sixty questions. The probability of selecting the correct answer for a good students and a brilliant student was 0.2 and 0.25 respectively. The poor students had no learning advantage. The teacher did not want students to cheat but does not have time and resources to monitor. All students were seated serially in 10 rows and 6 columns.


Three good students were sitting next to each other. What is the probability of them having the same incorrect choice for four consecutive questions? (1) 256/390625 (2) 256/3125 (3) 4/3125 (4) 1/3125 (5)


(1) 256/390625 (2) 256/3125 (3) 4/3125 (4) 1/3125 (5) Cannot be calculated


Can some please give solution for this problem ?


@giyan

doubthow to find the sum of the series upto 20 terms1+ 3+ 6+10.............. is it n(n+1)/2 plz explain



No. n(n+1)/2 is the nth term.

The sum is n(n+1)(n+2)/6.

Taking n=20, you get the sum as 1540.

The value of a diamond is proportional to the square of its weight.It is broken into three pieces whose weights are in the ratio 3:2:5.Find the loss incurred due to breakage if the value of the original diamond is 20,000 Rs.


  • 12600
  • 12200
  • 12400
  • 12000

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