If a and b are chosen at randomly from the set containing first nine natural numbers with replacement and let f(x)= a(x^4) + b(x^3) + (a+1)(x^2) + bx + 1,
then in how many ways f(x)>0 for all x belongs to R ??
ABCD is a cyclic quadrilateral and the points A, B and C form an equilateral triangle. What is the sum of line segments DA and DC
DB
DB/2
Root of 2*DB
DB/root 2
just change the vertices with A,B,C as equilateral and d as the fourth point.
hope it's correct
ABCD is a cyclic quadrilateral and the points A, B and C form an equilateral triangle. What is the sum of line segments DA and DC 1)DB 2)DB/2 3)Root of 2*DB 4)DB/root 2
Nīģŋ is the sum of squares of three consecutive odd nos such that all the digits of N are the same. If N is a 4-digit no then the value of N can be ?
- 5555
- 9999
- 3333
- 7777
0 voters
Let n be the smallest positive no such that S=(8^n)(5^600) has 604 digits then the sum of the digits of S is ?
a. 19 b.8 c.10 d.11
two sister go up 40 step escalator . the older sister rides the up escalator , but can take only 10 steps up during the ride since it is quite crowded . the younger sister runs up the empty down escalator , arriving at the top at the same time as her sister . how many steps does the younger sister take?
Total no of ways in which a match can be held = C(6, 2)*C(6, 2)*2
(we can choose two men in C(6, 2) ways and two women in C(6, 2) ways. Now a match can be held in 2 ways for these 4 persons)
We need to remove those cases when a couple is in the same team
If both the teams have a couple, then C(6, 2) ways
If only one team has a couple, then we can choose that couple in C(6, 1) ways. For 2nd team, men can be chosen in C(5, 1) ways and women in C(4, 1) ways (as they shouldn't be a couple)
So, C(6, 2)*C(6, 2)*2 - C(6, 2) - C(6, 1)*C(5, 1)*C(4, 1) ways
Sorry for this late a reply...had been solving P&C; these days.. đ
2 Men can be selected from 6 in 6c2 ways... now 2 female partners can be selected in 4c2 ways (excluded those who are wives)..
so the answer would be 6c2 x 4c2 x 2 (x 2 beacuase a mixed double can be held in between 4 in 2 ways) therefore answer is 15 x 6 x 2 = 180
friends,is there any set method or steps to find minimum/maximum value of an expression?
p.s. quant 
Lcm (1, 2, 3......50)/lcm (30, 31,....50) = ?
@amresh_maverick @iiminvincible
Plz solve using mass point geometry
Have a look into my method..I am not able to get 75/79 from this method...
the number of digit lying between 2000 and 7000 (including 2000 and 7000) which have at least two digit equal but atmist 3 digit equal is ?
appraoch please
Plz solve using mass point geometry
for BF\FG = x\y let
now 158\3 *x = y*50
=> x/y = 75\79
In triangle ABC, D is a point on BC such that BC : CD = 3 : 2, E is a point on AC such that AE : EC = 1 : 2 and F is a point on AB such that AF : FB = 1 : 3. EF and AD intersect at G. Find the ratio of area of triangles EGD and FGD.
A. 1 : 1 B. 1 : 3 C. 3 : 1 D. 8:3
what annual instalment will discharge a debt of 1450 due after 5 years at 8%p.a S.I? APPROACH PLS
- 450
- 250
- 400
- 320
0 voters
kiran has to pay 7282 at the end of three years. he agrees to repay the amount in three equal annual instalments. initially the interest rate in the scheme is 10%p.a compounded annuualy. but after two installments have been paid the interest rate is increased to 15%p.a effective from that year. what was the value of last installment. APPROACH PLS
- 2300
- 3300
- 2340
- 2200
0 voters
the sides of the triangle have 4,5,6 interior points marked on them respectively . the total number of triangle that can be formed using any of these points and/or the vertices would be?
please tell the approach
in the following figure .. find the other two angles of the trangle DEF if de and df are the angle bisector of angle ADB and angle ADC?
APPROACH PLEASE
PQRS is a trapezium with PQ and RS parallel PQ=6cm QR=5cm zrs=3cm and PS=4cm the area of PQRS is
27cm^2
12cm^2
18cm^2
NOT
if x= (0,1,2,5,6,8,9) how many six digit no. divisible by 3 can be formed using the elements of x, without repetition?
funda batao isko solve karne ka?
đ