Official Quant thread for CAT 2013

paridhi11890 · March 31, 2013, 9:13am

@DivineSeeker said:
i m the culprit and i, hereby, officially declare the answer to be 45. may all the CAT engulfed bodies rest in peace with this answer. amin!!!!

Ohh

😛 okk... so we can borrow the toffee in that case.. the shopkeeper is kind or the boy is too smart 😛 :)

ganeshv266 · March 31, 2013, 9:13am

@DivineSeeker

Where was this question taken from?

buck.up · March 31, 2013, 9:15am

@DivineSeeker said:
a shopkeeper sells 3 toffees for rupee 1 and also gives an extra toffee if u return him 3 wrappers then what is the max no. of toffees u can buy if u have 10 RS a simple one but ambiguous plz puys!!!!!!!!! give a min to this question. thanks.

45 toffee ?

mailtoankit · March 31, 2013, 9:16am

@ankittripathi said:
Ek toffee borrow karne ke baad, uske paas 3 wrappers ho jayenge. He can now give those 3 wrappers to the shopkeeper for the toffee he borrowed.

yaar..pura solution post karo....samajh nahi aaya kahan se borrow karega...i m getting 44 only!!

divineseeker · March 31, 2013, 9:17am

@mailtoankit nw u have reached 44 toffees and two wrappers. now let him borrow one toffee from the shopkeeper so that now he has 45 toffes and 3 wrappers. now he will return the 3 wrappers and dont take a toffee in exchange for the wrappers and compensates the borrowed on. now he has 45 toffees. look the effort is utterly towards maximising the no of toffees he can manage to buy. i hope its much clear nw.

divineseeker · March 31, 2013, 9:20am

@paridhi11890 what doubts are still floating in ur head???? post them

ankittripathi · March 31, 2013, 9:21am

@mailtoankit said:
yaar..pura solution post karo....samajh nahi aaya kahan se borrow karega...i m getting 44 only!!

So, here is the complete solution.

the boy hass 10 rupees. he can buy 30 toffees. = 30 toffees

now, he has 30 wrappers, he can buy 10 more toffees. = 40 toffees

now, he has 10 wrappers, he can buy 3 more toffees and has 1 wrapper left, = 43 toffees

now, he has 4 wrappers, he can buy one more toffee and has 1 wrapper left. = 44 toffees

now, he has 2 wrappers, he ca borrow one toffee, noe he has 3 wrappers which he can pay for the toffee he borrowed. = 45 toffees

divineseeker · March 31, 2013, 9:36am

ok the final solution goes here...

rs 10-----> 30 toffees

30 toffees-->30 wrappers

30 wrappers------------->10 toffees

10 toffees---------->10 wrappers

10 wrappers------------->3 toffees+ 1 wrapper

3 toffees+ 1 wrapper------> 4 wrappers

4 wrappers------->1 toffee+ 1 wrapper

1 toffee + 1 wrapper------->2 wrappers

so he has 44 toffees + 2 wrappers now let him borrow one toffee from the shopkeeper to count his toffees 45 and nw he will return 3 wrappers and compensate for the borrowed one..

so finally he is left with 45 toffees and no wrappers.

divineseeker · March 31, 2013, 9:50am

nw try this verbal ability question...

Choose the combination showing the CORRECT sentences:

A. Democracy fosters the freedom of expression.
B. He played really good in the last match.
C. She fell in the well in her back yard.
D. The party was held on the hotel €™s roof.

OPTIONS

1) A, C and D
2) B only
3) B and C
4) All are incorrect

amandeep2020 · March 31, 2013, 9:52am

@AsihekAdhvaryu thnxx bro..got it..!!

ganeshv266 · March 31, 2013, 9:56am

@DivineSeeker said:
nw try this verbal ability question...Choose the combination showing the CORRECT sentences:A. Democracy fosters the freedom of expression.B. He played really good in the last match. C. She fell in the well in her back yard.D. The party was held on the hotel €™s roof.OPTIONS1) A, C and D2) B only3) B and C4) All are incorrect

2??

pratishruti · March 31, 2013, 9:58am

@hexagon said:
M and N are integers satisfying M2 - M + 1 = N2. How many possible values exist for (M, N)?ans 4

M^2-M+1=N^2

M^2-1-(N^2-1)=0

M(M-1)-(N-1)(N+1)=0

now two cases arise

case 1

M(M-1)=(N-1)(N+1)=0

This implies M=0 and N=1/-1

or M=1 and N=1/-1

thus four pairs of (M,N)

case 2

M(M-1)=(N-1)(N+1) !=0

suppose M and N are even

then even*odd=odd*odd

this is never possible

suppose M and N are odd

then odd*even=even*even

this is also not possible because for both M and N to be integers we should have one to one correspondence between LHS and RHS for equating purpose

similarly when M and N are (odd,even) /(even,odd), same problem will occur

so in all we can only have four (M,N) pairs

divineseeker · March 31, 2013, 10:01am

@ganeshv266 its not the correct one.

B is incorrect because to modify a verb we always use the adverb and not the adjective 창€“ he played well would be correct.

the ans is "D"

buck.up · March 31, 2013, 10:05am

@DivineSeeker Bhai this thread is specific to quant only. Pla discuss verbal over here

http://www.pagalguy.com/posts/5047206

Please delete your question from here. Also I will also delete my comment.

@ganeshv266

techgeek2050 · March 31, 2013, 10:16am

@dream_BLAC_2013 said:
@techgeek2050Actually its one of those which is independent of the direction. I wish I could show you how but cant do it online. But lets take the example of the sum posted in the last page for you (ans-375 wala sum). Lets solve it inside a minute using this shortcut-->Total Distance travelled when they meet for the 3rd time- (5*100)km Relative speed- 60+20 = 80 km/hr Time taken to meet for the 3rd time= D/S = 25/4 hrsDistance travelled by Q in this time= 25/4 * 60 = 375 kmI understand the thing that u are trying to convey but it becomes too massive if we do sums like that, always trying to calculate whether they are in the same or opp direction. Use this formula for any similar sum & find out for urself

it becomes independent of direction only when we read 'B' , the ratio of their speeds. Because when we don't know that , we cannot say if the one with higher speed would be completing laps faster, thereby overtaking the slower one multiple times.

ganeshv266 · March 31, 2013, 10:27am

@Buck.up said:
@DivineSeeker Bhai this thread is specific to quant only. Pla discuss verbal over herehttp://www.pagalguy.com/forums/verbal-ability/official-verbal-ability-thr-t-90385/p-3615881/r-5047206Please delete your question from here. Also I will also delete my comment.@ganeshv266

bhai it wasnt my question..

j.gayu · March 31, 2013, 11:17am

@mani0303 : sry boss ....my fault din solve it properly

asihekadhvaryu · March 31, 2013, 11:21am

Its just a old ques from forum can you guys please confirm its answer with my answer?...What is the remainder when the number formed by writing all natural numbers in sequence (1234567891011...202122...) till the 120th digit is divided by 8?
My take is 6

ani1308 · March 31, 2013, 11:28am

@AsihekAdhvaryu said:
Its just a old ques from forum can you guys please confirm its answer with my answer?...What is the remainder when the number formed by writing all natural numbers in sequence (1234567891011...202122...) till the 120th digit is divided by 8?My take is 6

yup ..it will be 6..last three digit will be 646..divided by 8 ..rem =6

mailtoankit · March 31, 2013, 11:28am

@AsihekAdhvaryu said:
Its just a old ques from forum can you guys please confirm its answer with my answer?...What is the remainder when the number formed by writing all natural numbers in sequence (1234567891011...202122...) till the 120th digit is divided by 8?My take is 6

getting 6 ??

12345.....60 ---> 111 digits

616263646 ---> 111 + 9 = 120 digits

646 mod 8 = 6