@Logrhythm said:i misread the ques....both would be required
but from the 1st d distance can be calculated..isnt it?
@Logrhythm said:i misread the ques....both would be required
@dream_BLAC_2013 said:@[email protected]@ziddiarmaanCan someone plz try this DS sum? A & B start from two ends of a swimming pool 50m long simultaneously. What is the total distance distance covered by them?A. They are meeting 2nd time after startB. A's speed is twice that of B's.I know that this sum looks very simple. I just cant makeout if this book has a printing mistake in the answer keys or is there any hidden factor that I am missing. Plz help
@DeAdLy said:par we dont know the their speeds so how can we know about distance covered....is second statement is not there
@shattereddream said:@mailtoankit suppose A's Speed as 1 m/sec & B's speed as 50 m/sec tab kya 150 mt travel karte ??
@shattereddream said:@mailtoankit suppose A's Speed as 1 m/sec & B's speed as 50 m/sec tab kya 150 mt travel karte ??
@shattereddream said:@mailtoankit suppose A's Speed as 1 m/sec & B's speed as 50 m/sec tab kya 150 mt travel karte ?
@techgeek2050 said:y do v need the speed? v know the total distance

@mailtoankit said:EDIT : both are required ??total distance covered by them after 2nd meet = 50 + 2*50 = 150dist. covered by A = 2/3*150 = 100dist by B = 1/3*150 = 50
@DeAdLy said:par we dont know the their speeds so how can we know about distance covered....is second statement is not there

@techgeek2050 said:i don't get it. what is the need to calculate the individual distances?
@techgeek2050 said:y do v need the speed? v know the total distance

@mailtoankit said:1) when two bodies start moving towards each other, then the total distance covered by them for the nth meeting = D + ((n-1)*2D) = (2n - 1)D2) when two bodies start moving towards the same direction, then for the nth meeting they will cover together (n*2D) distancePS : ek book mein padha tha..

@mailtoankit said:1) when two bodies start moving towards each other, then the total distance covered by them for the nth meeting = D + ((n-1)*2D) = (2n - 1)D2) when two bodies start moving towards the same direction, then for the nth meeting they will cover together (n*2D) distancePS : ek book mein padha tha..

@shattereddream said:@mailtoankit suppose A's Speed as 1 m/sec & B's speed as 50 m/sec tab kya 150 mt travel karte ??
...chalo answer is neither 1 nor 2..
@dream_BLAC_2013 said:@[email protected]@mailtoankit@DeAdLy@LogrhythmWell exactly Thats what I thought it should be but the answer in this book says that the QUESTION CANNOT BE ANSWERED USING BOTH. In the explanation, it says that u are reqd to find theTOTAL DISTANCE TRAVELLED BY THEM and NOT TOTAL DISTANCE TRAVELLED BY EACH ONE OF THEM.Again nowhere is it mentioned if u have to find the total distance covered during first meet or second meet. So Data Inconsistent.Was very confused & taken aback at the soln. Thats y i wanted to consult with u guys. Do u think THAT answer is wrong or are we doing it wrong? Thanks for ur massive help this late