A can complete a piece of work in 4 days. B takes double the time taken by A. C takes double that of B, and D takesdouble that of C to complete the same task. They are paired in groups of two each. One pair takes two- thirds the timeneeded by the second pair to complete the work. Which is the first pair?1. A, B 2. A, C 3. B, C 4. A, D
A can complete a piece of work in 4 days. B takes double the time taken by A. C takes double that of B, and D takesdouble that of C to complete the same task. They are paired in groups of two each. One pair takes two- thirds the timeneeded by the second pair to complete the work. Which is the first pair?1. A, B 2. A, C 3. B, C 4. A, D
Efficiencies of A, B, C and D = 1/4, 1/8, 1/16, 1/32.
Option 4 - A, D
Proof => 1/8 + 1/16 = 3/16.
A and D => 1/4 + 1/32 = 9/32.
These are efficiencies. Time will be 16/3 and 32/9 where 32/9 = 2/3 of 16/3.
A can complete a piece of work in 4 days. B takes double the time taken by A. C takes double that of B, and D takesdouble that of C to complete the same task. They are paired in groups of two each. One pair takes two- thirds the timeneeded by the second pair to complete the work. Which is the first pair?1. A, B 2. A, C 3. B, C 4. A, D
A can complete a piece of work in 4 days. B takes double the time taken by A. C takes double that of B, and D takesdouble that of C to complete the same task. They are paired in groups of two each. One pair takes two- thirds the timeneeded by the second pair to complete the work. Which is the first pair?1. A, B 2. A, C 3. B, C 4. A, D
A can complete a piece of work in 4 days. B takes double the time taken by A. C takes double that of B, and D takesdouble that of C to complete the same task. They are paired in groups of two each. One pair takes two- thirds the timeneeded by the second pair to complete the work. Which is the first pair?1. A, B 2. A, C 3. B, C 4. A, D
Efficiencies of A, B, C and D = 1/4, 1/8, 1/16, 1/32.Option 3 - B and C Proof => 1/8 + 1/16 = 3/16.A and D => 1/4 + 1/32 = 9/32.3/16 = Two - thirds of 9/32.
A can complete a piece of work in 4 days. B takes double the time taken by A. C takes double that of B, and D takesdouble that of C to complete the same task. They are paired in groups of two each. One pair takes two- thirds the timeneeded by the second pair to complete the work. Which is the first pair?1. A, B 2. A, C 3. B, C 4. A, D
A can complete a piece of work in 4 days. B takes double the time taken by A. C takes double that of B, and D takesdouble that of C to complete the same task. They are paired in groups of two each. One pair takes two- thirds the timeneeded by the second pair to complete the work. Which is the first pair?1. A, B 2. A, C 3. B, C 4. A, D
A can complete a piece of work in 4 days. B takes double the time taken by A. C takes double that of B, and D takesdouble that of C to complete the same task. They are paired in groups of two each. One pair takes two- thirds the timeneeded by the second pair to complete the work. Which is the first pair?1. A, B 2. A, C 3. B, C 4. A, D
Time taken = 1:2:4:8Efficiency = 8:4:2:1 pairwise time taken = 2:3 pairwise efficiency = 3:2 hence 8+1:4+2
A can complete a piece of work in 4 days. B takes double the time taken by A. C takes double that of B, and D takesdouble that of C to complete the same task. They are paired in groups of two each. One pair takes two- thirds the timeneeded by the second pair to complete the work. Which is the first pair?1. A, B 2. A, C 3. B, C 4. A, D
Time taken = 1:2:4:8
Efficiency = 8:4:2:1 pairwise time taken = 2:3 pairwise efficiency = 3:2 hence 8+1:4+2
A can complete a piece of work in 4 days. B takes double the time taken by A. C takes double that of B, and D takesdouble that of C to complete the same task. They are paired in groups of two each. One pair takes two- thirds the timeneeded by the second pair to complete the work. Which is the first pair?1. A, B 2. A, C 3. B, C 4. A, D
Time taken = 1:2:4:8
Efficiency = 8:4:2:1 pairwise time taken = 2:3 pairwise efficiency = 3:2 hence 8+1:4+2
From which step of the following process does the error begin? Step 1 a = b i.e., let a = b Step 2 aa = ab Step 3 aa - bb = ab - bb Step 4 (a + b) x (a - b) = b(a - b) Step 5 a + b = b Step 6 2a = a Step 7 2 = 1 1. 3 2.1 3. 5 4. 6
That was efficiency. Needed to take the inverse of that.
Better to do the mistakes in practice than to do them in the real thing!