No dude..I could take it from online,but the one exclusively for remainders compiled by S/E engineer way back in 2004 is hard to get...I'd lost it nowOne from the remainderWhat is the remainder when (1!)^3 +(2!)^3 +(3!)^3 +(4!)^3 + -----------------------(1152!)^3 is divided by 1152?
A and B start swimming simultaneously from two points P and Q respectively, on a river towards each other. A crosses a floating cork at a point S and B crosses the floating cork at a point T which is at a distance of 8 km from point S. A and B cross each other at a distance of 2 km from T. It is given that the direction of flow of the river is from P to Q and in still water, the ratio of speeds of A and B is 3 : 1. P, S, T and Q ( in that order) are on the same straight line and assume that A, B and the floating cork move along that line.If PQ = 100 km, then find the distance between the floating cork and A when A reaches Q.
Time taken for A to move from S to X, Ta = 10/(3s+r)
Time taken for B to move from X to T, Tb = 2/(s-r)
Now Tb = 3Ta
This is because relative speed of both A and B w.r.t the cork's speed (river speed) is nothing but their own speeds. So if A takes T time to move away from cork, B will take 3T time to retrace back from same point and meet the cork.
So, 30/(3s+r) = 2/(s-r)
s/r = 4/3 ---(1)
Also, time taken for A and B to reach point X is same. (a + 10)/(3s+3/4s) = b/(s-3/4s)
And, a + b = 90
So b = 25/4
From (1), we get 3s/r = 4 --> (3s+r)/r = 5
So if A covers distance, 'd', cork will cover d/5.
Can u share the solution?=====Q: I left the room at a time between 4 and 5PM and returned between 7 and 8PM and noticed that the two hands of the clock had just interchanged their positions. What is the time when I returned?OA not available https://www.facebook.com/pages/Quantexpert/123213681084921
Suppose i left the room x minutes past 4 and i return at y minutes past 7 the two hands of the clock are interchanged that means the minute hand will replace the hour hand so they will make the same angle minute hand travels at 6 deg per minute and hour hand travels at 1/2 deg per minute 6x= 210 + y / 2 ( 210 becoz hour hand has past 7) 6y = 120 + x/2 ( 120 becoz hour hand has past 4) solving both these eqns you will get y = 23.04
Bill and Clinton take the square of a certain decimal number and express it in base 5 and 6 respectively. Then Bush comes and he takes the two representations and assuming that the expressions are in base 10, adds the numbers. Which of the following cannot be the value of the unit €™s digit of the sum obtained?
Bill and Clinton take the square of a certain decimal number and express it in base 5 and 6 respectively. Then Bush comes and he takes the two representations and assuming that the expressions are in base 10, adds the numbers. Which of the following cannot be the value of the unit €™s digit of the sum obtained?
Bill and Clinton take the square of a certain decimal number and express it in base 5 and 6 respectively. Then Bush comes and he takes the two representations and assuming that the expressions are in base 10, adds the numbers. Which of the following cannot be the value of the unit창€™s digit of the sum obtained?
options for the question are 0,2,8,6,3 @ganeshv266
No dude..I could take it from online,but the one exclusively for remainders compiled by S/E engineer way back in 2004 is hard to get...I'd lost it nowOne from the remainderWhat is the remainder when (1!)^3 +(2!)^3 +(3!)^3 +(4!)^3 + -----------------------(1152!)^3 is divided by 1152?
is it 225 ?
(4!)^3 + (5!)^3 +...........(1152!)^3 mod 1152 = 0
so (1!)^3 + (2!)^3 + (3!)^3 mod 1152 = 1 + 8 + 216 mod 1152 = 225 mod 1152 = 225
Bill and Clinton take the square of a certain decimal number and express it in base 5 and 6 respectively. Then Bush comes and he takes the two representations and assuming that the expressions are in base 10, adds the numbers. Which of the following cannot be the value of the unit €™s digit of the sum obtained?
x^2 mod 5 +x^2 mod 6 will b added x^2 mod 5 will b either 0,1,4 x^2 mod 6 0,1,4,3 6,9 cannot be formed i guess
1. In how many ways 18 identical balls can be put in 3 identical boxes? 2. In how many ways 18 distinct balls can be put in 3 identical boxes? 3. In how many ways 18 identical balls can be put in 3 distinct boxes? 4. In how many ways 18 distinct balls can be put in 3 distinct boxes?
