@vbhvgupta said:a 3 digit no has its first 2 digits equal. Find the maximum possible ratio of the no and the sum of tis digit, if the no is not divisible by 10.
991/19
@vbhvgupta said:the sum of the present ages of a mother and her daughter is 60 years When the mother attains her husband's present age, the ratio of her husband's age and her daughter's age would be 2:1 . FInd the present age of the daughter.
daughter=20 years, mother= 40 years , husband= can't be determined.
@vbhvgupta said:the sum of the present ages of a mother and her daughter is 60 years When the mother attains her husband's present age, the ratio of her husband's age and her daughter's age would be 2:1 . FInd the present age of the daughter.
Daughters age is 20 years
@Buck.up said:Find the area of the region consisting of those points (x,y) for which x^2+y^2-4xx^2+y^2-8x1)2*(2pi-1)2)4(pi/3 - _/3/2)3) 4(2pi/3 - _/3/2)4) 2(pi-2)
i m getting 4(2pi/3 - rt3/2) ??
radius of both the circle is 2
centers are (2,0) ans (4,0)
area = 2*(120/360*pi*(2)^2 - 1/2*2*2*rt3/2) = (8pi/3 - 2rt3)
now take 4 common from this
area = 4(2pi/3 - rt3/2)
@shattereddream said:Daughters age is 20 years
As per question .. there is nothing wrong in doing it like 2x + x = 60
x = 20. Right ?
Because present ages are in 2:1 ratio.
x = 20. Right ?
Because present ages are in 2:1 ratio.
@zuloo said:991/19
we have 911/11 greater than this. But still I am not able to find a particular way to do this.
question..
@dushyantagarwal said:we have 911/11 greater than this. But still I am not able to find a particular way to do this.
First 2 digits same tha bhai...
regards
scrabbler
regards
scrabbler
@psk.becks said:question..
Arrange NNNIT in 5!/3! ways then in the 6 spaces formed xNxNxNxIxTx choose 3 which will be occupied by Es. So 5!/3! * 6C3
regards
scrabbler
regards
scrabbler
@dushyantagarwal said:we have 911/11 greater than this. But still I am not able to find a particular way to do this.
buddy it is saying same first two digits so i am presuming it to be xxg. then the answer would be 991/19.
@zuloo said:buddy it is saying same first two digits so i am presuming it to be xxg. then the answer would be 991/19.
@scrabbler said:First 2 digits same tha bhai...regardsscrabbler
My Bad
question
for xxg one. here goes the solution.
(100x+10x+g)/(x+x+g)= (110x+g)/(2x+g)= 55-(54g/(2x+g))= 55- 54/(2(x/g)+1)
now for this expression to be maximum, x/g has to be maxmimum, which is possible for x=9 and g=1.
i hope it helps :)
@psk.becks said:question..
C?
aEbEcEd
a+b+c+d=5
b and c should be 1 atleast
a+b'+c'+d=3
6c3 solutions
arrange the 5 letters
5!/3!
6c3*5!/3!
OA FOR LAST ONE- 18
QUESTION