how can we reach the quotient???? remainder is possible. cant think of the approach to get the unit's quotient... plz help!!!!!!
@amresh_maverick said:There is a water tank of capacity 1,000 L with two inlet pipes A and B that can pump in water at the rate of 50 L/hr and 25 L/hr respectively. An outlet pipe C attached to the tank can pump out water at the rate of 50.Initially the tank is full and the outlet pipe is opened. Now when the water in the tank is (3/4)th of the maximum volume of water that it can hold, both the inlet pipes are opened until the tank becomes full after which they are closed back. This process is repeated for an infinite number of times. Find the volume of water in the tank as a fraction of the capacity of the tank after 205 hrs.
v/4 = 250
volume replaced in 250/50=5 hours
volume added per hour = 25+50-50=25l
250ls will be added in 250/25=10 hours
hours spent 15
205 mod 15=10
so volume added = 125
750+125=875
@amresh_maverick said:OA: 26.67A man starts from point A and walks northwards at the speed of 6 km/hr. He then turns right and walks eastwards at the speed of 4 km/hr, turns right again and walks southwards at the speed of 8 km/hr and turns left and walks eastwards at the rate of 6 km/hr. The time he walks in various directions is inversely proportional to the speed with which he walks. If the total distance that he covers is equal to 100 km then find how far he is from the starting point?
bhai there is some problem with the OA,use centre of mass concept.the train has travelld 600 m.so the trail must have travelled 400 m.we have to add 100 m of the train A.i don't agree with the OA.atleast laws of physics say otherwise
@DivineSeeker said:plz puys.... help this !!!!what is the digit in the unit's place of the quotient of 10^40000/(10^400+40).
testfunda? there is a guy who posted this solution over there..though how he derived that method is still not clear..
@Marchex said:N positive real numbers have a product of unity. Their sum must be(1) divisible by N. (2) equal to N + 1/N (3) at least N. (4) a natural number. (5) None of theseNeed Solution also
product = 1, so the numbers would be like a, 1/a ,b, 1/b....
a * 1/a * b * 1/b * ..... = 1
and u know that a+1/a >=2
so if there are 2 numbers, sum>=2 , 4 numbers , sum >=4 and so on. so must be atleast N
@DivineSeeker said:plz puys.... help this !!!!what is the digit in the unit's place of the quotient of 10^40000/(10^400+40).
10^40000 = Q(10^400 + 40) + R, where Q is quotient and R is remainder when 10^40000 is divided by 10^400 + 40
Remainder when 10^40000 is divided by (10^400 + 40) is (-40)^100 or 40^100
=> 10^40000 = Q(10^400 + 40) + 40^100
Clearly unit digit of Q has to be 0
@chillfactor said:10^40000 = Q(10^400 + 40) + R, where Q is quotient and R is remainder when 10^40000 is divided by 10^400 + 40Remainder when 10^40000 is divided by (10^400 + 40) is (-40)^100 or 40^100=> 10^40000 = Q(10^400 + 40) + 40^100Clearly unit digit of Q has to be 0
thats not even in the option..oa--6, 4 ,3, 9, 2
Question : --
Rachit bought 19 erasers for rs 10. He paid 20 paise more for each white eraser than for each brown eraser. what could be the price of white eraser and how many erasers could he have bought ?
a. 60, 8
b. 60, 12
c. 50, 8
d. 50, 10
Tell the approach please ! 
@Bigshu said:@chillfactor yar ye test funda me aaj ka question haii.......aur '0' option h nahi hai............
@Ani1308 said:thats not even in the option..oa--6, 4 ,3, 9, 2
I'm sure its 0.
6 can be the answer if question is asking for last non-zero digit of quotient and not for unit digit of quotient
white eraser = a
brown = 19 - a
Cost of brown one = x
Cost of white one = x + 20
a(x + 20) + (19 - a)x = 1000
20a + 19x = 1000
19x = 1000 - 20a = 20(50 - a)
x has to be a multiple of 20 (I am assuming price to be an integer)
x = 20,
a = 31 (not possible)
x = 40
a = 12 (possible)
x = 60 or more (not possible as a will be negative)
So, 60, 12
@ananyboss said:Question : --Rachit bought 19 erasers for rs 10. He paid 20 paise more for each white eraser than for each brown eraser. what could be the price of white eraser and how many erasers could he have bought ?a. 60, 8b. 60, 12c. 50, 8d. 50, 10Tell the approach please !
60, 12
@chillfactor elucidate how di u get the remainder as 40^100 ......also the quotient can be any number and when multiplied by the divisor will yield you a zero in units digit so when this is added to u r remainder will get u the divident......................
@ananyboss said:Question : --Rachit bought 19 erasers for rs 10. He paid 20 paise more for each white eraser than for each brown eraser. what could be the price of white eraser and how many erasers could he have bought ?a. 60, 8b. 60, 12c. 50, 8d. 50, 10Tell the approach please !
i did by equation..let white eraser be y and its price x
then brown quntity = 19-y and price x_ 20
now x —y +(19-y) —(x-20) = 1000
19x + 20y= 1380
b option satisfies
@Bigshu said:@chillfactor elucidate how di u get the remainder as 40^100 ......also the quotient can be any number and when multiplied by the divisor will yield you a zero in units digit so when this is added to u r remainder will get u the divident......................
Remainder theorem says that when f(x) is divided by (x - a) remainder will be f(a)
So, when 10^40000 or (10^400)^100 is divided (10^400 + 40) remainder will be (-40)^100 or 40^100
Now 10^40000 = (10^400 + 40)Q + 40^100
Q(10^400 + 40) = 10^40000 - 40^100
Number at RHS has 100 zeros at the end
=> Number at LHS should also have 100 zeros at the end but 10^400 + 40 has only 1
=> Q should have atleast 97 zeros at the end
This means unit digit of Q has to be 0
@Ani1308
I tried the same thing, I wanted to check whether we can solve this without options. Anyways thanks :)
@chillfactor lets take a siimple example 10^2/(10+4) according to RM the remainder should be 4^2 but the remainder is 2
@Bigshu said:@chillfactor lets take a siimple example 10^2/(10+4) according to RM the remainder should be 4^2 but the remainder is 2
10^400 + 40 = x
So, 10^400 = (x - 40)
So, (10^400)^100 = (x - 40)^100
So Exp: (x - 40)^100 / x
So only 1 term not divisible by x: C(100,0)*(-40)^100 = 40^100 [After expansion from binomial]
10^40000 = Q(10^400 + 40) + 40^100
So Unit digit will be 0.
Coming to your query:
Let (10 + 4) = x => 10 = (x - 4)
So (10)^2 = (x - 4)^2
Req Exp: (x - 4)^2/x --> remainder = 4^2/x = 16/14 = 2
@ananyboss said:Question : --Rachit bought 19 erasers for rs 10. He paid 20 paise more for each white eraser than for each brown eraser. what could be the price of white eraser and how many erasers could he have bought ?a. 60, 8b. 60, 12c. 50, 8d. 50, 10Tell the approach please !
solve from the options.... 60p, 8 = 4.8 for brown he paid 40p, and bought therefore 13.. but total should be 19.. so 1st option incorrect
2nd..... 60*12 = 7.2 now 2.8 left and 7 brown erasers can be bought, so total 19, data tally hence 2nd is the right option
@Bigshu said:@chillfactor lets take a siimple example 10^2/(10+4) according to RM the remainder should be 4^2 but the remainder is 2
4^2 = 16, which is greater than (10 + 4), so remainder is 2
In the question 40^100 is less than (10^400 + 40), thats why there is no need to solve it further
Q 13,14 nd 15
